Hill Cipher (Decryption)

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  • Опубліковано 9 лют 2025
  • Network Security: Hill Cipher (Decryption)
    Topics discussed:
    1) Classical encryption techniques: Substitution and Transposition techniques.
    2) Introduction to the basics of Hill cipher.
    3) Mathematical concepts to be known in order to deal with Hill cipher encryption and decryption problems.
    4) The Hill Algorithm - Encryption and Decryption process of Hill cipher with expressions.
    5) Formula for finding the key inverse matrix and explanation of all the parameters involved.
    6) Example - Decryption using Hill cipher for the plaintext “RRLMWBKASPDH” with a 3x3 Key Inverse matrix.
    7) Finding the determinant of a 3x3 matrix using a short-cut approach.
    8) Finding the adjoint of a 3x3 matrix using a short-cut approach.
    9) Finding the multiplicative inverse of a number with modulus.
    10) Verifying the key inverse matrix.
    11) Information about square matrix and unit/identity matrix.
    12) Various ways of doing Hill cipher encryption and decryption using Row Vector approach and Column vector approach.
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    Music:
    Axol x Alex Skrindo - You [NCS Release]
    #NetworkSecurityByNeso #Cryptography #NetworkSecurity #HillCipher

КОМЕНТАРІ • 125

  • @bitethebyte
    @bitethebyte Рік тому +43

    Making this video requires more hard work and dedication then the whole playlists available for various subjects on UA-cam.
    Thanks a lot sir.

  • @ramazandurmaz3012
    @ramazandurmaz3012 3 роки тому +36

    That you even explained the linear algebra part in details step by step is admirable!

  • @maazosmany1291
    @maazosmany1291 3 роки тому +21

    You are a genius...even for a movement you dint let me confuse thanks a lot !!! Professor

  • @KassimHondaTech-qw4pm
    @KassimHondaTech-qw4pm 11 місяців тому +1

    Gosh! Despite my extensive web browsing, this video provided very clear explanations of everything!

  • @uff_rani
    @uff_rani 3 роки тому +9

    i am very thankful to you sir for explaining it so transparently ,hats off sir

  • @marzipane9182
    @marzipane9182 2 роки тому +10

    That was 3 days of cryptography. Thanks a lot Sir!

  • @nathaliechateauneuf3205
    @nathaliechateauneuf3205 3 роки тому +94

    At the end of the video, I believe L should be set to "11" rather than 14 in the decryption of RRL to PAY. I spent a bit of time questioning this, as I calculated with (17 17 14) as is written, which failed to produce P. It is written/solved correctly in the calculations, but the formula at this point has (17 17 14). Hope this helps anyone like me who felt like they couldn't do basic multiplication :)

    • @mobeen360
      @mobeen360 2 роки тому +4

      Thanks alot bro was trying to figure it out. Saved me time!!!

    • @zohaibnazakat3920
      @zohaibnazakat3920 2 роки тому +5

      Le me : after wasting my 30 mint to figure out how it will be 14 instead of 11 after wasting time my mind figure out let's check comment section now I'm here lol

    • @zohaibnazakat3920
      @zohaibnazakat3920 2 роки тому +3

      Btw thanks bro Appreciated 😊

    • @umairyounuus108
      @umairyounuus108 Рік тому +1

      659 mod 26

    • @ShiennaYongco
      @ShiennaYongco 10 місяців тому +1

      i felt stupid.

  • @arjungaming2706
    @arjungaming2706 2 роки тому +2

    22:00 I love the way the sir is teaching explaining each and every step 😘😘😍

  • @NikitaNair
    @NikitaNair 3 дні тому +1

    Amazing!!!

  • @alejandra4798
    @alejandra4798 3 роки тому +16

    OMG!! I'd been watching a lot of videos and websites but this video explained all very clear!!

  • @basketboyz107
    @basketboyz107 3 роки тому +5

    helped me with my maths investigation, thanks a lot.

