XRD - Bragg's Law | Peak Position, Intensity, & Width

Поділитися
Вставка
  • Опубліковано 27 лис 2024

КОМЕНТАРІ • 260

  • @andawang9403
    @andawang9403 3 роки тому +39

    after hours of search I found this video...and it just contains all the things I want to know, great work sir !

  • @akshigupta8411
    @akshigupta8411 4 роки тому +7

    I was really thinking from so many days to watch any video describing about XRD technique... But then I was procrastinating due to such long duration videos....
    Thanks a lot sir and u described it very well and in very easily understandable manner as usual...

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +2

      Thanks Akshi. Now i am going to make some research related videos. Please share with your friends.

    • @akshigupta8411
      @akshigupta8411 4 роки тому +2

      @@AllLabExperiments I already did...

  • @nourihsane8886
    @nourihsane8886 3 роки тому +10

    Best XRD explication. Thank you sir. Your are an Angel. ❤️👍👍👍👍👍👍. Indians are genius

  • @triptofameaciddlab2909
    @triptofameaciddlab2909 3 роки тому +18

    Consequent, clear, straight to the deal. You’ve made a great work!

  • @arup812
    @arup812 2 місяці тому +1

    best class on XRD i have ever seen

    • @AllLabExperiments
      @AllLabExperiments  2 місяці тому +1

      @@arup812 thanks. One more Vidro on Raman Characterization and Analysis is also there. You can watch that too...

  • @Freddy_Merckx
    @Freddy_Merckx 3 роки тому +8

    Really, really good video for XRD beginners.
    Very much appreciated!

  • @dana5731
    @dana5731 Рік тому +3

    Really a good video at least I've found on UA-cam for understanding XRD method.

    • @AllLabExperiments
      @AllLabExperiments  Рік тому +3

      Planning to launch more videos on characterization techniques.

  • @semiconguy4467
    @semiconguy4467 3 роки тому +7

    Best video I have ever seen on XRD! Thanks a lot.

    • @AllLabExperiments
      @AllLabExperiments  6 місяців тому +1

      Please Checkout my latest video on Raman Effect and Spectroscopy.

  • @pankajinimahanta9830
    @pankajinimahanta9830 4 місяці тому +1

    Thank you very much for this excellent video 🙏🙏

    • @AllLabExperiments
      @AllLabExperiments  4 місяці тому +2

      @@pankajinimahanta9830 thanks for your words. Please check out my latest videos on raman characterization and research paper writing. Those will also help you in the field of research.

  • @yash-sb9ec
    @yash-sb9ec 7 місяців тому +2

    Wow really nicely explained sir

  • @muhammadzubair5391
    @muhammadzubair5391 4 роки тому +3

    Woderful 1st time fuly understood the XRD

  • @muskanarora3433
    @muskanarora3433 3 роки тому +7

    Excellent!!
    Very Well Explained...
    Systematic teaching and covering all the important points about the topic...
    Thank you for this video and efforts👍

  • @sudhishtsrivastava4336
    @sudhishtsrivastava4336 4 роки тому +4

    An excellent explanation. Even biology people can understand this complain technique

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +4

      When DNA was discovered. Biologists struggled a lot about XRD.... unfortunately At that time my video was not present... Not even youtube...lolz

    • @akshigupta8411
      @akshigupta8411 4 роки тому +2

      @@AllLabExperiments 😂👌

  • @sanamir6343
    @sanamir6343 4 роки тому +5

    Thanku so much sir.... Respect from Pakistan

  • @claireb579
    @claireb579 2 роки тому +5

    Great video! You nicely connected so many concepts together, specifically about strain (compressive and tensile) and what the literal peaks would do in response to that in the data! I now understand XRD better. Thank you from the US :)

    • @AllLabExperiments
      @AllLabExperiments  6 місяців тому +1

      Hi... Please watch my latest Raman Video for extended details on Raman Effect & Spectroscopy.

