Hello mam, you are really outstanding..Your methodology of teaching is so impeccable... Feeling lucky to find your channel..i can't afford coaching .. Please keep going like this
Up until this video, I was shrouded in the darkness of not knowing how to electron count. I can now see the light and you are the sole reason why I do not live in that dark pit any longer. May god bless your soul and your offspring for eternity, I will forever be in your debt and from this moment on my life's purpose is to serve any of your needs. May god bless you, america, and baby jesus. 🏈
"Jis jis ke man me aaya hai 2 , wou khud ko ek chata lagao".... Hehe it was damn cute... You teach as if our guardian is teaching to us.... So much of love , respect and blessings for u mam.... ❤... Forever grateful ❤
Mam...Kolkata Ka best inrgnc sir k pas tution leta hu...par class me above the head.. flying plan...abhi Pura samajh me aya...keya para raha tha sir...thank u mam
Mam in previous video you told for e' s donated by lp sigma bond double bond formal charge equal to zero but in this in examples you take -2 as formal charge in M=CH
Thanks ma'am for ur videos which are beneficial ever for those students who belongs from village area or small towns. I was one of those student. I suggest another book. Organometallic compounds by Dr Indrajeet Kumar which explains maximum property of the organometallic compound in Lucid manner and very beneficial for Net, Gate and set
Thank you mam for this video.. one request for u mam i,e pls make the videos of retrosynthesis, disconnection,protecting groups. u r like not just a teacher can't explain mam for our sake u can do this all.... Thank you so much mam......
In benzene anion negative charge resides on sp2 hybrid orbital and it is perpendicular to p orbital and does not involve in resonance thats why it is aromatic.
It's helpful or maine sach me chanta mara khud ko coz pahle Mene 2 hi consider Kiya tha hepticity lekn thik Kar diya tha chanta maro bolne se pahle 🤣🤣🤣🤣
Mam 11th example me ek doubt hai.. neutral method me jab electron count kar rahe hai tab homolytically 4 bonds cleav kar rehe hai to 4 e- Mila... Per ionic method me jab e- count kar rehe hai to heterolytically cleav karenge 4bonds to 8e- milna chahiye na..??
22:06 mam aapne btaya conjugation m participate nhi krta toh jb hm aromaticity calculate krte h agr hm vha y example le toh y aromatic nhi hota bu anti aromatic BN jata h ???
Mam please answer me As you told that's e- donate by line pair, double bond , Sigma bond then Formal Charge =0 but in Question no 3,4,5 is not zero why please explain me mam
@@mohilthanki2960 but jb humne formal charge k questions kiye the usme to 8th question m formal charge 0 liya tha wha bhi to double bond directly attached tha
Hlw mam ! Mujhe ek confusion h ki -- hepticity to sirf no of donor atoms attached count krte h..toh zeise's salt me.. hepticity to 4 hona chaiye but 2 kyu aate hai??
no mam has told if M is attached with double or triple bonded system i.e alkene or alkyne then formal charge is zero but here M is double bonded with carbon thats why formal charge is -2 for double bond and -3 for triple bond
Thnku mam bhutt helpfull rhi mam😁😁😁 mam 11 waala question smjh nii aaya ache se formal chaarge humne -2 ku Kiya mam saare carbon share krre hai toh -4 ku Ni hua ??
Thankuh mam ...mam mujhe 3 ,4,5 question me doubt hai alkene me double bond hai aur alkyne me triple bond aapne bola tha pie bond lone pair sigma bond ke liye formal charge zero hota hai aur 5 me co hai wo neutral ligand hai uska b..formal charge zero hoga..mam plzz reply...
thank you so much ma'am for this video.. I am preparing for entrance solely from your explanations... I have a doubt... in q.11 the electrons are donated from pi-bonds..so shouldn't the formal charge be zero?
Electrons are not donated by pi bonds because in that case, the structure will be antiaromatic and hence unstable. So we first change it to aromatic form by putting negative charges on 2 of the ligands, hence it becomes stable. And then we see the formal charge that will come to be -2
Mam aapne bta to diya ki sb parrel hote h but mam y sb to hypothetical hota h na to to repulsion to hoga hi jisse ki unkie geometry m gadbad aaye or wo planer tut jaye or benzene ring hi khtam ho jaye??
Ma'am if e is donated from a double bond then FC is 0 , as u told in previous video ... So in question no.3 , formal charge will be 0 , no! Kindly clear my doubt 🙏🏻
Excellent lecture but phenyl cation or phenyl anion is not correctly explained mam. Both are aromatic since charge is residing at sp2 hybrid orbital which is orthogonal to pure p orbitals resulting localisation of the charge.
Mam please make me clear one thing that in metal Carbonyls CO is inorganic but why metal carbonyls are organometalic? Similarly O2 molecule in example 9 is organometalic?
Hello mam , 5th example me agar C O neutral ligand he to fir uska formal charge 0 hona chahiye na aapne uska f.c . -1 likha hai why ???? Big Question ⁉️
Thank you dear..you are such an outstanding mentor i ever met... Be like this..May god bless you with all happiness and sucess in life..