  • @eex_jay
    @eex_jay 2 роки тому

    i have an exam today and this is so helpful, i'll come to say thanks on the reply after the exam...

  • @anupampan3007
    @anupampan3007 3 роки тому +2

    i am very happy u r uploading so many lectures

  • @enderslayer99og
    @enderslayer99og 2 місяці тому

    Amazing! Very helpful for Science Olympiad cryptography. Thanks you much!

  • @shivangssinha1915
    @shivangssinha1915 Місяць тому

    Excellent explanation 👍💯.

  • @iramshahzadi8297
    @iramshahzadi8297 Рік тому

    Really easy and understandable awesome way...

  • @yohannessintayehu1217
    @yohannessintayehu1217 2 роки тому +5

    Nice video overall with detailed explanation. One thing that confused me was the way you wrote the equations in the table at 20:09. on the right side of the equation, it is written 1 * 23 = 23 mod 26, 2 * 23 = 20 mod 26, etc... which can be interpreted as the value of the left side and right side are the same which is not the case in your explanation. Rather according to your explanation it would make more sense to write them as (1 * 23) mod 26 = 23, (2 * 23) mod 26 = 20 etc... and an overall formula of finding the value of inverse of any given number x where there is mod y could be z given x^-1 mod y = (z * x) mod y= 1.
    Edit: I feel like the way I wrote the formula could be misleading. I think it would be better if described as:
    - an overall formula for finding the inverse of any given number where there is a mod could be
    (z * x) mod y= 1, where
    x is the original number, y is the mod number and z is the inverse.

    • @kartikforwork
      @kartikforwork 8 місяців тому

      nope what he write is correct,

    • @yohannessintayehu1217
      @yohannessintayehu1217 8 місяців тому

      @@kartikforwork My reply also had an some issues which I corrected but how is what he wrote correct?

  • @dibabehrooz406
    @dibabehrooz406 10 місяців тому

    You really saved me, thanks sir🙏🏻🙏🏻

  • @crazy_world997
    @crazy_world997 Рік тому

    Thank for ur. Good.teaching 😊

  • @AkshayKumar-oh7mr
    @AkshayKumar-oh7mr 11 місяців тому

    Well done🎉

  • @rushabrathod335
    @rushabrathod335 3 роки тому +8

    @27:56 RRL = [17 17 11] but on the calculation took it as 11 so no problem

  • @PeterParker-xr5wt
    @PeterParker-xr5wt Рік тому

    nothing but the right way of using technology.

  • @nithinb2580
    @nithinb2580 Рік тому

    Thankyou very much sir ❤🎉

  • @toridii9983
    @toridii9983 Рік тому +1

    My question is for 26:28
    I understand the K x K inverse. But do you multiply these matrices as a whole or each numbers?
    Also, how did it end up being the result matrix before you use the mod 26?

  • @pmanasa4383
    @pmanasa4383 2 роки тому +3

    23 Inverse mod 26 can be found by gcd.
    Such a good explanation sir 👏thanks a lot

  • @fawazhussain1186
    @fawazhussain1186 Рік тому +1

    at 21:10 , WHAT WLL BE THE INPUT IF WE PERFORM EEA? I mean, for EEA, the format we do that in is, " a mod b ". So, what will be the values of the 'a' and 'b' respectively for this quetion we are solving in the video?

  • @fatmahaz8783
    @fatmahaz8783 3 роки тому

    thanks a lot , helped me so much❤❤

  • @Tuqa49
    @Tuqa49 9 місяців тому

    thx it really helps me

  • @farazsheikhhasan9673
    @farazsheikhhasan9673 3 роки тому +4

    One question, when I got the determinant of the matrix I got 1154 mod 26 which results in 10 mod 26. how do I get the multiplcaitve inverse since it always end in 0, what do I do?

  • @benallouaziz-n6h
    @benallouaziz-n6h 6 днів тому

    Thank you

  • @sandeepmacharla
    @sandeepmacharla 3 роки тому +2

    Thank you sir

  • @anupampan3007
    @anupampan3007 3 роки тому

    gr8 sir hope u will upload soon all videos

  • @sawpaingchitmin8848
    @sawpaingchitmin8848 11 місяців тому

    Thank a lot sir!