  • @GeorgeAugostino
    @GeorgeAugostino 3 дні тому +1

    I like it

  • @spscheckit
    @spscheckit 11 місяців тому +1

    Amazing Video ... Loved your explanation.
    '

  • @lemeii254
    @lemeii254 Рік тому +1

    Great 👍,, educative

  • @mkamalakkannan8327
    @mkamalakkannan8327 Рік тому +1

    Very good explanation, GOD bless you.

  • @nisarga100
    @nisarga100 Рік тому +1

    Really impressive, great job🎉

  • @MuhammadShoaib-ml1tc
    @MuhammadShoaib-ml1tc 3 роки тому +1

    A very comprehensive video, easy to understand, thanks

  • @shahidnaveed5408
    @shahidnaveed5408 3 роки тому +2

    Very Nice Sir, ❤

  • @priyankamaurya7480
    @priyankamaurya7480 3 роки тому +1

    Very helpful video....thank you so much sir

  • @shaheenerabbani7687
    @shaheenerabbani7687 2 роки тому +1

    Excellent explanation.........V.Good

  • @hope2633cu
    @hope2633cu 11 місяців тому +1

    pefecttttttttttt xrd concept
    Thanks

  • @prudhviravikumar2304
    @prudhviravikumar2304 2 роки тому +1

    Thank you for informative video

  • @vivalaciencia1
    @vivalaciencia1 Рік тому +1

    Great video! Very well explained!

  • @pradroydip
    @pradroydip 6 місяців тому +1

    Peak can be broadened due to many factors, but most significantly non-uniform stress, small particle size, alloying, low incidence angle (in case of GIXRD), etc.

    • @AllLabExperiments
      @AllLabExperiments  6 місяців тому +1

      Absolutely... Also Watch my latest video on Raman Spectroscopy.

  • @aftabbaig5367
    @aftabbaig5367 4 роки тому +4

    Simple and crystal clear

  • @shenawaralikhan
    @shenawaralikhan 2 роки тому +1

    Good Work, gentleman

  • @Educationhouse0002
    @Educationhouse0002 Місяць тому +1

    Best video on xrd.. Please make a video on CVD and PVD..

    • @AllLabExperiments
      @AllLabExperiments  Місяць тому +1

      Raman video is out. SEM video is next. Rest on waiting list.

  • @nikhilmohanp7464
    @nikhilmohanp7464 3 роки тому +1

    Brief and informative

  • @ThanseehaSherinPAAP
    @ThanseehaSherinPAAP 2 роки тому +1

    Great video!!!!!

  • @goyenkaneelam
    @goyenkaneelam 3 роки тому +1

    Very much informative. Thank you sir

  • @pralay5156
    @pralay5156 10 місяців тому +1

    Well explained....

  • @zarnaravtal7479
    @zarnaravtal7479 3 роки тому +2

    Thank you so much..explained so well ..very easy to understand.

  • @MA-ff9th
    @MA-ff9th 3 роки тому +1

    very good video sir. THANK YOU VERY MUCH

  • @نونوستار-ل4غ
    @نونوستار-ل4غ 3 роки тому +1

    Thank you for your very good explanation finally I got it😊😊😊

  • @uzmasubhan877
    @uzmasubhan877 11 місяців тому +1

    very welll explained Sir

  • @ajitdwivedi1069
    @ajitdwivedi1069 2 роки тому +1

    Thank you for making a such type of video very well explained in a systemetic way

  • @joelsacademy1409
    @joelsacademy1409 Рік тому +1

    Excellent. God bless you abundantly.

  • @pompapathipompapathi14
    @pompapathipompapathi14 8 місяців тому +1

    Excellent explanation

  • @MohammedIslamElshiekhElsmani
    @MohammedIslamElshiekhElsmani 2 роки тому +1

    Interesting!!

  • @temesgenyiber8614
    @temesgenyiber8614 4 роки тому +2

    nice lecture

  • @MrVedant006
    @MrVedant006 3 роки тому +1

    wonderful video sir.

