Electric Fields - A Level Physics

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  • Опубліковано 28 гру 2024

КОМЕНТАРІ • 146

  • @lunatic6320
    @lunatic6320 4 роки тому +83

    Damn he knew we all would need this one day.legend.
    (8 years ago. Just wow )

    • @russellfiscian9911
      @russellfiscian9911 3 роки тому

      😂😂😂😂

    • @Clert77723
      @Clert77723 2 роки тому +2

      its been a whole decade now
      mans still helping a lvl students all over

  • @ewanjk
    @ewanjk 9 років тому +77

    do you have small writing or a long sheet of paper?

  • @DrPhysicsA
    @DrPhysicsA  11 років тому +4

    Each playlist contains videos in the order in which I think they can be best and most logically viewed if you want to view the complete set. Alternatively you can select a particular video, although in some cases I may make mention of information derived in another video. In most cases these will be earlier videos in the playlist but occasionally I cross refer to other videos elsewhere on the channel, to avoid too much duplication of material.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому +3

    Thanks for kind comments. There are videos on Capacitors and Dielectrics in the Electricity & Magnetism playlist. Hope they help.

  • @moussaabmasskouri5796
    @moussaabmasskouri5796 8 років тому +56

    In the last part of the video (The Potential energy), it's not over the distance squared, it's only over the distance !!

    • @abdullahisamantar
      @abdullahisamantar 5 років тому +3

      I was wondering about the same thing.

    • @fredy749
      @fredy749 4 роки тому +1

      Same thing. Obviously we are human so it is mistaken, it is divided by sqr(separation).

    • @YesIlikebananasSo
      @YesIlikebananasSo 3 роки тому

      @@fredy749 not at all the same thing

    • @AllanLovezGaming
      @AllanLovezGaming 3 роки тому +2

      @@YesIlikebananasSo bruh.. they're referencing to them thinking the "same thing".

    • @mesmerizingindulgent8924
      @mesmerizingindulgent8924 2 роки тому

      Right as par the derivation ✅

  • @DrPhysicsA
    @DrPhysicsA  12 років тому +2

    I'll explain in more detail in next vid on Maxwell's equations. But in essence E = Q/4π r2 ε. V is defined as electric potential energy per unit charge = Force x distance / charge. Force = Qq/4π r2 ε. So V = Q/4π r ε. Do E = V/r (or V/d if you use d instead of r). So E can be measured either in units of newtons per coulomb or volts per metre.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому +3

    In the Coulomb force equation (F=Q1Q2/4 pi E r^2) one of the Qs will be the test charge q, so that is the one that is divided. The other one is the substantial charge.

  • @alpha.m5483
    @alpha.m5483 7 років тому +12

    The myth, the legend, the prodigal son : DrPhysicsA

  • @DrPhysicsA
    @DrPhysicsA  12 років тому +4

    Thanks. I had spotted this. I had put an annotation on the video to make the correction.

  • @DrPhysicsA
    @DrPhysicsA  12 років тому +2

    Well spotted. Thanks. I have added an annotation to make the correction.

  • @DrPhysicsA
    @DrPhysicsA  12 років тому

    At 6:50 the E at the top of the screen is the Electric Field strength = F/q. The E at the bottom of the screen is Electric Potential energy. Energy = force x distance = Fr. So Electric PE is Qq/4 pi ε r2 x r = Qq/4 pi ε r

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    This is the essence of scientific method. Scientists observe the real world and then attempt to account for it both in terms of explaining what is happening and, where possible, assigning a mathematical representation. The key to all theory is that it must fully and accurately describe what we already know and forecast something else that can be tested by experiment. If the experiment agrees with the theory, then the theory can be developed. If not it must be changed.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    Not sure what you mean by EM force field. There are electric fields & magnetic fields. A charged particle in an E field and a moving charged particle in a B field (or a moving B field) will experience a force. So the field is really the potential to exert a Force if there is something in that field on which a force can be applied. eg the electric field has no impact on a neutron. There is electromagnetic radiation which consists of a travelling electric field with associated mag field.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    When you have 2 particles of the same charge and move one from infinity to a distance r from the other, then the potential at point r equals the work done in bringing the charge from infinity to r. In the case of opposite charges, at infinity the PE=0. As you bring the charge from infinity to r it has the capacity to do work. Work is integral of force x dist eval from infinity to r. F=kQq/r^2. Integral=-kQq/r. PE is negative. PE decreases as r decreases. Similar to gravitational PE.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    It covers material in the AQA, OCR and Edexcel syllabus and I have also added some material from the CIE syllabus. I cant guarantee that it covers everything. If anyone spots gaps, let me know and I'll try to add more videos to cover them.

