SHM as projection of uniform circular motion

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  • Опубліковано 30 чер 2024

КОМЕНТАРІ • 234

  • @syedhajisajjadhussain9528
    @syedhajisajjadhussain9528 3 роки тому +34

    Ossum lecture every point completely clear .May Allah Bless U. Ur teaching method is good☺🤗☺🤗😊🙏🏻🙏🏻

  • @Imoabubacar
    @Imoabubacar Рік тому +3

    Sir ! God May Bless You ,,thank you so Much ....I really Appreciate your tutorial ,, it's Really Helpful 💪💪 before Watching your Tutorial I was about to Give up On Simple Harmonic Motion ,,,but now on am glad and thanking God to give me Opportunity to view your Video

  • @pareshkumarkhatua8950
    @pareshkumarkhatua8950 3 роки тому +10

    U r the great teacher.my concepts are clear now sir.🙏

  • @dhanuvalla2812
    @dhanuvalla2812 3 роки тому

    I just loved the way you teach really awesome thank u sir

  • @hridaybasa4597
    @hridaybasa4597 7 років тому +6

    it was on the day b4 of my physics xam,this concept of SHM was abstrusing me a lot,then my sis insisted me to have a look in the you tube.then i went through this video nd i could understand everyfrom A TO Z!!really i thank this chap who made me understand this concept throughly...thank you

    • @stopfootage
      @stopfootage 6 років тому +4

      hriday basa You should take some English classes instead

  • @rishabhraj702
    @rishabhraj702 3 роки тому +6

    Thankyou sir my concepts are clear now😊

  • @akanshachakraborty7136
    @akanshachakraborty7136 2 роки тому

    Damn he is just so good at explaining 😍

  • @deborahgebremariam4708
    @deborahgebremariam4708 Рік тому

    Thank you so much u derived a lot of formulas clearly & concisely

  • @ARMY0001
    @ARMY0001 5 місяців тому +1

    Sir really, You are so good at explaining all this physics questions. Hats off sir🫡. Your explanation are still useful till today.

  • @navdeepdeep8371
    @navdeepdeep8371 4 роки тому

    To the point things crisp explanation very well explained
    Thanks sir

  • @JsT_1705
    @JsT_1705 2 роки тому +2

    Thank you it was a great sigh of relief 😊

  • @mahakkuradia7380
    @mahakkuradia7380 6 років тому +1

    Very helpful sir...thanku....make more and more videos. ...thank you so much. ...

  • @smruticreationofficial14nov
    @smruticreationofficial14nov 2 роки тому +1

    I clearly understood from this vdo...... More thanks sir..... 🙏🙏🙏

  • @omparkashmehra7769
    @omparkashmehra7769 Рік тому

    Sir you are very good lecture. You deserve a million views or more .
    May God bless you sir ! 🙏

  • @rafiaomer7079
    @rafiaomer7079 7 років тому +3

    You explained much better than my Physics professor!

  • @olukahiswill3493
    @olukahiswill3493 Рік тому

    Thank u . Ur explanation is awesome

  • @charith6670
    @charith6670 3 роки тому +4

    Concept Crystal clear
    Tq 👍

  • @nerotyagi
    @nerotyagi 7 років тому +3

    sir, today is my physics exam and I was not able to interpret this topic. your video is so good that I understood everything!! you deserve a million views or more! may God bless you!

    • @ssjagtap66
      @ssjagtap66  7 років тому +2

      Thanks for watching and the feedback Harsh!

  • @AdityaYadav-jd8ly
    @AdityaYadav-jd8ly 4 місяці тому

    Sir on 6th march my final exam of 11 class will start, but this chapter is not completed by me conceptually, i have only memorised the formulas only, but after watching your this lecture. My concept is crystal clear now.
    Thanks for your wonderful efforts for us.

  • @shaikjakeer2203
    @shaikjakeer2203 2 роки тому +1

    VERY THANK YOU 😊😊 SIR
    FOR YOUR VIDEO I HAVE CLEARED PHYSICS IN DIPLOMA

  • @gorrekarthik8346
    @gorrekarthik8346 6 років тому +2

    It would help at lot in exam times to learn fastly with out confusion thank you for making this video

  • @boboganbobogan9297
    @boboganbobogan9297 2 роки тому

    Thank you a lot!