  • @ankitanikam3804
    @ankitanikam3804 2 роки тому +1

    Thank you for the video, it's really helpful.👍

  • @hussnainshirazi6996
    @hussnainshirazi6996 2 роки тому +1

    woo fine explanation

  • @him31anshu
    @him31anshu 3 роки тому +1

    Thankyou Brother. Thanks a lot. This saved a lot time. Liked. Subscribed

  • @gaithhalloum2076
    @gaithhalloum2076 Рік тому +1

    You did a great job ❤

  • @viditverma4406
    @viditverma4406 3 роки тому +1

    Great video

  • @latifroghani857
    @latifroghani857 2 роки тому +1

    very informative

  • @amit3230
    @amit3230 3 роки тому +1

    excellent explanation

  • @akalankaekanayake1024
    @akalankaekanayake1024 2 роки тому +1

    nice explanation

  • @cd8836
    @cd8836 2 роки тому +1

    Thank you so much! I have a lab tomorrow and this helped a lot!

  • @achyutjagdhane9683
    @achyutjagdhane9683 Рік тому +1

    VERY NICE , THANKS A LOT

  • @payam1597
    @payam1597 Рік тому +1

    wonderful. Thank you

  • @shahzadahmed5012
    @shahzadahmed5012 4 роки тому +4

    Thanks for making the wonderful video. Please add the analysis part also. Small angle and wide angle xray techniques also.

  • @najeebullahkust2708
    @najeebullahkust2708 4 роки тому +1

    thanks a lot, sir to explain the XRD very well and will give very help to researchers.

  • @tommasosanguettoli6808
    @tommasosanguettoli6808 7 місяців тому +1

    Very useful video

  • @_The_Alchemist_
    @_The_Alchemist_ 4 роки тому +3

    @11:45 As you mentioned, peak 1 & 3 will be destructive, similarly, peak 2 and will be destructive. Then, where does constructive interference will come from? It means no XRD signal whatsoever.

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +1

      Plane 1 n 3 give constructive waves .but because of the introduction of plane 2 which is at half of the path difference it cancels wave from plane 1. Similarly there will be another lattice which will cancel plane 3 contribution which is not in picture.
      The conclusion of the discussion is that what layer 2 is not present then there is a peak and because of the introduction of layer 2 it vanishes

    • @_The_Alchemist_
      @_The_Alchemist_ 4 роки тому +2

      @@AllLabExperiments Yes, that's what I meant. This represents BCC. Since plane 1 wave is cancelled by mid plane. Similarly, mid plane cancels the bottom plane. So, how do we get peaks in BCC? Since the structure is periodic, we can just focus on this particular unit cell.

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +1

      @@_The_Alchemist_ This is just one condition obeying bragg's law. BCC structure will not show a peak for this respective plane. But at other angle when it obeys for other planes (@6:30) it may show peaks. And the overall pattern confirms that it is BCC (@12:00).

    • @_The_Alchemist_
      @_The_Alchemist_ 4 роки тому +1

      @@AllLabExperiments No no. My question is for this unit cell which has simply these 3 planes which are going to be repeated throughout the lattice. And if you are saying that at some other angle there may be the reflection, then the systematic absences is hoax. Because when we put the crystal in the machine, it will be scanned over a range of theta. So, why to discuss systematic absences then.

  • @manishkshukla8548
    @manishkshukla8548 4 роки тому +4

    Very clear and lucid explanation. Thanks for creating such great quality videos.

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +1

      Thanks bro. Bs aap dosto ka saath rahe to aise hi kaam chalta rhega....

  • @عبيرمحمود-د1م
    @عبيرمحمود-د1م 2 роки тому +1

    Thank you its simple and clear

  • @rajibdas1087
    @rajibdas1087 2 роки тому +1

    Excellent sir

  • @lolwasamet8096
    @lolwasamet8096 3 роки тому

    Excellent video for XRD beginners. Thank you

  • @dana5731
    @dana5731 11 місяців тому +1

    Please Make a video on Reciprocal lattice and Brillouin Zone, and their application in X-ray diffraction.

  • @amazonphysics3455
    @amazonphysics3455 3 роки тому +1

    Best explanation

  • @Coffeebean1985
    @Coffeebean1985 2 роки тому +1

    Such a great and helpful video. Thank you!

