Shear Stress Calcuation and Profile for I-beam Example - Mechanics of Materials
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- Опубліковано 8 жов 2024
- An example problem that goes into detail on calculating the shear stress at various points on an I-shaped cross section. In addition, the video explains how to draw the shear stress profile for a beam with an I-shaped cross-section.
Amazing how in 8 min and 25 sec you taught me more than my lectures did in 6 months. Cheers!
+ZehLana efficiency. 😎
Yep that is because the average lecturer (and tutor) is a wasted space - no idea how to explain anything. Academics live in bubble and are practically useless.
Thank you for the kind words and your genuine support. I will say it's pretty rewarding knowing that I'm connecting with people in Australia and many other countries around the world! I'm always hoping that one day I'll go to a conference and someone will yell out "structure free...whasssup!"...and I'll say to the rest of the audience, "that's what I'm talkin' about...recognize (insert jesse pinkman's favorite word)!".
structurefree haha you are extraordinarily Awesome! :)
Decade later, another Australian appreciating your work
Thank you mate
Why are people complaining about the speed, audio... etc... you're essentially get a quality tutoring session from a Professor. Its a video so you can pause, go back as many times as you like. It audio is too quiet on the speakers, use a headphone.
a trick : you can watch series on Flixzone. Me and my gf have been using them for watching all kinds of movies during the lockdown.
@Coen Kaden Definitely, I have been watching on flixzone} for months myself :)
Here in Australia, we call people like you an 'absolute legend'. Thanks for the help, yo
Best illustration and explanation I've seen so far.
You are literally the best, its like listening to gaming youtuber teach you very hard mechaincs wayyyyyyy better than a lecturer ever could!!!! Thank you
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Just wanna say that your tutorials are way more effective than the actual lectures i have to attend.
Dude thank you so much! Incredible how easily you were able to teach this far better than my prof.
bro i cant thank you enough for these videos man. God bless your work bro, ive revised a whole semesters work in an hour with your vids. #not #all #heroes #wear #capes
Being stuck working at home finding the load capacity of a beam, with my college text books at work, I stumbled on this very easy to follow example which jogged my memory. Watched one time and knocked out the max shear for two beams easy. Bravo! Got an example for LTB?
I actually want to cry, I've been struggling with this for hours now and you have made it so simple and easy to understand. Thank you so much :)
"Plug and chug".
Never heard that before.
That alone is worth the price of watching the video. Thanks!
+Joe Parrotta fo sho.
Thank you so much! Now i am ready for my strength of materials exam thanks to you!!
Really great video. I was stuck on this and the video explained it far better than my lecture notes! Thank you
YOUR VIDEOS ARE THE BEST SOURCE OF INFO FOR ANY STUDENT STUDYING ENGINEERING. KEEP UP THE GOOD WORK AND THANKS FOR THE HELP!!! structurefree
you cant ever make this problem clearer, awesome video
All your videos are amazing! I love how you edit out little chunks so that the writing moves as fast as you speak. It really smooths out the video.
Thank you for the kind words and noticing! Editing is a lot more work than I ever thought it would be. No wonder they give an academy award for it.
Thank you for being American and using the metric system. It helped a lot!
Thank you for your comment. I'm a professor but sometimes i wish i were a student...actually no, i just wish i could run faster and jump higher....on third thought, if i'm wishing....this could go on forever.
Thanks a lot for the video, I made an excel sheet for I-beams and it has a >95% accuracy when I checked it with abaqus. Really good explanation as well.
This was very, very, very, very useful. Thank you for the explanation
2 hours before the exam and I needed this so bad... Thank you!
cool............. what happened to the result???
This is what I was looking for, Sir, Thanks indeed !!!
Thank you very much for the clear and thorough explanation!! you've just saved my homework!
No problem! I'm glad the video is helpful.
Your saved my life man. Thank you!
you are the best man. please keep making more videos. you are awesome
Thanks very much for this video, i love the highspeed already prepared style of presentation
Awesome videos, you explain things in very simple ways and your diagrams and writing is so clear. Thank you!
Thank you structure free learning I have so much more of an intuitive sense of mechanics from shear stress in a beam to beam deflection!
great question! the Q would also be zero below it since the distance between the neutral axis of the entire section and the area below the location where the shear stress is calculated would be zero, (i.e. ybar' = 0 since the areas are the same)
Great video. Can't understand how my lectures couldn't explain this!