Hello mam, you are really outstanding..Your methodology of teaching is so impeccable... Feeling lucky to find your channel..i can't afford coaching .. Please keep going like this
Thank you, God will bless you with great success and protect u from all deadly diseases.
Up until this video, I was shrouded in the darkness of not knowing how to electron count. I can now see the light and you are the sole reason why I do not live in that dark pit any longer. May god bless your soul and your offspring for eternity, I will forever be in your debt and from this moment on my life's purpose is to serve any of your needs. May god bless you, america, and baby jesus. 🏈
Thank you so much..my the best chemistry teacher...
Thank you so much simplification made easy to solve numericals😊
In the era of online classes you are our Messiah🙌❤
Thank you so much mam.
Simply outstanding teaching
"Jis jis ke man me aaya hai 2 , wou khud ko ek chata lagao".... Hehe it was damn cute... You teach as if our guardian is teaching to us.... So much of love , respect and blessings for u mam.... ❤... Forever grateful ❤
Thanku mam.best tarike se explain krti h ap.
11 month k baad again ye video dekh rha hu , aur 24:52 m fir se bohot hasi aaya . But farq h iss baar m correct tha .
Thank you so much mam..it's very helpful 🙏
Thanks a lot 🧡🧡.......It’s very helpful🥰🥰
The examples are very good..keep it up mam
U r good teacher mam
Thanks ma'am need this likes teachers.. hindi students..
24:50 chaanta lagao 😂 that was epic. Obviously ma'am we are talking about Hepticity not denticity. Maza aa gaya 😂
Very nice mam n thank you so much
Ma'am all time my favorite😍😍😍so stunning look ❤❤❤❤both are so cut
Nice video mam😊👌
Thank you mam. Your lessons are very helpful
I literally slapped myself and couldn't stop laughing cause I was about to write hepticity 2 in question no. 3😂
Jbaat❣️❣️
I also did same thing Yar 😁
Mam thanks for your efforts. Plz explain electron donation by the bridging ligands in the complex
Thank you much mam.god is always blessing you🌹🌹🌹👏👏👏👍👍👍
Thanku so much for video
Thank u mam....as expected lit one 🔥
amen!
best , to the spot explaining
Fabulous... Dear... And your dialog *chanta lgaoo😂😂😆...
Mam...Kolkata Ka best inrgnc sir k pas tution leta hu...par class me above the head.. flying plan...abhi Pura samajh me aya...keya para raha tha sir...thank u mam
Clear...👌👌👌👍👍
Thank you mam vese bhi electron contribution mein m bhut confuse thi
Mam in previous video you told for e' s donated by lp sigma bond double bond formal charge equal to zero but in this in examples you take -2 as formal charge in M=CH
Point out this comment mam
I like the way you say, ek chata lagao 😁.
Thank you so much ma'am
Thanks ma'am for ur videos which are beneficial ever for those students who belongs from village area or small towns. I was one of those student.
I suggest another book.
Organometallic compounds by Dr Indrajeet Kumar which explains maximum property of the organometallic compound in Lucid manner and very beneficial for Net, Gate and set
Is book ko download krny ka link send kr do plz
U r magic...and great
Thank you mam for this video.. one request for u mam i,e pls make the videos of retrosynthesis, disconnection,protecting groups. u r like not just a teacher can't explain mam for our sake u can do this all.... Thank you so much mam......
In benzene anion negative charge resides on sp2 hybrid orbital and it is perpendicular to p orbital and does not involve in resonance thats why it is aromatic.
It's helpful or maine sach me chanta mara khud ko coz pahle Mene 2 hi consider Kiya tha hepticity lekn thik Kar diya tha chanta maro bolne se pahle 🤣🤣🤣🤣
Mam 11th example me ek doubt hai.. neutral method me jab electron count kar rahe hai tab homolytically 4 bonds cleav kar rehe hai to 4 e- Mila... Per ionic method me jab e- count kar rehe hai to heterolytically cleav karenge 4bonds to 8e- milna chahiye na..??
22:06 mam aapne btaya conjugation m participate nhi krta toh jb hm aromaticity calculate krte h agr hm vha y example le toh y aromatic nhi hota bu anti aromatic BN jata h ???
very good mam.
Thankyou mam you are very outstanding mam
I m from pak is the best licture
Mam please answer me
As you told that's e- donate by line pair, double bond , Sigma bond then Formal Charge =0 but in Question no 3,4,5 is not zero why please explain me mam
Because it is directly attached to that bond.
@@mohilthanki2960 but jb humne formal charge k questions kiye the usme to 8th question m formal charge 0 liya tha wha bhi to double bond directly attached tha
Wha pe M double bond C hai na ki C double bond C
Thank you mam …..you are really Great.
Benzene ring m -tiv nhi aayega vo neutral ligand h
Thank you ma'am....😊😊😊
You are so beautiful ma'am and your lecture is so nice and interesting
Wow amazing...
Ma'am in the example no. 8, electron contribution from neutral method should also be 2 since CO is a neutral ligand. I think so.