  • @harshithadkharshithadk4031
    @harshithadkharshithadk4031 10 місяців тому +1

    ❤ thank you so much sir

  • @MrChakrvarthy
    @MrChakrvarthy 3 роки тому +1

    very nice video

  • @AbdulJalil-vb5iq
    @AbdulJalil-vb5iq 3 роки тому

    Wow. Very precise and accurate

  • @harshpatil4377
    @harshpatil4377 4 роки тому +3

    Thank you sir

  • @zairazara2923
    @zairazara2923 9 місяців тому +1

    Zabardast🎉

  • @tamanjotsingh6848
    @tamanjotsingh6848 3 роки тому +1

    appreciate your effort. it helped a lot , thanks

  • @EasyChemistryLearningwithDrAbh
    @EasyChemistryLearningwithDrAbh 3 роки тому +1

    Thank you for making such a simple and informative video on XRD

  • @ShraddhaShukla-fw5lt
    @ShraddhaShukla-fw5lt Рік тому +4

    Loved this video. You are an awesome teacher. Thank you. Also, can you please explain the splitting of peaks in XRD graphs?

    • @AllLabExperiments
      @AllLabExperiments  Рік тому +2

      Like in Barium titanate it is tetragonal in nature. So if you look at it from three different sides from two sides there is one inter planar spacing and from one side you see a different interplanar spacing so you see 200 and 002 peaks split because of different inter planar spacing. This splitting may not be visible for lower angle peaks because they don,t get resolved properly by then but with increasing angle they resolve better and you can see them as separate peaks easily.

  • @shwelpajadhav5905
    @shwelpajadhav5905 4 роки тому +1

    excellent...thank you

  • @farhajabeen1484
    @farhajabeen1484 3 роки тому +1

    Nice video

  • @kamnabharati2970
    @kamnabharati2970 3 роки тому +1

    Thank you Sir❤️👍🙏🏻

  • @Rughveda2358
    @Rughveda2358 4 роки тому +1

    thank you sir, nice explanation

  • @mageshwarir9914
    @mageshwarir9914 3 роки тому +1

    Thank you so much sir.., understood clearly🙏

  • @gianodevi3782
    @gianodevi3782 2 роки тому +1

    Excellent.. please make more videos with the origin of how to use the Williamson method and other parameters by XRD please.

  • @divyapruthi4312
    @divyapruthi4312 3 роки тому +2

    Wow kya baat h sir,
    Sir can u tell me what is the effect of particle size on the broadening of Raman peaks
    Acc to 4-5 marks in detail......

  • @yaranasser3310
    @yaranasser3310 2 роки тому +1

    Thank you dear

  • @dwivediannu5843
    @dwivediannu5843 3 роки тому +1

    thank u so much sir

  • @muraliishwar7022
    @muraliishwar7022 8 місяців тому +1

    When will I consider a peak amorphous ? If the peak is broader , should I consider it is crystalline with very small crystallite size or an amorphous material ?

  • @mgbokommesoma6271
    @mgbokommesoma6271 2 роки тому +1

    Thank you for the video. I love it.Can we also get a video where a proper XRD pattern is interpreted and insights are made from the plot Thank you.

  • @youwilllaugh3136
    @youwilllaugh3136 4 місяці тому +1

    Can we explain for example am the dissolution of a clay mineral in terms of lattice strain?

    • @AllLabExperiments
      @AllLabExperiments  4 місяці тому +1

      @@youwilllaugh3136 i guess this is amorphous. And i think for an amouphous it is not possible to get strain.

  • @syedashobnam2573
    @syedashobnam2573 20 днів тому

    Why is the right side of brags law constant?? Thank you

  • @robamatariq8485
    @robamatariq8485 Рік тому

    THANKS for your great effort. Can you please provide material about d-value.