  • @martinmanoj2103
    @martinmanoj2103 3 роки тому

    Thank u sir
    at right time I got this video
    So helpful

  • @monikasaharan7975
    @monikasaharan7975 2 роки тому

    Superb explanation ❤

  • @olukahiswill3493
    @olukahiswill3493 Рік тому

    Plz make more videos. Am in Africa I really like ur explanation

  • @dudanaikd9736
    @dudanaikd9736 5 місяців тому

    TQ sir ur teaching method is very good 😊

  • @yujirohanma06
    @yujirohanma06 Рік тому

    wow great explanation, thank you sir

  • @Himanshurar
    @Himanshurar 4 роки тому

    Very good lacture ....very helpfull

  • @nishavarghese6451
    @nishavarghese6451 4 роки тому +2

    sir,
    how does phase difference come into play during projection

  • @anishkhambete1544
    @anishkhambete1544 6 років тому +1

    thanks Mr.Jagtap..... you teach in an awesome way!!!

  • @chandutudum
    @chandutudum 5 років тому

    Soo good sir...
    Excellent sir

  • @shaikjakeer2203
    @shaikjakeer2203 3 роки тому

    SUPER 💖 SIR
    REALLY GREAT
    MY SIR DIDN'T TEACH THAT YOU CLEARLY TEACH

  • @ambatijyothi4139
    @ambatijyothi4139 2 роки тому

    Super..sir...Amazing..explanation🤓😍😘

  • @vasanthp7426
    @vasanthp7426 4 роки тому

    Nice definition sirr. Thankss

  • @Srikanthbudige
    @Srikanthbudige 3 роки тому

    Good lecture I liked it sir

  • @AryanYadav-lf6qn
    @AryanYadav-lf6qn 6 років тому

    it was really OsUm..Watched many bt understood here

  • @honestman276
    @honestman276 2 роки тому

    Thanks. From Bangladesh.

  • @RaviPatel-vd5kx
    @RaviPatel-vd5kx 5 років тому

    Excellent work sirji

    • @ssjagtap66
      @ssjagtap66  5 років тому

      Thank you for watching and the feedback:-)

  • @madhulathaganaraju9888
    @madhulathaganaraju9888 6 років тому

    excellent teaching sir

  • @gauravahuja8410
    @gauravahuja8410 6 років тому +1

    Thank you so much sir
    You are the best tutor...

  • @disha6301
    @disha6301 4 роки тому +1

    such a grt video🙏

  • @889xclusive6
    @889xclusive6 6 років тому +2

    How to differentiate displacement with time for velocity??. I mean we do v=dx/dt= d(Asin(wt) )/dt ... how we do that?

  • @vikasthakur9271
    @vikasthakur9271 3 роки тому

    Bahut bahut aabhar sir aapka

  • @youmayguess4083
    @youmayguess4083 7 років тому

    finally I got it !!! thank you

  • @muskaansharma7668
    @muskaansharma7668 5 років тому

    Why we had take cos wt at place of y in the rough work???

  • @shahhussain8735
    @shahhussain8735 3 роки тому

    Good job sir

  • @technicallakshya7937
    @technicallakshya7937 5 років тому

    Thank u

  • @sumera2214
    @sumera2214 5 років тому

    Awesome explanation!!!

    • @ssjagtap66
      @ssjagtap66  5 років тому

      Thank you for watching and the feedback:-)

  • @M.Aryan.Siddiqi
    @M.Aryan.Siddiqi 6 місяців тому

    Sir, Ossum lecture my every point are clear now
    😊
    I was preparing for exam
    Sir which subjects do you teach in UA-cam

  • @AshishSharma-el3hz
    @AshishSharma-el3hz 7 років тому

    very well got it..thanks sir

  • @abishek9645
    @abishek9645 Рік тому

    Thank you sir💫

  • @vectork3
    @vectork3 4 роки тому

    Thanks sir

  • @kumahhh2915
    @kumahhh2915 5 років тому

    Awesome teaching

    • @ssjagtap66
      @ssjagtap66  5 років тому +1

      Thank you for watching and the feedback:-)

  • @ertugrulghaziofficial157
    @ertugrulghaziofficial157 4 роки тому +1

    Sir ur shirt is nice and it suits a lot on your wrist😊

  • @mr.ssj2131
    @mr.ssj2131 3 роки тому

    Thx a lot.....

