Shortcut method for solving Q36 via simultaneous equations: where c = count rate at 0 hours: x + c = 400 at 30 hours: 2 half lives so x/2^2 + c = 115 Solving simultaneous equation, x= 380. Put x value in equation: 380+c = 400. c= 20.
AHHHH your writing is so pleasing to the eyes!! Moreover, your explanations and tricks to remember things are marvellous. I have my Physics MCQ in 10 hours, so thank god I found your videos!! :)
In physics, propagation is the term used to describe how waves move or travel. It can also refer to the process of transmitting a disturbance, such as sound or electromagnetic waves, through a medium like air or water. Just wanted to let everyone know. :D
I have an easier method for Q36. So we know the half life is 15h and the table gives up to 30h, so we divide 30 by 15 to get 2. So the isotope is halved 2 times, that is equal to (1/4). Now ‘x’ will be the background count rate and we can make an equation out of this. ((400-x)/4)+x =115. This basically means if we remove background count rate from original isotope and halve it twice, then add back the background count rate we have the final number 115. This is a summary of what you did for each option. So we can simplify this. ( 400+3x )/4 = 115 Now let’s solve 400+3x = 115*4 3x = 460-400 x = 60/3 x = 20 Hope this isn’t too long and helps 😊
Your videos are really helpful and I really like your teaching style. Hope to create videos about the electromagnetic and electromagnetic effects practice questions only. That would be really helpful for me.plz
In the 0625 syllabus I think there’s a learning objective that the most of the energy of the sun belongs in the infrared and uv light and visible light art of the emw spectrum
hiiii i really like your videos.im appearing in this may june 24 session for phy can u plz guide me how to study for it also can u make a video on how to apply the hand rules THANKUUUUUUUU
I’ll try to make a video on this soon 🙏🏽 but for now I’ll suggest to print out your course specifications and use that as a checklist and guideline to see which topics you have covered. Get your foundation on the subject brushed up very quickly then move on to practicing lots of past papers
ummmm, read ur question again......... if v is unknown and current or I is 20, resistance is 3. V=60? so if resistance decrease to 2. then 2x20 = 40??? what do u not get.......
@@si0thy240 dude you have no time till the exam, and this is how where you at. bro watch the 2 hour video of mo ali on electricity and magnetism. pleaseeee, you need it. like not critisizing. tryna help. watch it on 2x speed if you can keep up with it. watching anime allows me to watch videos on 2x easily. try it
Focal length is the length from the middle of a lens, to the focal point. Length y measures exactly that, therefore, length y is equal to focal length. This means the largest value of y is the largest value of focal length.
Shortcut method for solving Q36 via simultaneous equations:
where c = count rate
at 0 hours: x + c = 400
at 30 hours: 2 half lives so x/2^2 + c = 115
Solving simultaneous equation, x= 380. Put x value in equation: 380+c = 400.
c= 20.
Thank you my little genius.
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@@learntodayIGCSE Yayy! Thank you :D
Physics paper went super well today... thanks to your videos 😁
That's actually really smart thanks
@@hishamawudu7532 hope your paper goes well!
AHHHH your writing is so pleasing to the eyes!! Moreover, your explanations and tricks to remember things are marvellous. I have my Physics MCQ in 10 hours, so thank god I found your videos!! :)
In physics, propagation is the term used to describe how waves move or travel. It can also refer to the process of transmitting a disturbance, such as sound or electromagnetic waves, through a medium like air or water. Just wanted to let everyone know. :D
I have an easier method for Q36.
So we know the half life is 15h and the table gives up to 30h, so we divide 30 by 15 to get 2. So the isotope is halved 2 times, that is equal to (1/4).
Now ‘x’ will be the background count rate and we can make an equation out of this.
((400-x)/4)+x =115. This basically means if we remove background count rate from original isotope and halve it twice, then add back the background count rate we have the final number 115. This is a summary of what you did for each option.
So we can simplify this.
( 400+3x )/4 = 115
Now let’s solve
400+3x = 115*4
3x = 460-400
x = 60/3
x = 20
Hope this isn’t too long and helps 😊
(400-x)/4 = 115-x
Fantastic 🎉 Made me understand the concepts well as the questions by not just giving answers like ms. 😊
Happy to hear that ! Good luck for your upcoming examss
why do we use left hand rule in question 32
PART 1 (Q1-16) IS HERE :
ua-cam.com/video/mseZBFUTIng/v-deo.htmlsi=HTO2WcEoimkwAePz
It was helpful for me ❤😊😊😊😊
Please create a video providing tips for Paper 2 in both physics and chemistry. Thank you
Your videos are really helpful and I really like your teaching style.
