It is algebraic structure, semigroup and monoid but If we take 5*(1/5)=1 then though we obtain the identity element but as (1/5) is not a natural number and hence it doesn't belong to the set of natural numbers and so it is not a group.
For [N, . ], First checking if its AG, Closure: Yes, the product of two natural numbers is always a natural number. then checking if its a semi group or not with associativity: Yes, multiplication is associative. Now checking if its a monoid with Identity element: Yes, the identity element is 1, because for any natural number n, n * e = n, so 1. Now checking if its a group or not with inverse element: No because not every natural number has a multiplicative inverse within the set of natural numbers. Because lets take a = 4 then, a * b = 1, 4 * b = 1 then b = 1/a which is not possible in N so [N, . ] is not a group.
Sir there is a one request, please upload the vedio on the topic Floyd's algorithm for all pairs shortest path problem .... I have seen this topic from various other channels but I'm not able to understand this topic from there. please sir i want and need ur explanation in this topic.... I know you will surely make this vedio sooner.... Thank you sir.....😇
In case of natural numbers it is not a group as if we multiply 5 by 1/5 to get identity element as 1 we have 5 which belongs to N but 1/5 dosen't belongs to N so it is not a group
that is right but (N, *) will not be a group as in case of natural no, with operation multiplication,it is not a group 8 *(1/8)=1 but here 1/8 is not natural no. so it is not a group.
sir in case of natural no, with operation multiplication,it is not a group
8 *(1/8)=1
but here 1/8 is not natural no.
so it is not a group
(N,*)is not a group
Becoz
5*1/5=1
But 1/5 does not belong to N
Yes exactly
@Hari Priya Chowdary that condition must satisfy all the numbers bro
Your teaching experience is totally different from others LOVE FROM KASHMIR
(N, ×) is closure, semi-group, also monoid, but it is not a group, because 1/N is not a natural number, inverse doesn't exist.
As usual very easy to comprehend. Bravo 👍
A tip: you can watch series at flixzone. Me and my gf have been using them for watching lots of of movies these days.
@Rudy Kevin definitely, I've been using flixzone for years myself :)
Yeah !!! That's the content which I am looking for ! Thank you so sooo much sir ..
Sir, please please upload the rest of the videos. Your videos are conceptual and easy to understand. 🥺
It is algebraic structure, semigroup and monoid but If we take 5*(1/5)=1 then though we obtain the identity element but as (1/5) is not a natural number and hence it doesn't belong to the set of natural numbers and so it is not a group.
Sir your explanation is very clear....Huge Thanks to You Sir. !!!!!!
a*(1/a)=1 but 1/a doesn't belong to natural number
A mean any number
Inverse does not have to belong to the set.
@@bhavyarai4218 yes it does
It's written
(a*b) = (b*a) = e
Such that b belongs to S
@@bhavyarai4218
No inverse also belongs to set
(N,.) NOT FOLLOW THE PROPERTY OF GROUP
Simple and easily understandable..
conceptual, concrete, concise. thank you, sir
no concrete or cement just good teaching sir.
@@ROSUJACOB vah vah vah vah.......100 times.
@@mabbrarsaif7534 ty babbarji.
8:11 sir (N, *) is not a group as inverse of natural is always a rational number..
Yes
7 crore 😅
Ur explanation is very clear & easy to understand ....thanks 👍😊
For [N, . ],
First checking if its AG, Closure: Yes, the product of two natural numbers is always a natural number.
then checking if its a semi group or not with associativity: Yes, multiplication is associative.
Now checking if its a monoid with Identity element: Yes, the identity element is 1, because for any natural number n, n * e = n, so 1.
Now checking if its a group or not with inverse element:
No because not every natural number has a multiplicative inverse within the set of natural numbers. Because
lets take a = 4 then, a * b = 1, 4 * b = 1 then b = 1/a which is not possible in N so
[N, . ] is not a group.
Very Informative Session!!❤
Waiting for this
LOVE YOU SIR ❤
Sir (N,•) is not a group because of most of number ke inverse element N me nhi hai 🙏🏻
😂😂😂😂😂
Ohh shet..
Welcome back Sir✌
Wowwwwwww, U really made it easy.
Big Salute to u🥰🥰🥰🥰🥰
Sir in (R,*) case in group we can multiply with 1 instead of 1/n
Nice session sir👍👍,,Discrete k sbi topic complete krwa do sir please for NET exam...
(N , .)is an algebric structure ,
it is a semigroup,
it is monoid,
but it is not a group
sir (N, . ) IS not a grp becoz if 5 is taken then in indentity 1 we have to take 1/5 which is not an natural no.
Best teacher
Actually identity element in a set of natural number could be one.We may take the inverse element likewise.