  • @a-sumanyadav6098
    @a-sumanyadav6098 4 роки тому

    Sir 👌👌👍👍👍👨‍🏫 thank you sir

  • @motepalliganesh9354
    @motepalliganesh9354 6 років тому

    supper sir .tanq.... very so mutch

  • @niapanselkriselvam4934
    @niapanselkriselvam4934 3 роки тому

    Thank you sir clearly understood

    • @ssjagtap66
      @ssjagtap66  3 роки тому

      Thank you for watching and the feedback:-)

  • @sujathaa2393
    @sujathaa2393 4 роки тому

    Awesome explanation sir...

    • @ssjagtap66
      @ssjagtap66  4 роки тому

      Thank you for watching and the feedback:-)

  • @anjalikulkarni7280
    @anjalikulkarni7280 5 років тому

    is the radius of reference circle always equal to the amplitude?

    • @ssjagtap66
      @ssjagtap66  5 років тому

      Yes. The radius of the reference circle is always equal to the amplitude.
      Thank you for watching :-)

  • @saiajaybompalli3028
    @saiajaybompalli3028 7 років тому

    A very easy way to understand SHM!!!!!!!

  • @kapildevandivyan4401
    @kapildevandivyan4401 6 років тому

    beauty awesome explanation

  • @khs3274
    @khs3274 Рік тому

    The best

  • @AsmaTk-jr5he
    @AsmaTk-jr5he 3 місяці тому +1

    ❤❤❤❤

  • @riyabhurse369
    @riyabhurse369 2 роки тому

    At 7:27 after cos why did you take omega again?

  • @jasmeetniranjan6933
    @jasmeetniranjan6933 7 років тому

    amazing

  • @ShahidKhan-nf4qf
    @ShahidKhan-nf4qf 5 років тому

    A nice and helpful explanation. Thanks sir.but next time plz maintain audio quality it's too annoying. Otherwise you are brilliant

  • @prathiksrp6702
    @prathiksrp6702 7 років тому

    Thank you soo much sir u made me understand this topic in the easiest way possible

  • @DawoodKhan-uf5dc
    @DawoodKhan-uf5dc 6 років тому +1

    impressive

  • @cm-106murali3
    @cm-106murali3 2 роки тому

    Good explination

  • @sachinrath219
    @sachinrath219 4 роки тому

    how will the equation of y change if the particle moves in clockwise direction in the circle,pl clarify.

  • @mehwishkhan8403
    @mehwishkhan8403 5 років тому

    Sir can you tell me what is horizontal diameter and vertical diameter

  • @sachit.bhardwaj
    @sachit.bhardwaj 6 років тому

    Your explanation is brilliant sir. But please use a white sheet rather than a pink one for making the derivations more clearer and easy to understand. Thanks sir .

    • @ssjagtap66
      @ssjagtap66  6 років тому

      Thank you for the feedback. I have used white sheet. It is appearing pink for some reason. Will correct it.

  • @DSouza_Osh_in
    @DSouza_Osh_in 6 років тому +5

    Nice explanation sir helped me a lot but instead of sin there's cos in Maharashtra state book

    • @ssjagtap66
      @ssjagtap66  6 років тому +1

      Thank you.
      If we take the projection on the X-axis we will get cos theta. And that is equally correct.

  • @koduruvinay2534
    @koduruvinay2534 3 роки тому

    Tq sir🙏

  • @blackhole-oy2xd
    @blackhole-oy2xd 6 років тому

    Does this have anything to do with Swedish house mafia???

  • @tubasiddiqui380
    @tubasiddiqui380 5 років тому

    Thanks a lot for this video!!

    • @ssjagtap66
      @ssjagtap66  5 років тому +1

      Thank you for watching :-)

  • @mazharsksk1730
    @mazharsksk1730 6 років тому

    Thnx to explain this

  • @tnaccountancy6600
    @tnaccountancy6600 3 роки тому

    Supet

  • @burhanuddin4753
    @burhanuddin4753 5 років тому

    nice explination sir

    • @ssjagtap66
      @ssjagtap66  5 років тому

      Thank you for watching and the feedback:-)

  • @niroshanvenkateshwaran
    @niroshanvenkateshwaran 7 років тому

    Shouldn't the derivative of sine be negative cosine?

