How to calculate the required bearing plate thickness to support a steel beam bearing onto a masonry

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  • Опубліковано 12 тра 2021
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    Using a worked example| we will demonstrate how to calculate the required thickness of the bearing plate that takes the reaction of a steel beam and distributes the force over a masonry wall.
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КОМЕНТАРІ • 23

  • @suhaibkhan7356
    @suhaibkhan7356 2 роки тому

    Well explained doing good work for important useful design

  • @emmadavies7434
    @emmadavies7434 3 роки тому

    Very impressive thank you

  • @vikas_mourya
    @vikas_mourya 2 роки тому

    Awesome.... content

  • @thangtrinh7384
    @thangtrinh7384 3 роки тому

    nice!

  • @alisomizaias5534
    @alisomizaias5534 Рік тому

    Fantastic resolution. But i have a question, all this math is based in some manual, guide, norm or just strenght of materials?

  • @timothyadem8354
    @timothyadem8354 2 роки тому

    How do you calculate and design Analysis for a block and beam slab

  • @aliveli3519
    @aliveli3519 2 роки тому

    i am planning to construct a studio over an existing masonry garaj ( 1 story) but I am not sure if I need to retrofit it for this adding another static load on it? what you think? how can I retrofit it support it or should I do it? should I use steel from outside? now there is a roof. I am planning to make it higher to fit a studio inside. give me an idea pls.

  • @frhproductions9327
    @frhproductions9327 Рік тому

    can you please with me the formula which used in this calculation taken from which reference.

  • @SUREshARTS
    @SUREshARTS 3 роки тому

    What software u r using? Doodlify?

  • @richardmtonga9784
    @richardmtonga9784 3 роки тому

    So in short, for purposes of over designing, plate thickness of above 10mm is okay to use because it will produce stress of less than 275?
    Another question, is there a machine that can be used to ascertain the required thickness of base plate?

  • @Fshah1
    @Fshah1 2 роки тому +1

    Hi, I as per my understanding,
    Factored stress under bearing plate = Maximum factored Share force / Area of bearing plate must
    should less than Allowable compressive stress of brick masonry.
    Where assumed allowable compressive stress of 225 mm thick brick masonry = 2.9/3 = 0.97 N/mm2. But in your calculation, it is 1 N/mm2 which is exceded to 0.97 N/mm2 ?. Please advise.
    I have calculated size of bearing plate as 850x215x35 mm for a 4800 mm long 203x203x46 kg/m U.C in opening of 225 mm thick main load-bearing brick wall. Maximum factored share force is coming as 95 KN. Where only total 450mm spaces is available on both ends. Practically it is not possible to insert 850 mm long M.S plate in 450 mm space. Please advise.
    In one other case, I have calculated size of bearing plate as 1500 x100x70 mm for a 6900 mm long 203x203x46 Kg/m U.C. Maximum factored Share force is coming as of 129 KN. size of the supporting wall in each end is 300 mm (cavity wall). So, thickness of bearing is limited to 100 mm. Please advise,
    1) is providing 1500 mm long M.S plate is in order?
    2) can we use 275 mm thick width of bearing plate on cavity wall.In this way length of the bearing can decrease from 1500 mm to 500mm. But the beam will cross to the cavity portion of the wall.
    3)) What is allowable compressive stress for a light weight of 100 mm thick concrete block.
    4 ) is there any difference in Euro and British steel code as for as calculation of bearing plate is concerned?
    Thanks

    • @alexadept
      @alexadept 2 місяці тому +1

      You are very good observant. I observed it now and the right thing to do is to increase the area of the plate by increasing the length of the plate. Doing this the applied stress will be less than the allowable stress.
      Please note you don't factor in the load. Use Service load.
      Thanks.

  • @LvPatriot1
    @LvPatriot1 3 роки тому +1

    Great video. I have a question. So stress below the plate is 1 N/mm², the fk=2.9 N/mm² and the yM=3, so the allowable stress below the plate for the masonry is 2.9/3=0.97 N/mm² which is less than the stress under the plate. I would say that plate must be made wider to pass this check as well. Is that correct or I missed something?

    • @StructuralEngineerCalcs
      @StructuralEngineerCalcs  3 роки тому +1

      Thank you for your comment. This video shows you how to briefly work out the plate thickness which supports a steel beam. However, in order to work out the allowable stress below the plate, you would need the wall dimensions and the location of the beam. The allowable stress equals enhancement factor for concentrated loads times design compressive strength of masonry! So easily, the allowable stress is greater than one.

    • @LvPatriot1
      @LvPatriot1 3 роки тому

      @@StructuralEngineerCalcs Thanks for the swift reply. Hmm, I will have to dig a bit in the EC to get familiar with the enhancement factors. I have seen that for the RC structures, when there is a C-C-C(full compression) in a strut-tie model, then the concrete strength can be increased by a factor o 3 if I remember it correctly. Also, is there a universal understanding on how to calculate the stiff bearing length? In this video it was beautifuly shown for the I-beam, but I was wondering about RHS or L angles or other , well L angles are not the typical used sections for beams, but still, maybe this knowledge can be shared.

  • @motwerrahman3289
    @motwerrahman3289 2 роки тому

    Hi how did you get t squared / 6, for section modulus shouldnt it be multiplied by breadth also?

    • @suhaibkhan7356
      @suhaibkhan7356 2 роки тому +1

      It takes per meter 1xtsq

    • @haithamalfarhan4612
      @haithamalfarhan4612 2 роки тому

      ​@@suhaibkhan7356 & Structural Engineer Calcs, so the moment should be taken per meter too. something wrong please check

    • @kuklangaren
      @kuklangaren 2 роки тому

      @Tom Shouldn't it still be ((QL^2) / 2) / ((L*t^2) / (6)) or (QL / 2) / (t^2 / 6)? where Q=UDL

    • @kuklangaren
      @kuklangaren 2 роки тому

      @Tom Ohh I see now. Q would not be equal to 1 N/mm^2, but rather 100 N/mm if you want to use the conventional way, although the one you used and the one used in the video is a lot faster. Thanks for the replies!

  • @johnymingle
    @johnymingle 2 роки тому

    Oh I see, well that's easy enough

  • @manoweb1
    @manoweb1 Рік тому

    so in theory, you said there is no possible way I can calculate this to apply it.... 🤯