  • @DrPhysicsA
    @DrPhysicsA  12 років тому +2

    I'll have a go, but meanwhile are you aware of the excellent video lectures by Prof Walter Lewin on Electricity and Magnetism made by MIT which, among other things, derive Maxwell's equations.

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    r is indeed the complete distance. It does not stand for radius. It is simply a distance parameter. So when F=q1 q2/ 4 pi epsilon r^2 then r is the total distance between q1 and q2.

  • @DrPhysicsA
    @DrPhysicsA  12 років тому +3

    Thanks for comment. The link to the full playlist of my A Level Physics Revision Videos is now in the description.

  • @DrPhysicsA
    @DrPhysicsA  12 років тому

    Try "Classical Mechanics - A Level Physics" in the A level Playlist on my main page.

  • @beattoedtli1040
    @beattoedtli1040 6 років тому +7

    Potential is ~1/r, NOT 1/r^2

  • @DrPhysicsA
    @DrPhysicsA  12 років тому

    No because the formula is calculating the difference in potential energy between being an infinite distance away from Q (PE=0) and a distance r away from Q.

  • @markgromala5900
    @markgromala5900 11 років тому +1

    Are the Q's interchangeable? I am referring to the point at around 5:30 where you quickly explain that you can cancel out one of the capital Q's with a small q. I always have problems with the mathematics rather than the concepts and am not sure if I just misunderstood what you were trying to explain. Thanks

  • @letsdoit236
    @letsdoit236 9 років тому +1

    i am from morocco, we study in frensh, but i understand much better with your videos even they are in english,, thank u sir,, you'r doing very well

  • @rainbowrose675
    @rainbowrose675 9 років тому +17

    Sir, can you please explain the difference and relation between electric potential and potential difference

    • @DrPhysicsA
      @DrPhysicsA  9 років тому +26

      +Rainbow Rose The electric potential is defined as the work done by an electric field in carrying a unit positive charge from infinity to that point. Potential difference is just the difference between the electric potentials at different points.

    • @mesmerizingindulgent8924
      @mesmerizingindulgent8924 2 роки тому

      Well it's pretty easy to tell as the word difference suggests

  • @DrPhysicsA
    @DrPhysicsA  12 років тому

    Since electric flux is the amount of the electric field passing through a particular area (window), the net electric flux will be zero if the amount of the electric field passing out the window is the same as that passing in.

  • @Joebingley15
    @Joebingley15 10 років тому +2

    Electric field stength is the force per unit positive charge.

  • @ANSIcode
    @ANSIcode 11 років тому

    I understand that the term 1/r describing the potential energy can be derived by integrating the force from "infinity" to the distance r. However, I somehow completely fail to see why that should be equal to the potential energy at that point in the case of attraction, since in that case the distance from infinity to r has nothing to do with the distance where the force is aplied. Also the integration gives the term -1/r, allowing "Ekin+Epot=0", which is not explained here.

  • @the_golden_one4733
    @the_golden_one4733 8 років тому +1

    Are electric fields diverted towards conductors like copper wire in a circuit?

  • @toxcipher795
    @toxcipher795 12 років тому +1

    I admire Dr physicsA youtube channel ! I have a suggestion : Why don't yo do lectures on Algorithms and theoretical computer science ?

  • @peterb9481
    @peterb9481 5 років тому

    The 4piEo with respect to charge is a constant in which case CQq similar to gravity of GMm for the formulas at the end. One questions if dark energy is a kind of inverse gravity, in which case it may be possible to shield oneself from it. Further if positive fields go out and negative in - is this just as we have chosen to look at it I.e. inverting the negative could be viewed as out and positive in??

  • @TheGoldenEagles100
    @TheGoldenEagles100 7 років тому +5

    At the very end when you said that the difference in PE GMm(1/r1^2 -- 1/r2^2) for a gravitational field. Why is it "r^2" instead of it just being just "r"? And also why is it that for the PE of the electric field.

    • @pakhtun7639
      @pakhtun7639 7 років тому

      TheGoldenEagles100 dude its coz W=Fx..so F=Qq/4pi*r2 x r which cancels the r..so its left r

    • @ganweijun3976
      @ganweijun3976 7 років тому

      Can someone explain please

  • @hadeedahmad9465
    @hadeedahmad9465 5 років тому +2

    The man the myth the legend Dr physicsa. Can you make a vid on Thermometers and energy changes

  • @olivierlaurent1409
    @olivierlaurent1409 10 років тому +4

    Hello,
    At the end of your video, the potential energy must vary as 1/r instead of 1/r^2.
    Thanks

    • @DrPhysicsA
      @DrPhysicsA  10 років тому +4

      Yes. I did put an annotation on the video to clarify this but I understand that not everyone can see the annotation.

