Clean way, but too bad you didn't explain well 😊 I mean you should have introduced a variable at least and thrown in some comments... otherwise onlybthose who know this stuff already would be able to follow
Hey author, WHY did you have to overcomplicate things by doing that nonsensical division ? Why didn'y introduce variable y=5× right away ?! Dividing entire equation by expression containing x (125× in your case) can result in losing 1 of possible roots
Come on! This one is easy, why 13 mins ? let t=5× t+t² = t³ t³-t²-t = 0 t(t²-t-1) = 0 t1 = 0, 5× = 0 - nonsensical as there is no such x that would make 5× = 0, rejecting so now it's a matter of solving this innocently looking quadratic equation: t²-t-1 = 0 I can tell the roots are going to be irrational, maybe even imaginary - so I can't be bothered doing the tedious bit 😂
Very thorough explanation, so it was always easy to follow along
5^x+5^2x=5^3x
5^x(1+5^x)=5^x(5^2x)
(5^x)²-5^x-1=0
5^x=(sqrt5+1)/2
x=log((sqrt5+1)/2)/log5
x≈0.299
Clean way, but too bad you didn't explain well 😊
I mean you should have introduced a variable at least and thrown in some comments... otherwise onlybthose who know this stuff already would be able to follow
Hey author, WHY did you have to overcomplicate things by doing that nonsensical division ?
Why didn'y introduce variable y=5× right away ?!
Dividing entire equation by expression containing x (125× in your case) can result in losing 1 of possible roots
The way you write the x hurts my eyes
😂😂😂naso u talk to teacher when we de school...😮
Come on! This one is easy, why 13 mins ?
let t=5×
t+t² = t³
t³-t²-t = 0
t(t²-t-1) = 0
t1 = 0, 5× = 0 - nonsensical as there is no such x that would make 5× = 0, rejecting
so now it's a matter of solving this innocently looking quadratic equation:
t²-t-1 = 0
I can tell the roots are going to be irrational, maybe even imaginary - so I can't be bothered doing the tedious bit 😂