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a/sinA=b/sinB=c/sinCA=105a/sin105=b/sinB=c/sinCa=BC is given. So from the above rule we will get b and c Area of 🔺 =1/2abSinCOr 1/2bcsinAOr 1/2casinBThanks for ur video. Pl offer remarks
Very nice 👍🏻
@@JPSir Thanks a lot. Have a good day.
न्यूमैरिकल वैल्यू क्यों नहीं दी। एरिया 2.928।Correct derivation.
Sir J आप प्रतिशत निकालना सिखादो दो 🙏🙏😭😭
THE ANSWER ON THE NUMERATOR HAS TO BE MINUS THAN ADDITION
a/sinA=b/sinB=c/sinC
A=105
a/sin105=b/sinB=c/sinC
a=BC is given.
So from the above rule we will get b and c
Area of 🔺 =1/2abSinC
Or 1/2bcsinA
Or 1/2casinB
Thanks for ur video.
Pl offer remarks
Very nice 👍🏻
@@JPSir Thanks a lot. Have a good day.
न्यूमैरिकल वैल्यू क्यों नहीं दी। एरिया 2.928।
Correct derivation.
Sir J आप प्रतिशत निकालना सिखादो दो 🙏🙏😭😭
THE ANSWER ON THE NUMERATOR HAS TO BE MINUS THAN ADDITION