-CO is neutral, in 8 it is-COR
Very nice mam
24:52 😂😂😂jisney bhi 2 socha khud ko chanta lagao sunte he hass diya
Nice explanation mam
Mam, Jo 4th question h jisme Carbonyl metal k sath attach h usme formal charge 0 hona chahiye.Kyonki CO neutral ligand h.
HAN MAM M-CO KA formal charge 0 hoga (CO) is a neutral ligand
Thanks 😊 ma'am 👍😀
Maam ques 5 mein carbon monoxide is a neutral ligand so it donates by lone pair that's why N=2 but f.c =0 hona chaiye na??? Apne -1 likhaya
Jyoti Rathi maam plz reply??
Thank you ma'am 😊
Thank you Ma'am 🙏🏻🙏🏻
In q.no 3 why f. C is not 0 as electrons shared b pi bonds.., in ist video u said f. C will be 0 for double bond
Thank you di😃🤗🙏💐
chata lagao .yesssssss mam laga liye😍😍👍❤❤❤❤
Mam please do make video on chapterwise weightage for gate chemistry 2020
Awsome
Ma'am which book u would suggest for organometallic compounds
Can u plz explain me qtn 12 its f.c
N how it can be +1
At 28:40 CO is neutral ligand so FC should be 0 right ?? as like que. 9
Thanks mam
🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
my all concept for e. c. is clear
Thank you very much mam 😊
Nice one
Hlw mam ! Mujhe ek confusion h ki -- hepticity to sirf no of donor atoms attached count krte h..toh zeise's salt me.. hepticity to 4 hona chaiye but 2 kyu aate hai??
Best part is 24:53 😅😅😅
Mam at 25:50 the formal charge M=ch2 should be zero na mam ... formal charge due to double and triple bond should be zero..
no mam has told if M is attached with double or triple bonded system i.e alkene or alkyne then formal charge is zero but here M is double bonded with carbon thats why formal charge is -2 for double bond and -3 for triple bond
Mind blowing am fan of you pls help me to give notes PDF for net okk jii very amazing
mam aape bhut achhi h
Mam app ka time hoo to ekk vidio bana dijiyee pls stereochemistry of cyclohexne kee oppor mee pls.
Thnku mam bhutt helpfull rhi mam😁😁😁
mam 11 waala question smjh nii aaya ache se formal chaarge humne -2 ku Kiya mam saare carbon share krre hai toh -4 ku Ni hua ??
mam if Q will ask in exam so Which one is prefer neutral or ionic However Both gives different electron
26:47 isnt contribution of pi and sigma bond is 2 then why it is 1 and 1 for both neutral and ionic .ethod
Ex-5
Agar carbonyl electron contribution me neutral ligand he to F. C. =0 hoga na????
🌸💮Thanks jyoti..💮🌸
💐💐💐35-like💐💐💐
Thank u very much
Thankuh mam ...mam mujhe 3 ,4,5 question me doubt hai alkene me double bond hai aur alkyne me triple bond aapne bola tha pie bond lone pair sigma bond ke liye formal charge zero hota hai aur 5 me co hai wo neutral ligand hai uska b..formal charge zero hoga..mam plzz reply...
Yes same doubt😢
Can someone explain me the 10th example it's already aromatic so f.c should be +1?
great mem
thank you so much ma'am for this video.. I am preparing for entrance solely from your explanations...
I have a doubt... in q.11 the electrons are donated from pi-bonds..so shouldn't the formal charge be zero?
Electrons are not donated by pi bonds because in that case, the structure will be antiaromatic and hence unstable. So we first change it to aromatic form by putting negative charges on 2 of the ligands, hence it becomes stable. And then we see the formal charge that will come to be -2
Mam aapne bta to diya ki sb parrel hote h but mam y sb to hypothetical hota h na to to repulsion to hoga hi jisse ki unkie geometry m gadbad aaye or wo planer tut jaye or benzene ring hi khtam ho jaye??
Thanku so much mam...
Thank you ma'am.....
Thank you so much mam very helpful for me
Ma'am if e is donated from a double bond then FC is 0 , as u told in previous video ...
So in question no.3 , formal charge will be 0 , no!
Kindly clear my doubt 🙏🏻
Superb mam
Thanks you mam 🙏🏻🙏🏻
Man last example ma ionic electron contribution 8 aave ...🙌
Thanks di...
Thank you so much mam
Excellent lecture but phenyl cation or phenyl anion is not correctly explained mam. Both are aromatic since charge is residing at sp2 hybrid orbital which is orthogonal to pure p orbitals resulting localisation of the charge.
Mam.. In question no. 5 why the formal charge is -1not zero.. Though it'a neutral ligand...
Same question !
Plz answer this ques..
it's 0
Mam please make me clear one thing that in metal Carbonyls CO is inorganic but why metal carbonyls are organometalic? Similarly O2 molecule in example 9 is organometalic?
Thankuu mam😘
Hello mam , 5th example me agar C O neutral ligand he to fir uska formal charge 0 hona chahiye na aapne uska f.c . -1 likha hai why ???? Big Question ⁉️