  • @malomatkedunya7266
    @malomatkedunya7266 4 роки тому +3

    How can i determine that this xrd pattern is of cu ic,rhombohedral and tetragonal etc
    I shall b thankful for ur answer

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +2

      First check the JCPDS card of your material or match your data with the literature. You can compare your data with them and determine the shape of the crystal. Different peaks will appear for different structures by matching them you can come to a conclusion of shape... But before that your should have known the composition of your material.

    • @MA-ff9th
      @MA-ff9th 3 роки тому

      @@AllLabExperiments But sir, if you know nothing about the sample, how will you proceed. Please guide me Sir.

  • @shivkortalwar6942
    @shivkortalwar6942 4 роки тому +3

    Excellent video i like the topic and information, what is tensile strength explain, please make more videos on XRD data interpretation for identification and quantification by powder X ray diffraction.

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +1

      Thanks Shiv. I am continuously creating content in this field and soon will reach to that aspects of XRD as well. You can also find origin lab tutorial videos helpful in research field.
      Now let us talk about strain. It is caused either in the case of very small particle size or in thin films (it means high surface area causing strain) or while synthesis the bonds of your compound didn't attain its natural length of minimum potential energy. So as the inter atomic distances change, they reflect this effect in the form of XRD peak shift or peak broadening.
      The strain cause while synthesis can be tuned by your rate of heating or cooling or the pressure around.

    • @pranzz30
      @pranzz30 2 роки тому +1

      @@AllLabExperiments is xray spectrometer and diffractometer same?

    • @AllLabExperiments
      @AllLabExperiments  2 роки тому +1

      @@pranzz30 i have not heard of xray spectrometer... It should be diffractometer i guess...

    • @pankajinimahanta9830
      @pankajinimahanta9830 4 місяці тому +1

      @@AllLabExperiments XPS ( X- Ray photo electron spectroscopy) is there. It is similar to EDS/EDX but in XPS we measure emitted electron and in EDX emitted xray.

    • @AllLabExperiments
      @AllLabExperiments  4 місяці тому +1

      @@pankajinimahanta9830 just in output you may have similar results. On xps carbon correction there is one of my video in which i also discuss its science.

  • @YogeshPatil-ju2ls
    @YogeshPatil-ju2ls 3 роки тому +1

    A very nice video that gives a clear understanding of XRD basics. I have one doubt haw to analyze peaks in terms of h k l values and plane of peaks mainly how to assign planes for particular peaks?

    • @AllLabExperiments
      @AllLabExperiments  3 роки тому +2

      Consider you xrd a random sample about which you don,t know. Then from the available peaks you get to know about all possible inter planar spacings in that structure and then you match your data with the available peak patterns of different structures or do back calculation to know about the structure...
      You must have noticed in one of the slides that simple cubic, BCC, FCC have a certain pattern of visible peaks... just that helps to identify the structure...

  • @niteenjawale3862
    @niteenjawale3862 9 місяців тому +1

    very good video. one problem is that what is the value of the shape factor (K). how it is coming 0.9. If is there any calculation for 0.9 then please tell me.

    • @AllLabExperiments
      @AllLabExperiments  9 місяців тому +1

      This is an average value taken average for all shape values because we rarely know the shape of crystallite present

  • @eshanjaiswal2135
    @eshanjaiswal2135 3 роки тому +1

    Can you please share this presentation. BTW love your content.

    • @AllLabExperiments
      @AllLabExperiments  3 роки тому +2

      Thanks for appreciation. But Sorry, can,t share as it took a lot of efforts to prepare this and also the content is a source of earning for me. B.D. Cullity,s book on XRD contains most of the information and some of the pics. You can use that for the info

    • @eshanjaiswal2135
      @eshanjaiswal2135 3 роки тому +1

      @@AllLabExperiments Ohk Thanks :)

  • @kassk2323
    @kassk2323 3 роки тому +3

    Nice presentation! Could you please explain how can we find out the chemical structure of the particle by using the lattice parameter?

    • @AllLabExperiments
      @AllLabExperiments  3 роки тому +1

      Use literature to match that data and you can find out the chaemical and its structure

  • @sheetalSonar
    @sheetalSonar 4 роки тому +2

    Hello sir, you have explained very well . can you please elaborate on why we use the arbitrary unit for intensity in the XRD pattern?

