Thanks, very informative! But I wanna ask if r = {(1,1), (2,2), (3,3), (4,4)} considered symmetric? if yes, please explain because I can't wrap my head around it
damn i was about to fail the class agter watching your video i am the one who wish to get A on the exam damn what a transition..You really explain good..
Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!
No you cannot because , Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!
Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) for a
Not necessary, if some elements in a set are {a,a} and some are {a,b}, then its not reflective as {a,b} exists but it isn't irreflective either since {a,a} exists. It has to be all elements following the requirement.
Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!
Let me explain you, Antisymmetric = { (1,1) , (1,2) , (2,3) } Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed Assymetric = { (1,2) , (2,3) , (3,1) } Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!
No you cannot because , Consider a relation R = { (1,1) , (1,2) , (3,1) , (1,3) } Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and Hence, Antisymmetric is not always equal to (not symmetric) I hope you got it!
From Nigeria, FUTA, this tutorial and that of Algorithm saved a whole faculty😅😅. Nice one really!!!
😂😂 we gather Dey
He's Indian
same LASU
Much more short and straighforward explanation. Appreciated🌸
Gm
Your voice is so soothing 💝 and teaching is very very good 👍🏻😊
Concise and to the point. Thanks
Your video is best one for relation examination
Clear and easy to understand . thanks sir
SAVED MY LIFEEEEEEEEEEEEEEEEEEEEE
Century complete re baba
Thanks neso academy and specially Jaspreet sir 🙏
thank you so much for these videos, i should have skipped my 2 hour long professor lecture where i understood nothing and just watched this instead
FR
Thanks sir , your way of explaining is fantastic
You have just ruined professor's one hour lecture in 6 minutes
*2 hour
*5 hours
whole semester
Whole career
Whole life😂
Thank u, ur saving my college life
This is very helpful
yours vedios are well explained,, so please give vedios for functions in maths
When you say "as simple as that", it hits me lol🤣, doubting if i am supposed to be that intelligent in first go 😇
Thanks, very informative! But I wanna ask if r = {(1,1), (2,2), (3,3), (4,4)} considered symmetric? if yes, please explain because I can't wrap my head around it
Yes it i s symmetry
damn i was about to fail the class agter watching your video i am the one who wish to get A on the exam damn what a transition..You really explain good..
Much needed video 🎉
Great 👍
4:06 ....... Why we need not to check for (1, 1), (2, 2)
(1,1) is relexive of(1,1) simillarly for (2,2)
thank you!!!!
Character In the video It's great, I like it a lot $$
Super smooth
Very good explanation 😊
Thanks
really nice sir thank you
Thanks bro
Bro tysm
Sir please upload videos on DBMS
So a=b means it is not symmetric but anti symmetric?
Holy shit I love you. My brain finally understands symmetric vs antisymmetric
Hi I am not understanding the example on Antisymmetric, shouldn't it be that THAT example is NOT Antisymmetric?
The first ex given for irreflexive relation is not irreflexive but is it reflexive or not
This helped me alot. Thank You~
Is there any relation which is not reflexive, not irreflexive and not antisymmetric
Topic explaination is very good
explained it better than my prof lol 10/10
Sir please upload more videos. They are helping me too much
Great work appreciated
question: why isn't there (1;3)??
Because if we change 1,1 and2,2 answer is 1,1and2,2
omg bro ur so smart
blud will def clear iit
bro is smarter than einstein himself
16 missed calls from harvard
Data structures...
Please upload and complete DS Course.
How is anti-symmetric different from non-symmetric?
Consider a relation
R = { (1,1) , (1,2) , (3,1) , (1,3) }
Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric
However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and
Hence,
Antisymmetric is not always equal to (not symmetric)
I hope you got it!
Itna acha itna smoothly 👌
Thank you for the video
Sir can I conclude that antisymmetric is equal to not symmetric
No you cannot because ,
Consider a relation
R = { (1,1) , (1,2) , (3,1) , (1,3) }
Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric
However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and
Hence,
Antisymmetric is not always equal to (not symmetric)
I hope you got it!