    • @olivierlaurent1409
      @olivierlaurent1409 10 років тому

      Hello,
      Thanks for your response. Yes, the annotation appears correctly on my PC.
      Indeed, I watched your video on my tablet with the youtube apps (and also the mobile version of youtube with Chrome) and unfortunatly the annotation does not appear (I've just checked).
      Nevertheless, by forcing to use the computeur mode with Chrome with my tablet, we can see the annotation.
      Thank you.

    • @zeyn4792
      @zeyn4792 6 років тому

      @@olivierlaurent1409, how did your exam go? This is 4 years later so i understand if you don't reply. Hope you're doing well

    • @buqbooQ
      @buqbooQ 3 роки тому

      @@zeyn4792 How did YOUR exam go ? 2 years later lmfao hope ur doing well tho

  • @yabi1384
    @yabi1384 11 років тому

    Hi drA , this is a question that a really need an answer ; how do scientists come up with these equation , why do they for example devide the Q1Q2 over the free space permitevity times 4pi ... or in the equation of gravity that newton came with where he devided by r^2 and multipled by G the gravitational constant ? Hope I get an answer thanks

  • @rainbowrose675
    @rainbowrose675 9 років тому +3

    Sir, the cambridge coursebook says that, potential V at a distance r from a charge Q = Q/(4*pi*epsilon not*r^2)
    Can you please explain why it is not r, according to your equation of V

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      +Rainbow Rose At what time on the video does this arise?

    • @xeryan2747
      @xeryan2747 9 років тому

      +Rainbow Rose i didnt get it

    • @xeryan2747
      @xeryan2747 9 років тому

      +Rainbow Rose he wrote Q/(4*pi*epsilon*r)

    • @tanzimahmed2886
      @tanzimahmed2886 9 років тому

      sir , I feel confusing about when it will be 'r' and when will it be 'r^2"

    • @samiareza8698
      @samiareza8698 8 років тому

      +Rainbow Rose There is a printing mistake in the book
      DrPhysicsA is correct

  • @leonellg3167
    @leonellg3167 7 років тому

    For electric potential energy, since it is defined as 0 from a main charge Q. If the force between the charges is attractive then does that mean that as little q is moved closer it loses electric potential energy?

  • @LivesHereSusie
    @LivesHereSusie 12 років тому

    Link the other videos in the description please, Thanks for making these videos, I was having huge trouble understanding fields.

  • @dr.dipendrakandel
    @dr.dipendrakandel 11 років тому +1

    Thank you very much for the video. I learnt much more about electric filed than my physics taught in whole month. And please upload video about capacitor too. like capacitance,spherical capacitor,parallel plate capacitor,its principle,combination of capacitors, energy stored in charged capacitor,energy density,loss of energy in joining capacitors,charging and discharging of capacitors. And also about the dielectrics. Thank you very much.

  • @AeonFlexMusic
    @AeonFlexMusic 11 років тому

    what can the actual force of an electric field do when compared to an electromagnetic force field?

  • @Haokennxt
    @Haokennxt 12 років тому

    Feedback: last seconds before the video end:
    Change in Electric Potential Energy = Charge x (potential change) .....
    (1/r2 - 1/r1) instead of (1/r1 {squared - 1/r2 {squared}}) as potential proportional to 1/r and with negative sign.

  • @Matthewsgirl000
    @Matthewsgirl000 6 років тому

    This guy's enthusiasm is amazing. Thumbs up from me !! 😄

  • @ANSIcode
    @ANSIcode 11 років тому

    I don't understand why with opposite charges the potential energy has to be derived from the work done in bringing something in from infinity.
    When the charges are let go, the potential energy will convert to kinetic energy, while the charges accelerate towards each other. Why (I know the formula is wrong) is the kinetic energy not equal to the integral of the force from 0 to r, since that should be the work done in bringing the charge there from a state where PE=0?

  • @niharikarajanala9454
    @niharikarajanala9454 Рік тому

    Can you explain potential energy when the test charge is -ve instead of +ve?