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +3

      In your XRD pattern, the relative intensity of different peaks depends upon the position of atoms with in the lattice as you have seen in this presentation. Now what if you increase the intensity of your x-ray source? In case of heavy radiation the intensity of all the peaks increases proportionally and vice-versa. Additionally, If you increase or decrease the scanning rate then also the intensity varies so we write it arbitrary.
      The interesting fact is that in all cases the pattern of peaks doesn't change. for example If peak for 011 is the highest and for 012 plane it is around half of the 011 then for any x-ray source intensity or scanning rate this ratio will remain the same if the detector is capable of recording it.

    • @sheetalSonar
      @sheetalSonar 4 роки тому +1

      @@AllLabExperiments Thank you very much for clearing my doubt. One more quick question if I use theta - theta goniometer then can I plot graph of intensity vs theta rather than 2 theta?

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +2

      @@sheetalSonar Sorry I missed your comment. In fact 2 theta is just a convention. There is no harm even if you plot it against theta but the reviewers of your paper may get confused by this. So in my advice don't do this unless there is a strong reason for doing this.

    • @sheetalSonar
      @sheetalSonar 4 роки тому +1

      @@AllLabExperiments Thank you so much for prompt reply.

    • @kaiser434
      @kaiser434 2 роки тому

      @@AllLabExperiments , hi.. I have a quick question. If increasing peak intensity results in a higher peak, is there any setting for the X-ray intensity that needs to be emitted towards the sample in order to get a good match with the fingerprint diffraction pattern of the sample ? The arbitrary unit is still somewhat confusing to me.

  • @deepamakhija1346
    @deepamakhija1346 Рік тому +1

    Nice explanation.. I have one query related to peaks.If we do powder xrd on single crystals of two sets of same compound then in one set peaks coming along 00l direction and in another set peaks are coming 00l as well as hkl.
    So wht is the reason in one set getting peaks only of 00l and in another 00l+hkl? Eventhough both sets grown under same conditions..
    Will u share your views for the same?
    Thanks and regards,

    • @AllLabExperiments
      @AllLabExperiments  Рік тому +1

      Sorry but i am not an expert on single crystals but yes I can look into it in my free time and reply as soon as i get the answer.

  • @lokithaloki8780
    @lokithaloki8780 2 місяці тому +1

    Do the order of diffraction changes the information about the interatomic structure

    • @AllLabExperiments
      @AllLabExperiments  2 місяці тому +2

      @@lokithaloki8780 no. Its intensity is very low and for n=2 it will give the same info

  • @hongzhang1279
    @hongzhang1279 3 роки тому +2

    Thanks for the video. Is the signal intensity affected by the x-ray source power level and sample distance from the detector/or x-ray source?

    • @AllLabExperiments
      @AllLabExperiments  3 роки тому +1

      Yes but in that case all peaks will proportionally decrease or increase and their relative ratio will not change...

    • @hongzhang1279
      @hongzhang1279 3 роки тому +1

      @@AllLabExperiments Thanks for your answer. Yes, I am comparing different instruments with different source power levels and the goniometer radius to see if/how the power and sample distance affect the S/N of a specific sample. Is there an equation you may share please? Thanks.

    • @AllLabExperiments
      @AllLabExperiments  3 роки тому +1

      No these is no such eqn. Not just power but the placement of the sample n how much radiation a sample absorbs also matter. So it is not easy to bound all the things and derive a formula which is not even useful

  • @amag9877
    @amag9877 4 роки тому +1

    thank you so much. please what does the peak area signify?

    • @AllLabExperiments
      @AllLabExperiments  4 роки тому +2

      Youcant interpret peak area in jss one word or theory as it deepnds upon intensity width parameters. So don,t bother for this. Generally in powder xrd if peak width increases then peak height decreases. And area remains almost the same.

    • @amag9877
      @amag9877 4 роки тому

      @@AllLabExperiments thank you very much