Hope to create videos about the electromagnetic and electromagnetic effects practice questions only. That would be really helpful for me.plz
Thanks this really helped.Keep it up
Hiii hope u r doing well i was wondering if u teach online plz i hv my igcse in may june 😢tbh i love your teaching❤❤❤❤❤
Sorry dear I don’t 😭😭 I don’t have the time as I teach at school and make videos on the side
Thank you ma’am 🥹
Most welcome ❤️❤️
Your such a lifesaver!
please can you send the past paper!
Thank you ❤️❤️
These papers are online just type the variant on the browser u will be able to download them ☺️
Can you explain why 39 is B? Is there a reason for it?
Thank you.
www.cambridgeinternational.org/Images/595430-2023-2025-syllabus.pdf
All theories are from here hope it helps
Really helped me!!! When can we expect the video with the solved Chemistry MCQ paper (0620/22) to be uploaded? Thank you!
The plan was to upload tonight but I got my wisdom tooth extracted yesterday and now I am still under recovery can’t speak a lot 😭😭😭😭
@@learntodayIGCSE Please take your time to recover...I hope you feel better soon!!!!!!!
thank you for understanding
IGCSE Chemistry Paper 42 - Feb/March 2024 - 0620/42/F/M/24 FULLY SOLVED
ua-cam.com/video/iHfJ1X5pqd4/v-deo.html
THANK YOU SMMM
Most welcome 🤗
at 10:09 isnt the resistance supposed to decrease ?
No, its a thermistor. Temperature is inversely proportional to resistance.
Thankkk youuuu you are literally the best teacher in the world
Btw I have my mock tmrrw wish me luck
Thank you for the support 😍😍😍
And best of luck !!! I hope it went well ❤️❤️
Hi, why can't Question 39 be A as frequency and eneegy are directly proportional?
The sun only transfers energy in the from of ultraviolet, visible and infrared rays, And so only b fits in
In the 0625 syllabus I think there’s a learning objective that the most of the energy of the sun belongs in the infrared and uv light and visible light art of the emw spectrum
Yes but still, why?
@@saniyaafzal-tk1ym it’s just something you have to rote learn
I guess, thankyou
This eas eo clear thank you
Youre most welcome 🤗
for questions 39, why is the answer not A? x-rays and gamma rays have the highest frequency meaning they are the most energetic
Can u pls give pdf link of FM 2024 paper 22
bro paper in a few hours homie. aint now way u havent studied
hiiii i really like your videos.im appearing in this may june 24 session for phy can u plz guide me how to study for it also can u make a video on how to apply the hand rules THANKUUUUUUUU
I’ll try to make a video on this soon 🙏🏽 but for now I’ll suggest to print out your course specifications and use that as a checklist and guideline to see which topics you have covered.
Get your foundation on the subject brushed up very quickly then move on to practicing lots of past papers
Your lenz law😩🩷🩷🤣
Toxic relationship 😤
For question 30 why does the decrease in resistance by the thermistor cause a decrease in potential difference? I thought V= IR
ummmm, read ur question again......... if v is unknown and current or I is 20, resistance is 3. V=60? so if resistance decrease to 2. then 2x20 = 40??? what do u not get.......
@@DayyanRaja8816 but it was never stated the current is kept the same
I is constant as it’s a series circuit
@@samarthg_28 brother, why were you awake at 3, you need sleep. exam in four hours, please sleep atleast 2 hours atleast. your body needs it
@@si0thy240 dude you have no time till the exam, and this is how where you at. bro watch the 2 hour video of mo ali on electricity and magnetism. pleaseeee, you need it. like not critisizing. tryna help. watch it on 2x speed if you can keep up with it. watching anime allows me to watch videos on 2x easily. try it
Hi can you upload a video for biology paper 2 mcq ?
It was my plan for this week, unfortunately I had an emergency wisdom tooth surgery and now I’m on recovery 😔😔 sorry
@@learntodayIGCSE Oh I am so sorry. Wish you a speedy recovery
Take care 😊
I need help with Paper 21 Q15 of Oct/Nov of physics. I have my exam today please help me asap! Thank you
Sorry I will not be able to them today 🥲🥲
Good luck hope u do your best 🙏🏽🙏🏽🙏🏽
@@Pixel_Pulse-y sorrry 😭😭😭 I didn’t know what u meant
It's ok ma'am. Anyways it went good
@@learntodayIGCSE
can you do feb/march 2023 paper 4?
Once I’m done with Oct/Nov 2023, I might be able to do that
Hi can you please do the 23 variant for October November 🥹
Sure. Give me some time:)
plss do bio paper 41 and 43 of ON fastttt plsssss
This won’t be anytime soon, but it will be before May/June 2024
I don't understand question 21 😭
Focal length is the length from the middle of a lens, to the focal point. Length y measures exactly that, therefore, length y is equal to focal length. This means the largest value of y is the largest value of focal length.