Dilution Chemistry: How to Calculate and Perform Molarity Dilutions

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  • Опубліковано 11 лип 2024
  • AP Chemistry Lesson 1.5
    molarity
    volume
    moles
    dilution
    stock solution
    series of dilutions
    dilution sample problems

КОМЕНТАРІ • 17

  • @misfortune2633
    @misfortune2633 3 роки тому +4

    Thank you for the help! I started Chem in college and my teacher basically told us to figure this out for ourselves, you are a life saver! :)

  • @alderamin1402
    @alderamin1402 2 роки тому +5

    I could not understand the last question :((((

  • @meerabye4586
    @meerabye4586 3 роки тому +1

    So nice....❤ from india .

  • @mirembeshamira7789
    @mirembeshamira7789 2 роки тому +1

    Nice teaching

  • @johnkofibiney7589
    @johnkofibiney7589 3 роки тому +1

    Thanks sir

  • @mohemmmad5982
    @mohemmmad5982 3 роки тому +1

    Thank you so much

  • @Shailesh_Pandey_V.
    @Shailesh_Pandey_V. 3 роки тому

    Love from India

  • @babenkoprop571
    @babenkoprop571 Рік тому

    How could I make the concentration of a solution of HCl of which 25mL would be needed to neutralize 12.5mL of 4.0M NaOH?

  • @BoltzSquad
    @BoltzSquad 3 роки тому

    Thanks for this. Why you not doing a exam of this lesson in your website.

    • @ketzbook
      @ketzbook  3 роки тому +1

      I haven't updated my website in a while. I need to redesign it.

  • @inner-lifevlognutritondiet4499
    @inner-lifevlognutritondiet4499 3 роки тому +1

    This is so help full, but how about if I want to create a 2% solution? How do I calculate for persantage?

    • @ketzbook
      @ketzbook  3 роки тому

      check out: ua-cam.com/video/pXN6rJlNXSg/v-deo.html

  • @DelmahKarisiwa-yr1by
    @DelmahKarisiwa-yr1by Рік тому

    If how much of copper 3 SULPHATE SOLUTION

  • @ishiniwathsala7772
    @ishiniwathsala7772 Рік тому

    Thank you sir

  • @babenkoprop571
    @babenkoprop571 Рік тому

    How could I make the concentration of a solution of HCl of which 25mL would be needed to neutralize 12.5mL of 4.0M NaOH?