Hats off
good so good👍👍👍🍀
Tomorrow is my paper and i complete whole syllabus in just 6 min video🤣
Love you sir
God bless you🎉🎉🎉
Excellent
Thank you so much sir.
Thanku so much sir
Very helpful sir thank you sm
Plz regularly upload videos on DBMS series ✌️✌️🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Do u mean dms?
@@drg9807 Database management system is a engineering sub
You're gods
"gods" 💀
I am from India
Thank you so much sir ❣️❣️☺️💗
Sir what happened to the gate aptitude series ? plzz sir upload the continuation videos
👍🏻
❤
“Let me tell you”❤
When will part 2 be released?
Antisymmetric?
never heard of that when i was studying PU i thought the last one was Transitive relations
Let me explain you,
Antisymmetric = { (1,1) , (1,2) , (2,3) }
Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed
Assymetric = { (1,2) , (2,3) , (3,1) }
Here if (a,b) exists then (b,a) is not allowed, also (a,a) for a
This explanation is illogical. How is something irreflexive because the numbers are not in the set when they are clearly in the set?
Please start teaching CO SUBJECT as soon as possible
Sir PLz...thora jldi videos Upload kia krein
hmara uni waly sir achy nhi hain.....ham aap se idhr hi parhaty hain..
Oke)
❤❤
Dbms and ds pls
DBMS
if a relation is not irreflective .is reflective????
Not necessary, if some elements in a set are {a,a} and some are {a,b}, then its not reflective as {a,b} exists but it isn't irreflective either since {a,a} exists. It has to be all elements following the requirement.
Same here plzz complete data structure playlist....🙏🙏🙏🙏
My brain is not braining
Tomorrow is the test and I'm studying tonight ,🤫🤫🤫🤫
Yesterday was my test I'm studying today 🤫🤫🤫🤫
Yor boss
awesome
i haven't understand which you have explained its not clearly explain
Let me explain you,
Antisymmetric = { (1,1) , (1,2) , (2,3) }
Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed
Assymetric = { (1,2) , (2,3) , (3,1) }
Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed
Consider a relation
R = { (1,1) , (1,2) , (3,1) , (1,3) }
Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric
However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and
Hence,
Antisymmetric is not always equal to (not symmetric)
I hope you got it!
Arigato gozaimasu sensei
2:10
Nice
anti symmetric is not clearly explained makes no sense or logic
Let me explain you,
Antisymmetric = { (1,1) , (1,2) , (2,3) }
Here if 1,2 ( say a,b ) exists then 2,1 ( that is b,a ) is not allowed , however if 1,1 ( say a,a ) exists then 1,1 ( agai a,a ) is allowed
Assymetric = { (1,2) , (2,3) , (3,1) }
Here if (a,b) exists then (b,a) is not allowed, also (a,a) is not allowed
Consider a relation
R = { (1,1) , (1,2) , (3,1) , (1,3) }
Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric
However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and
Hence,
Antisymmetric is not always equal to (not symmetric)
I hope you got it!
Bhai hindi me smjhi diya kro yl
you shouldve had images to represent the relations in this video. all the formal notation is brain melting. no thanks
So fast
Bro said ir🔫🔫🔫reflexive
Sir hindi me asani hoti😢😢
Lekhin Hindi asan nahi hoti 😅
👍👍👍👍
it is super fast for me 😭😭
خخخخخخخخخ انت بتقول اي
You talk too fast
So a=b means it is not symmetric but anti symmetric?
No you cannot because ,
Consider a relation
R = { (1,1) , (1,2) , (3,1) , (1,3) }
Here R is not symmetric because ,R is symmetric if there exists a,b then there should be b,a since R contains 1,2 but not 2,1 R is not symmetric
However , R is also not Antisymmetric because , R is Antisymmetric if it contains a,b but not b,a ( note : it can have a,a as an ordered pair ) since in our example there exists 3,1 as well 1,3 which is not allowed in antisymmetric relation and
Hence,
Antisymmetric is not always equal to (not symmetric)
I hope you got it!
Thank you sir
Character In the video It's great, I like it a lot $$
❤
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