Sir there is a one request, please upload the vedio on the topic Floyd's algorithm for all pairs shortest path problem .... I have seen this topic from various other channels but I'm not able to understand this topic from there. please sir i want and need ur explanation in this topic.... I know you will surely make this vedio sooner.... Thank you sir.....😇
Varun sir, how many is needed to complete a discrete mathematics.from your videos??
Yes sir (N,•)is also inverse because any natural no multiplying with 1 so give identity
No
If we take rather than it doesn't obey inverse , because b doesn't comes in set
Sir please upload fast as you can🙏
right
Waiting for more videos. Thank you
Great sir ❤
N does not contain zero where as Whole numbers do, but its not a group if (N, *) cause (1/N) is not part of N
Great ❤️ sir 😌👌💯💯💯
natural number in case of multiplication is not a group because for a = 5, we get b = 1/5, and this value of b does not belongs to N.
Bhaiya please poora discrete complete kr dijiye!!!
M.IMP thing varun bhai says ..."subscribers bahut zaroori h" 😅
Thanks sir 😊
In case of natural numbers it is not a group as if we multiply 5 by 1/5 to get identity element as 1 we have 5 which belongs to N but 1/5 dosen't belongs to N so it is not a group
great explanation!!
Sir please make next topic videos like cosets lagrange theorem and all
(N,*) case 2*1/2=1,since 1/2 is not part of natural number its not a group
Sir(N,.) is not grp because inverse of 5 is 1/5 which is not a natural number.
Great sir
And thank you sir ☺️😘
Sir .. please...aktu syllabus base per...theory of automata and formal language...ke lecture bhi bnaye...🙏🙏
why these kind of teacher is not in universities??
because they are on UA-cam
(N,*) is not a group, instead, it's a monoid, because 5*(1/5) = 1, but 1/5 does not lie in or belong to N.
Hi , sir varun ... sir mai ap k teachers k bary me janana chahti hn , jo ap ka sourse hoty hain youtube py parhaty hoay ,
Vesry essay teaching sir ji 🙏
please make playlist of this
Thank you so much
Natural number doesn't contain the inverse element with respect to mult.Hence,not a group.
Thankyou sir
5 is a natural number.
5*1/5=1
But 1/5 is does not belongs to natural number. So (N,.)is not a group.
Good afternoon sir ,pls upload motivational videos
Sir dsssb ka kuch vedio bnate
Multiplication on R is a moniod?
Thank sir.
sir please upload the lagrange's theorem from discrete math ...
i've seen lots of vid you are my last hope
(N,*) is not to group
N*1/N=1
but not passible to 1/N in N
(N, .) Is not a group because natural no. Doesn't consider fraction no.
Thankyou
(N,*) is not a group as 2+(-2)=0 but -2 is not natural number
Sir R is not a group because it doesn't follow semi group,monoid so sir it means real number are not a group.
Sir natural number is not a group.
(N,.) Is not a group because after multiply by 1/a the output is 1 but 1/a doesn't belong to N that's why (N,.)is not a group
Great
aapke wazah se 4th sem paas huye
(N,×) is not a group because the inverse is not belongs to natural no.
Subscribers bahot jaruri hai😂......
Last question answer is no it is not a group
1*1/5 hoga but that's not belogs 1/5 N me nehi he bhi or to or...... 0 bhi he na then N* bhi nehi hoga
Thank u sir
8:11 not a group
Natural no (5*1 =5) does not group ✓
keeep goin
sir aap board ko pura cover kr ke khade hote hain thoda side hokr video banayega please content chup jaata hai thankyou!
(N, .) Is not a group
very good
(N,•) is not a group
It is not a group because inverse of any natural number except 1 is not a natural number.
watching your videos in 2.75x (with extension) everytime 😂😂😂
Subscribers bht zaruri hain😂😂
(N ,*)=1*1=1
It's right or wrong
plzz ...
reply sir ❤
that is right but (N, *) will not be a group as in case of natural no, with operation multiplication,it is not a group
8 *(1/8)=1
but here 1/8 is not natural no.
so it is not a group.
(N.) Not a group bcz set B doesn't belong to the set N
ooo bhai yehi bacha tha. discrete maths. Students can officially stop going to colleges now
sir🙏🙏🙏🙏🙏
(N, .) is not group
1*1=1
This way this is group?
(N,.) this is not a group
Subscribers bahut jaruri hai
(N ,.) Is not a group sir
but 0 into infinity is 0 only
5+(-5) =0
Next time please try to record a video in English.. not everyone on UA-cam is from India
No it's not a group..
3rd part : Not a group
Kisco lag raha ha ka in ka face tech burner ka slok sa milta ha
No group
🙏
you just speak like amir khan