This comment is cheating a bit, because I first watched the video until the end. Rewrite expression (1) as 3x = (√13 - 1)/2 and call this expression (1B). Raising to the 6th power the left-hand side of (1B) leaves 729x^6. Raising the right-hand side of (1B) to the powers 2, 3 and 6 looks like this: (13+1-2√13)/4=(7-√13)/2 (-7-13+√13(7+1))/4=-5+2√13 (25+4*13-5*4√13)=77-20√13
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Great question sir g ❤
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This comment is cheating a bit, because I first watched the video until the end.
Rewrite expression (1) as 3x = (√13 - 1)/2 and call this expression (1B).
Raising to the 6th power the left-hand side of (1B) leaves 729x^6.
Raising the right-hand side of (1B) to the powers 2, 3 and 6 looks like this:
(13+1-2√13)/4=(7-√13)/2
(-7-13+√13(7+1))/4=-5+2√13
(25+4*13-5*4√13)=77-20√13
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