  • @PrasadAI
    @PrasadAI Рік тому

    Thank you❤

  • @JusticeWillBeServedBro
    @JusticeWillBeServedBro Рік тому +3

    12:20 what if its 2X2 matrix or some other

  • @arnab_sheikh
    @arnab_sheikh 2 роки тому +3

    what will i do if the multiplicative inverse is not available in modulo 26 ? what is the multiplicative inverse of 4 in modulo 26?

  • @sammymendis475
    @sammymendis475 2 роки тому

    Thank you!

  • @e.l.d5795
    @e.l.d5795 5 місяців тому +1

    Sir is it necessary to take mod 26 in the determinant of K and its adjoint .

  • @agbaiobasi7390
    @agbaiobasi7390 Рік тому

    Thanks genius.

  • @Shayar_Shaigan
    @Shayar_Shaigan Рік тому

    I'm stuck in my calculation, can you help me out, My determinant is 8 and its multiplicative inverse does not exist under mod 26, What should I do?

  • @PMe-my1td
    @PMe-my1td 2 роки тому +1

    Thanks! Can you do a video on finding the key with a Plain-text and Cipher only for a 3x3 matrix?

  • @poojapoojadhapte1430
    @poojapoojadhapte1430 8 місяців тому

    😊😊😊😊 very happy

  • @ayansiddiqui7383
    @ayansiddiqui7383 2 роки тому +2

    Is there any shortcut to find multiplicative inverse of a number

  • @shaludeena6360
    @shaludeena6360 2 роки тому +2

    Thalaiva , you are great 👌

  • @codingroast7500
    @codingroast7500 Рік тому

    awesome

  • @meriem1708
    @meriem1708 Рік тому

    there is a little mistake in 27:54 RRL --> (17 17 11 ) not (17 17 14 ) and thank you very much sir

  • @DAYYAN294
    @DAYYAN294 3 роки тому +2

    Sir kindly upload rest of the videos as soon as possible

  • @biswajyotishmanachutia499
    @biswajyotishmanachutia499 Рік тому +3

    In some sources and videos encryption formula for hill cipher is given as C=k*Pmod26 and some sources C=P*kmod26, since its a matrix multiplication both the answers are different.. so what should we follow🥺?

  • @purushothamans5527
    @purushothamans5527 Рік тому

    hi bro nice teaching ,but i have one doubt that is in inverse is odd(20:29) instead of even ,what we can do bro? how to find that value??

  • @s.gangmei5837
    @s.gangmei5837 2 місяці тому +1

    While finding the inverse matrix why do we have to do mod 26 ... Even while finding the adjoint matrix.. why can't we simply write the matrix value ...place them in the formula and finally perform mod 26

  • @radhacreations2503
    @radhacreations2503 2 роки тому +4

    I have a doubt why we need to take mod 26 always after adjoint and u also took mod 26 after determinant and also again after inverse plz clarify my doubt

    • @lohitlgd8335
      @lohitlgd8335 Рік тому

      I think its because we have 26 letters in English alphabet
      Once we complete 26 alphabets, we go back to the beginning.
      Thats the reason for that i guess.

    • @abhilashmadhav.m536
      @abhilashmadhav.m536 Рік тому

      did you understand it? pls explain if you did?

    • @nageshgour3148
      @nageshgour3148 Рік тому

      Be cause of total number of alphabet is 26

  • @yogeshFlix23
    @yogeshFlix23 2 роки тому

    thanks

  • @SaidHaaji12
    @SaidHaaji12 Рік тому

    16:40
    There is a big deffrence acording what you explan

  • @nasratt
    @nasratt 2 роки тому

    why we need to take the modulo while finding determinant and adjoint, we are taking modulo at the end?

  • @SohamMahapatra-x3j
    @SohamMahapatra-x3j 3 місяці тому +1

    why can we find the value of k-1 directly with calculator??

