Entropy Change of Ideal Gases | Thermodynamics | (Solved Examples)

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  • Опубліковано 11 лис 2024

КОМЕНТАРІ • 17

  • @xo571
    @xo571 7 місяців тому +1

    didn’t even watch this video but i always appreciate the work u put into ur videos. hope all is well in ur life 😁👍

    • @QuestionSolutions
      @QuestionSolutions  7 місяців тому

      Thank you very much! I appreciate the comment. All is well, I hope yours is good too! 😊

  • @milannikic3837
    @milannikic3837 7 місяців тому +4

    thermo exam coming up, please more!!!!

  • @iamalihussein
    @iamalihussein 6 місяців тому +1

    Your videos are perfect ❤

  • @nimipen
    @nimipen 9 днів тому

    Hello! I have a question for the last problem you solved why was the Wout a negative?

    • @QuestionSolutions
      @QuestionSolutions  9 днів тому +1

      I am not exactly sure where you're referring to, is it 11:25? If yes, we have energy in minus the energy out, and we are told there is 600kJ of work output, so the negative sign in front means we multiply the 600 by the negative sign, giving us: -(600 kJ) = -600kJ.

    • @nimipen
      @nimipen 8 днів тому

      @@QuestionSolutions Yes it is that! Thank you so much I just got confused about the sign convention for when work is positive or negative!

  • @bhbvh4904
    @bhbvh4904 7 місяців тому

    Just in time for my quiz!

  • @kylecatman7738
    @kylecatman7738 3 місяці тому

    In the last example, If you said it produced 200,000 kJ we would've gotten a positive delta S also. But is that realistic?? Just because delta S is positive??

  • @MMMMMMMMMMBALLS
    @MMMMMMMMMMBALLS 7 місяців тому

    perfect timing

  • @godoffootball-24.7
    @godoffootball-24.7 7 місяців тому

    please a question concerning the second trial question, please why did you use 450k in determining the K ,since the first temperature was 300.15k

    • @QuestionSolutions
      @QuestionSolutions  7 місяців тому +1

      So you need an average temperature to use the equation, right? So you're just using an educated guess to figure out what the average temperature would be. You can pick 400, 450, 500K, etc, but it needs to be around there since the temperature will rise during the compression. You will get similar values regardless of the temperature picked.