Newton Raphson Method - Problems in hindi(Part-II)
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- Опубліковано 6 лют 2025
- This video lecture " Newton Raphson Method in hindi(Part-I) " will help Engineering and Basic Science students to understand following topic of of Engineering-Mathematics:
1. Two solved example
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f’(x)= 3x^2-3 kaise huwa ….can you explain ???pls…
@@avinashchoudhary1951 can't u know the differentiation of the function
@@avinashchoudhary1951f(x)=x^3 - 3x + 1
f'(x)= 3(x)^3-1 -3(1) +0
f'(x)= 3x^2 - 3
Differentiation me x ke power aage aa jati h aur bohi power -1 karte h
ab aap kya kar rhe ho bhaiya?
7 years ke baad bhi yeh videos use krr rhe hai !! Bcz college mei teachers ka smjh nhi aata 😒😒.....Thankyou so much sir
THE GOD OF MATHEMATICS thankyou sir
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f’(x)= 3x^2-3 kaise huwa ….can you explain ???pls…
Yesss
@@avinashchoudhary1951 bhai f'(x) matlab... f(x) ka differentiation with respect to x
After 7 years of uploading the vdo, I'm learning and it helps a lot.
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Really
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Bhagwan Singh Vishwakarma
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Jai Hind, Vande Mataram?
8:11 the value of f(x2) will be 3.5*10^-6 not 10^-5
Thank you sir, bahut achhe se samajh me aaya, ye wala chapter itna hard lagta tha ki aisa lagta tha kabhi Nhi bnne wala e humse 😀.
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I think this equation has 2 roots--> One at x=0.3472 another one at 1.532091
Substitute the first value or the second value in the equation u will get 0 in both cases..
*_But my computer always gives the second answer(which gives more 0's after the decimal)_*
Any coder brother can check this C code out-->
#include
#include
#include
#define f(x) (pow(x,3)-(3*x)+1)
#define g(x) (3*pow(x,2)-3)
main()
{
float n,a,z,c;
printf("enter a number and accuracy---> ");
scanf("%f %f",&n,&a);
while(f(n)>a)
{
z=n-(f(n)/g(n));
n=z;
}
printf("x= %f where y=0",z);
getch();
}
power of x is 3 hence it will have 3 roots , you will find negative for f(x) when x is above 1 also because its curve is cutting x 3 times.
Sir I am Bsc cs students but within 5 days I started study by seeing yours videos and I got 30 out of 40 thank you sir but I have to a request to you that you must teach also Bsc math all paper like discrete and real analysis and complex
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*how to find X1* ?
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Jai Hind, Vande Mataram?
Thanks ! for your enlightening lectures , Sir.
I have a doubt at 9:57 ,when you write x=0.3472 , I think it should be x=0.3473 because x2 = 0.347295 , and when we write correct upto four decimal places x needs rounding off which gives x= 0.3473
I checked x3 was 0.347308.
So, x2 and x3 are not same upto 4 decimal points!
Thank you so much sir🙏🧡
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Hameshs Khush Rahiye
जय हिन्द, वन्दे मातरम्
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@@BhagwanSinghVishwakarma f’(x)= 3x^2-3 kaise huwa ….can you explain ???pls…
sir your way of teaching is very good and your way of talking is very humble and cute :)
Sir you have said that if the functional value for an approximation contains four zeros after the decimal then the approximate value is correct upto four decimal places but for the second question in case of x1,it is correct upto three decimal places whereas f(x1) contains only one zero after the decimal.How it(x1) becomes correct upto three decimal places?How to understand the exact correction of the approximate value (i.e., how to know the number upto which the approximation is correct?)? Please explain me sir.
bhagwaan ko pranam.kya padhate ho sir aap,thanku sir!!
GREAT EXPLANATION SIR
KEEP IT UP SIR
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Jai Hind, Vande Mataram?
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Hameshs Khush Rahiye
Bhagwan Singh Vishwakarma
Sir plzz make video on Lin Bairestows Method also
Sir if we do upto 3rd approx. Root we get x2 = 0.347295 & x3 = 0.347296. So the required ans is 0.347296.
U are my online teacher i love u
sir y cant we start with x0=0 or 1? eventually v r drawing tangents to f(xn) and no matter where f(xn) lies on the curve, the tangent drawn to f(xn) will cut x axis near to the real root. and applying this same formula we will get closer and closer to the real root.
Very helpful dear गुरु जी
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sir instead of taking 0.5 , you should have started the equation from 1.5 , because the true root lies between 1 and 2. hence the value of x=1.5320 . you can confirm this value of x is correct by inserting this value of x in equation , and the answer will be 0.
accurate value of x = 1.53208886
you are amazing sir your lectures are magnificent to any students of engineering
f’(x)= 3x^2-3 kaise huwa ….can you explain ???pls…
Sir you are a great teacher sir👍 nice explanation
Very good and fruitfull lectures sir ji..
God give u more grace...
Thanks sir aapne meri confusion dur kr di
sir if we find the value of xo (means neartest value to our root ) , than we can also find our root by same method as we find xo, so why we used this newton raphson method or others method such as bi-section etc
thanks sir I understand by watching one times.
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जय हिन्द, वन्दे मातरम्
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Jai Hind, Vande Mataram?
Hello sir, What we need to do when our function is trignometric? should we use any integer value as our intial guess or we need to take radian angle as our intial guess? Your videos are really good. Kindly request you to answer.
Maja aa gya sir best ever taught 😍
f’(x)= 3x^2-3 kaise huwa ….can you explain ???pls…
Nice video..sir
you are doing mind blowing sir
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मिलते हे अगली Video
JaiHind, VandyMatrem
love you sir your efforts are marvellous god bless you
Thank you for your comments.
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Jai Hind; Vandey Matrem
Nice explanation 👌👌👌👌👌👌👌👌👌👌👌
Thanks sir
nice explanation of the method.
Thank u very much for ur hard work sir🙂
Sir you are such a great nice explanation 😊
Badiya pdate h sir ap👏👏happy teachers day sir g
Ek dam mast pdate ho aap sir g
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Jai Hind, Vande Mataram?
Thanks alot sirr...... It's completely understandable❤
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Jai Hind, Vande Mataram?
Thanks sir mere problem ka solution dene k liye thanks again
Awesome lectures
very very good job