  • @chiragmadaan3255
    @chiragmadaan3255 3 роки тому +4

    does that mean we cant find multiplicative inverse mod 26 of even numbers? because whatever is multiplied with even number can't result in odd number and hence 1 as the remainder.

    • @utilizator1701
      @utilizator1701 3 роки тому

      I do not know the particilarities of mod26, but in mod 6 you have the matrix [ 2, 3; 3 2 ]. Even though no element is inversable in mod 6, the matrix itself is inversable.
      Maybe same matrices can be found in mod 26.

  • @yogeshbmyogeshbm5154
    @yogeshbmyogeshbm5154 2 роки тому +1

    While it is 3×3 matrix you just copied 2more columns & 2more rows, but what if its 2×2 matrix then how to do sir

  • @shreyachauhan2685
    @shreyachauhan2685 Рік тому

    great

  • @rumisakhankhan1091
    @rumisakhankhan1091 Рік тому

    Sir in ist row instead of 17 there is 7 at 2nd place in ist row plz correct this becoz key is same for encryption and decryption

  • @nasratt
    @nasratt 2 роки тому +1

    OMG, maths 🤯. got me confused, what is all this modulo modulo going on

  • @sameermeshram3062
    @sameermeshram3062 3 роки тому +1

    Sir upload the video of control system ✅

    • @nesoacademy
      @nesoacademy  3 роки тому

      Sure. The next lecture is coming soon.

    • @d3monlord_019
      @d3monlord_019 3 роки тому

      @@nesoacademy your videos are very helpful but can you please tell name of application you use for java ?

  • @vendeltout8562
    @vendeltout8562 9 місяців тому

    what if i cant calculate the multiplicative inverse? i got K^-1= 24^(-1) * matrix * mod 26

  • @uff_rani
    @uff_rani 3 роки тому

    sir why you put mod 26 after calulating mod,it should go off ryt?? ,that make me confuse,

    • @tamillenin2276
      @tamillenin2276 3 роки тому

      It is taking everytime so that the result cannot exceed 25.

    • @utilizator1701
      @utilizator1701 3 роки тому

      There are 26 letters in english language.

  • @blaze9558
    @blaze9558 Рік тому

    it'd take 10 mins in the exam just to find the inverse

  • @anupampan3007
    @anupampan3007 3 роки тому +1

    plz upload whole syllabus

  • @arjunk2223
    @arjunk2223 Рік тому +1

    Why including mod function while doing diterminant

  • @ShiennaYongco
    @ShiennaYongco 10 місяців тому

    Hello, please help explain to me how the 23 became 17 more simply. 🙇‍♂🙇‍♂ Thank you!

  • @nehaburhade3991
    @nehaburhade3991 3 роки тому +1

    First view first Comment

  • @mlblazrvlog8131
    @mlblazrvlog8131 10 місяців тому

    how to get a reminder sir?

  • @rishiaryal9566
    @rishiaryal9566 Рік тому

    why do you mod everytime. can't we find 1/det(k) and adj(k) [without mod by 26]. Multiply 1/det(K) and adj(k) then mod by 26.

    • @abhilashmadhav.m536
      @abhilashmadhav.m536 Рік тому

      we applied mod 26 on det k and now we have also applied mod 26 on adj k. since applying mod 26 on both detk and adj k, how will mod 26 still remain to be used in the k inverse equation ? Please tell if you have understood coz i dont understand it.

  • @muhammadusamariaz2492
    @muhammadusamariaz2492 2 роки тому

    YALLAH Y AJ PAPER MA NA AYE.AMEEN

  • @sreelekhajyothitatavarthy355
    @sreelekhajyothitatavarthy355 3 роки тому

    sir if the key value matrix is not given in the question ,how to find the key matrix sir.reply soon.

  • @arkatanukundu_171
    @arkatanukundu_171 Рік тому

    Isnt the formula C= K*P mod 26 not P*K mod 26??