    • @ssjagtap66
      @ssjagtap66  7 років тому

      No. Derivative of sine is positive cosine. The derivative of cosine is negative sine.Thanks for watching the video.

  • @GtaSandreasModder
    @GtaSandreasModder 7 років тому

    Hello sir. Thank you so much for your explanation.

  • @shivakumargadepaka947
    @shivakumargadepaka947 3 роки тому

    Tq Sir

  • @brahmeshs9655
    @brahmeshs9655 5 років тому

    Very helpfull

    • @ssjagtap66
      @ssjagtap66  5 років тому +1

      Thank you for watching and the feedback:-)

  • @pinakroy8599
    @pinakroy8599 6 років тому

    super sir

    • @ssjagtap66
      @ssjagtap66  6 років тому

      Thanks for watching! :-)

  • @asifalamjoy9530
    @asifalamjoy9530 4 роки тому +2

    What does the word "projection" mean over here?

    • @ssjagtap66
      @ssjagtap66  4 роки тому +1

      The point we get on the diameter when a perpendicular is dropped from a point on the circle

    • @sabahatbatool4234
      @sabahatbatool4234 3 роки тому

      ua-cam.com/video/bnnSVEVq3p0/v-deo.html

  • @ComedyCapsule143
    @ComedyCapsule143 5 років тому +2

    Sir in shm w is angular frequency

    • @rrtuition7740
      @rrtuition7740 4 роки тому

      SINCE SHM IS SHADOW OF UCM SO IF UCM ANGULAR VELOCITY FAST MEANS SHADOW SHM WILL MOVE FAST HENCE WE SAY ITS ANGULAR VELOCITY S OMEGA

  • @kumarnakka8049
    @kumarnakka8049 4 роки тому

    tq sir

  • @alexgiri361
    @alexgiri361 7 років тому

    nice sir..plz upload the vedio on astronomical telescope

  • @apttde6817
    @apttde6817 6 років тому +1

    thank you very much sir it is very help full to me

  • @tnaccountancy6600
    @tnaccountancy6600 3 роки тому

    Super

  • @aliyajafar1986
    @aliyajafar1986 Рік тому

    Thnkyou sir

  • @mayapol4853
    @mayapol4853 Рік тому

    Best

  • @MuhammadAbdullah-zl2dt
    @MuhammadAbdullah-zl2dt 3 роки тому

    Sir what is the meaning of projectile?

  • @manasih.s.3114
    @manasih.s.3114 4 роки тому

    Thank you sir helped a lot!!

    • @ssjagtap66
      @ssjagtap66  4 роки тому

      Thank you for watching and the feedback:-)

  • @waaheedkhan4976
    @waaheedkhan4976 6 років тому +2

    Outstanding

  • @panyida
    @panyida 5 років тому

    could we derive that function using other example like horizontal motion model?

    • @ssjagtap66
      @ssjagtap66  5 років тому

      Yes.
      In that case we would get cos instead of sine

  • @ChrisFolland
    @ChrisFolland Місяць тому

    Unfortunately there are mistakes here. You can not cancel the density terms since these terms refer to different densities. One is of the block and the other the fluid. This should be intuitive since in ( wrongly ) cancelling the terms you reach a result which means that the period is independent of the density of the water which is clearly not the case. You can check this by adding salt to the water and observing a change in the frequency

  • @DeepakSharma-ds2bh
    @DeepakSharma-ds2bh 7 років тому

    plzz tell me that in circular SHM .. if we see the simple pendulum where is the disp. x and amplitude A in that .. is the simple pendulum which is available in physics lab. follows this👆👆 circular motion .. if yess .. where is the displacement nd amplitude there???? plz answer

    • @DeepakSharma-ds2bh
      @DeepakSharma-ds2bh 7 років тому

      i want reply fastt. plz

    • @rrtuition7740
      @rrtuition7740 4 роки тому

      @@DeepakSharma-ds2bh MY DEAR WHEN WE PULL SIMPLE PENDULUM FROM ITS REST POSITION MEANS IT IS DISPLACED.HE MAXIMUM DISPLACEMENT IS XWE WRITE RESTORING FORCE =mgsintheta ,for small angle theta =x/L

  • @saudriyaz1283
    @saudriyaz1283 7 років тому +1

    Thanks now I understood 😊

    • @ssjagtap66
      @ssjagtap66  7 років тому

      Thanks for watching! :-)