Great Video! Really helped me learn how to calculate Q
You make it look easy and understandable!! Thank you!
I have been following all your u tube tutorials. They are simply the best in terms of contents and commentary. You have great sense of humour which makes it more interesting to watch! Great work and keep it up and thanks millions. Rahman Rahmani
You are too kind.
really helpful to visualize & understand clearly how they work You should make more videos on ''Strength of Material'' ,you really Good at it
very helpful thank you!! love from Malaysia :)
Thank you sir! This was faster than your other videos, and much more efficient! :-bd
S/O to you buddy, you really know your stuff!! This video has helped in ways that you can't imagine. Salute.
Great explanation and so easy to understand, Thanks so much man!
Good vid. Fast and concise. Thanks alot!
Why did i just found this video today, when my assignment deadline is tomorrow :')
Anyway this a very great, detailed work.. Tq so much : )
You're a lifesaver man.
you are welcome.
Hi im 6 years late but you should know that your videos are so helpful and youre entertaining!!
Awesome video! I look forward for watching more of these to help me out with my Strength class!
Thanks! You're a life-saver.
i finally understand!! many thanks from south africa
this video reaally helped
nice quick way to review for my test... your videos are the best
Really sir, your videos help me a lot, thanks.
+Afnan Ahmad you're welcome!
Dude, you are amazing! THANK YOU!!!
Amazingly eloquent
Great lectures. Thank you very much.
my man, you are a genius
nice and quick, and surprising very well thought-out and easy to fathom!
The only thing I could suggest would be that there are instances where the Max Shear does not occur at the the NA, maybe mention that. Great video though, thank you! Exam tomorrow :)
of course it makes sense...everything makes sense.
(150mm - 20mm)2 = 65mm. This represents the width of the flange from the edge of the web.
This is as well as all your videos is brilliant. Thank you ever so much and god bless you
You taught me sooooo much...........
Awsome, fantastic and you make learning so much fun !!! Thanks millions
Thanks Professor, this is very helpful.
Very clear! Thank you.
Could you explain the forces to connect two I beams if they were stacked on top of each other to work as compound beams???
Thank u bro ,it. was easy to understand through u
structure fuh-reezy!
Superb explanation!
thank you.
Duuude, that was awesome, thanks a bunch I have a test to write this tuesday, and you helped :D, my lecturer is eh...hard to ask questions to -.-''
Wow! Helped so much! Do you have videos on Combined Loadings and Stress Transformation? Keep on posting!
thank you very much! Point B is tricky!
Wow this was brilliant. Thank you so much
Excellent video! Really helped me understand this difficult concept! Subscribed
clear explanations and vocals, :)
Amazing explanation!
You are a savior
thanks mfethu this was very helpful please continue your great job
Extremly helpful!
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Thanks for sharing your information!
thanks so much that was really helpful
hope you keep going on
I liked the video so much.
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Structure Free is simply the best :)
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so cool sir
Your videos are great, thanks a lot!
Dude you serious? You sound like you're in your teens! haha you're one lively Professor bro. Your videos have infinitely reduced my stress levels! Thank you very much
at point A if you take the area under point A how could you find that tau(A)=0 ? Thanks for these videos I preciate.
ybar' is equal to zero if you take the area below.
+canberk fidan the centroid of the area below is the centroid of the whole figure itself so distance between centroids is zero.
@@structurefree how come there us a jump of the shearstress at point B. if you cut the beam at point B i would think the shear stress at both parts of the beam would be the same but in opposite direction ?
again, great video :)
i was just wondering in your calculation for the shear stress at point A, i understand that it would = 0.. but you also say that you can take 'Q' as being the areas above OR below, now it wouldnt = 0 if taken from below. thank you!
Thx a lot from Perú. I was sick about watching lectures from indian professors who have horrible accent until i met you :D
you've got the same voice and accent as Dave Franco. Awesome videos
Oh and not to mention it is fun listening to you as well haha, peace bro
Nice explanation. I was revising though.
That was very helpful thank you so much.
Thank you for saving me
put the topic on the channel comments/discussion section and I'll do my best to get to it.
Very clear!!!Thank you so much!!
dude, thank you very much for these videos! you rock!
Would you please discuss shear stress distribution on a square beam with it's diagonal in vertical direction. ?
explanation for shear strss distribution in 8 minutes.....wow!
Thank you, so MUCH.
Sublime Explanation.