Stresses in a Soil Mass

[@mphozmakalengz4373]

Hi Doc,
the formula for Total stress should be as follows:
Stress (D) = 3 * dry unit weight (sand) + 6 * saturated unit weight (clay)
= 3 × 17.33 + 6 × 18.59
= 163.53 kN/m2
if you use the submerged unit weight for calculating total stress then you will get an answer of 104,67 kN/m2
17,33(3)+(18,59 - 9,81)(6) = 104,67kN/m2

[@marktj284]

This video helped me out a lot . I'm looking forward to seeing induced stresses in soil under area loads

[@dr.mariaceciliamarcos]

Glad it was helpful!

[@ramonbaccomperi7871]

The submerged part got me confused. In class we were taught to just add without subtraction.

[@onyotganii5748]

So helpful 😊 thanks doc

[@basoeneeferebo820]

Thanks for the lecture. But please a question like the already solved one which involve capillary rise or action should be solved

[@quizzlerprofessor]

Writing as well as explanation is crystal clear

[@dr.mariaceciliamarcos]

Thank you :)

[@writersrapdebates2159]

Thanks alot, you are very helpful 🙏

[@ayusuryaningsih7680]

Thank you, Madam really help.

[@javanbenard3893]

why didnt you included 1.5 X 17.33 when calculating the total stress at D?

[@antoinetterobles8423]

because the depth for dry unit weight of sand at point D is 3m

[@rajeshae875]

Mam what we have to do in Case of partially saturated soils

[@mounirderfouf8494]

you have done a mistake in calculating the total stress in point d: total stress must be calculated by using the saturated unit weight (gamma sat) not by buoyant unit weight. The result is true, but the method is false

[@dr.mariaceciliamarcos]

thanks for noticing. its a sort of typo/write error.

[@mounirderfouf8494]

@@dr.mariaceciliamarcos yes

[@Jaffnamohan556]

great

[@jacklee3608]

wrong for point D