I did 1000 iterations on desmos by using multiple g's where I would have g(z) as 10 f(z)'s and then use i(z) as 10 g(z)'s (I skip h because I use h as hsv colours) and then j(z) is 10 i(z)'s which I use multiple iterations to see where other stuff is that I don't see because of too many iterations that I won't see the colour which shows there is something
the formula for the mandelbrot set is z^2 + c, where z is any complex number (x + yi), and i is the square root of -1 so 0 + yi^2 would be -y + 0i. leaving the complex number to be (x^2 + yi^2, 2*x^2*y^2) which is, if we simplify, z = (z.x^2 - z.y^2, 2z.x^2z.y^2) + (x, y). the last part takes the distance of the finishing point from (0, 0), and compares it to 2. if it is less, then it will be coloured black as part of the set. and if not, it will be uncoloured or more popularly, coloured based on how many iterations it takes for its distance to be greater than 2.
the formula for the mandelbrot set is z^2 + c, where z is any complex number (x + yi), and i is the square root of -1 so 0 + yi^2 would be -y + 0i. leaving the complex number to be (x^2 + yi^2, 2*x^2*y^2) which is, if we simplify, z = (z.x^2 - z.y^2, 2z.x^2z.y^2) + (x, y). the last part takes the distance of the finishing point from (0, 0), and compares it to 2. if it is less, then it will be coloured black as part of the set. and if not, it will be uncoloured or more popularly, coloured based on how many iterations it takes for its distance to be greater than 2.
www.desmos.com/calculator/vibes965qr
BRO WAIT THE LINK LMAOAOA VIBES
I got errors :/
@@ЕвгенийШамшитовthen get a better pc or phone
@@ЕвгенийШамшитовdoesn't work on all devices sadly
If you replace the two with -2, it becomes the tricorn variation. It’s super fun to mess around with with the values
Now, play it.
you cant
Obviously not possible
how did you do f(f(f(f... and g(g(g(g... without getting definitions nested too deeply?
Explain?
I did 1000 iterations on desmos by using multiple g's where I would have g(z) as 10 f(z)'s and then use i(z) as 10 g(z)'s (I skip h because I use h as hsv colours) and then j(z) is 10 i(z)'s which I use multiple iterations to see where other stuff is that I don't see because of too many iterations that I won't see the colour which shows there is something
The mandrelbrot set is the fractal that's shown in this video Do burning ship next!
Do make 10,000 iterations?
The graph you posted in the comments isn't the same one as in the video. Still works, but it's much less handy to work with.
Good job!
That's cool! How do these equations make this work?
the formula for the mandelbrot set is z^2 + c, where z is any complex number (x + yi), and i is the square root of -1 so 0 + yi^2 would be -y + 0i. leaving the complex number to be (x^2 + yi^2, 2*x^2*y^2) which is, if we simplify, z = (z.x^2 - z.y^2, 2z.x^2z.y^2) + (x, y).
the last part takes the distance of the finishing point from (0, 0), and compares it to 2. if it is less, then it will be coloured black as part of the set. and if not, it will be uncoloured or more popularly, coloured based on how many iterations it takes for its distance to be greater than 2.
o_õ
Wooow, so cool!
In Mandelbrowser
link pls
What equations u used?
Look at the video.
Giant space Zoom
Or z^2 + c
that won't work?
What is the g(z)=(f.....
Full formula?
g(z) = f(f(f...f(f((0,0))))...)))
I wish I understood the equation.
the formula for the mandelbrot set is z^2 + c, where z is any complex number (x + yi), and i is the square root of -1 so 0 + yi^2 would be -y + 0i. leaving the complex number to be (x^2 + yi^2, 2*x^2*y^2) which is, if we simplify, z = (z.x^2 - z.y^2, 2z.x^2z.y^2) + (x, y).
the last part takes the distance of the finishing point from (0, 0), and compares it to 2. if it is less, then it will be coloured black as part of the set. and if not, it will be uncoloured or more popularly, coloured based on how many iterations it takes for its distance to be greater than 2.
@@H_fromDiscord_real Thank you.
@@arvaneret_329 np :)
how?
GIVE LINK
so it’s D(g(g(g(g(g(g(g( and now what?
He defined g(z) and D(z) and then used these functions
At the Center is (0, 0), the starting point which, of course, you can change