  • @gireeshkumarkancharla4176
    @gireeshkumarkancharla4176 3 роки тому +2

    @ Neso academy we are getting different cipher text when we use KP approach ..

  • @musicmonkey8367
    @musicmonkey8367 2 роки тому

    Easy to learn but difficult to do

  • @cronojob8502
    @cronojob8502 3 роки тому

    Op🔥

  • @programmertik2046
    @programmertik2046 3 роки тому

    What if the total letters is not a multiple off matrix size .??
    i.e if text was neso academy and matrix size was 3x3 then how to breaj the letters??

    • @tamillenin2276
      @tamillenin2276 3 роки тому +2

      Insert a filler character X
      nes oac ade myx

    • @utilizator1701
      @utilizator1701 3 роки тому

      @@tamillenin2276 Something like padding?

  • @37rajalakshmir44
    @37rajalakshmir44 3 роки тому +1

    Sir may I know the 13 inverse of mod 26???? If no multicative ..then how will solve this problem sir ??? Please tell because my internal qstn the qstn mtrx 19 is differ in 9 ..so using this method u guide 13 I get detk ...so what can I do sir ????

  • @sachinsudaraka6397
    @sachinsudaraka6397 3 роки тому +1

    ❤️

  • @madhavdhobale9576
    @madhavdhobale9576 2 роки тому

    There is the small mistake in place of 14 there must be 11 I hope everyone can see that.

  • @mihirkate3553
    @mihirkate3553 11 місяців тому

    adjoint of k could be calculated in calculator.
    if any one knows the steps pls paste the link.

  • @hasibulislam1143
    @hasibulislam1143 2 роки тому

    L=11 at 28.02 mistaken

  • @madhavdhobale9576
    @madhavdhobale9576 2 роки тому

    By mistakely it written as 14 instead of 11

  • @ibrahimgadli2583
    @ibrahimgadli2583 Рік тому

    The ending part was not explaind properly

  • @hetdoshi9385
    @hetdoshi9385 Рік тому

    VALUE OF L = 11 DURING THE DECRYPTION OF RRL NOT 14 🤣 and funny part is my faculty also do the same mistake but her total somehow match's the correct total 🤣🤣

  • @niteshgupta9697
    @niteshgupta9697 3 роки тому

    I am once again asking for the code, please

  • @phunsukhwangdu8273
    @phunsukhwangdu8273 5 місяців тому

    sharath sir .........

  • @STUDYTALK1102
    @STUDYTALK1102 2 роки тому +1

    Sir -936 mod 26 =0

    • @GooSoft
      @GooSoft Рік тому

      Bro is that wrong I am also getting the same reminder .what did you do ?

  • @sagargupta7609
    @sagargupta7609 2 роки тому

    bhai ye tera adjint kaise nikala hai vo bilkul bhi samajh mai nahi aaya.
    Make new video to understand the concept

  • @lucidaxis1233
    @lucidaxis1233 Рік тому

    How did you get multiplcative inverse of 23 as 17? Shouldn't it be 1/23? I am very confused. Someone pls help.

  • @pablo_Esciccha
    @pablo_Esciccha 26 днів тому

    Better leave this qn

  • @ToanPham-wr7xe
    @ToanPham-wr7xe 7 місяців тому

    😮

  • @mahipanchal9661
    @mahipanchal9661 Рік тому

    End of brain

  • @PeterParker-xr5wt
    @PeterParker-xr5wt Рік тому

    gottcha.

  • @jahnu.1366
    @jahnu.1366 2 роки тому

    billa

  • @GooSoft
    @GooSoft Рік тому +4

    9:48 -936 mod 26 = 0 @nesoacademy

    • @jeevi4123
      @jeevi4123 Рік тому +1

      But we get -939 mod 26 okay it's mod value is-3 and it is in negative so we add 26 then 26-3=23😅

    • @hehehehme6293
      @hehehehme6293 5 місяців тому

      Appreciate you bro 🤣

  • @abdiworku9835
    @abdiworku9835 Місяць тому

    thanks