  • @rojafx
    @rojafx 9 років тому

    at 5:28 you gave the definition of electric potential as electric potential energy

  • @alphie10
    @alphie10 12 років тому

    have you got videos on momentum laws? conservation of momentum and kinetic energies?

  • @abcxyz518
    @abcxyz518 9 років тому +2

    Hi isn't the potential energy supposed to be inversely proportional to r rather than r^2? However at the end of the video while comparing the similarities between the change in pe for g field and e field it seems to reflect otherwise. Correct me if i'm right and thanks for your videos!

    • @abcxyz518
      @abcxyz518 9 років тому

      Correct me if i'm wrong*

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      +abcxyz518 At what time on the video does this arise?

    • @aeroscience9834
      @aeroscience9834 8 років тому

      +DrPhysicsA 16:00

    • @water5210
      @water5210 3 роки тому +1

      @@aeroscience9834 Mans left you hanging for 5 years lmao

  • @jhasllanmartins5484
    @jhasllanmartins5484 9 років тому

    If I have 3 densities of charges, and when I add them up if I get a negative result, when I calculate the electric field between plates using E= sigma/2episilon 0, will the electric field be negative?

  • @ghassemi10
    @ghassemi10 11 років тому

    Hello,
    could you explaine the diffrent advantages of (or between) electics fields and maghnetic fildes in practice.

  • @ZazzlesGS
    @ZazzlesGS 6 років тому

    This video is great and very informative. The only bit that confused me was when you used the notation of 'E' for potential energy, when E is already used the state electric field strength. After it was corrected it was fine but before I couldn't see where any of the equations were coming from. Maybe try using 'W' instead :)

  • @YoSoFuny
    @YoSoFuny 12 років тому

    Thanks so much, it's much easier when I can rewind it and when it is laid out properly.

  • @tJiNpolitics
    @tJiNpolitics 12 років тому

    then shouldnt the r be from q to the middle dot as that is the distance travelled ?

  • @xXxBladeStormxXx
    @xXxBladeStormxXx 11 років тому

    Could you please arrange the video's in the playlists in order in which they are meant to be viewed? I tried follow the present order but then you keep telling to view the "other video" :(
    Sorry for the rant but would be much helpful to many people if the videos were in order.

  • @EmadTAudi
    @EmadTAudi 12 років тому

    Its all wonderful ,Thank you very much, but what about Practical physics? particle detection, How to investigate the decay curves for capacitor circuits are exponential . and such things

  • @samuelj5890
    @samuelj5890 7 років тому

    You, my friend, are a fucking lifesaver.

  • @myvideosarefine
    @myvideosarefine 3 роки тому

    I like the classic and simple way of explanation. With due respect there are minor technical mistakes in the video.

  • @styno2010
    @styno2010 9 років тому +1

    You are the best teacher... Thanks

  • @viks22
    @viks22 12 років тому +1

    best explanation of electric fields thank you

  • @tonystark9960
    @tonystark9960 6 років тому

    at 6:5 9 why do we take r and not r^2?

  • @DrPhysicsA
    @DrPhysicsA  11 років тому

    You might find my video on electromagnetism helpful.

  • @abdulmoizbutt5546
    @abdulmoizbutt5546 5 років тому

    The gravitational potential enger is GMM(1/r2 - 1/r1) its not squared

  • @xyz39r1abc
    @xyz39r1abc 11 років тому

    Doctor how do we derive did the rule of electric potential energy ( Q/4Pi€ r )

  • @MikeRoePhonicsMusic
    @MikeRoePhonicsMusic 11 років тому

    Is 4pi used because the field is moving either outward from a point or inward towards a point in all directions (spherically?) I get confused as to why sometimes pi is used in equations, but other times it's 2pi, 4pi, etc. Is there some underlying principle to tell you what to multiple pi by under a given context?
    Thanks for these videos. They are very good!!

  • @danielsegura9127
    @danielsegura9127 10 років тому +1

    made everything so clear

  • @andreasdc1
    @andreasdc1 12 років тому

    at 6:50 why r and not r^2 ???

  • @777Dunkelheit666
    @777Dunkelheit666 10 років тому

    from wich book you get all this?

  • @AJpennster
    @AJpennster 10 років тому

    Shouldnt V be the electric potential difference between two positions in an electric field?

    • @DrPhysicsA
      @DrPhysicsA  10 років тому

      Yes. Any potential is always given in terms of a potential difference with respect to some other point

    • @AJpennster
      @AJpennster 10 років тому +1

      So when you say voltage in this video, you know without the potential difference, what are you referring to? That point potential compared with 0(infinity)?

  • @fablife55
    @fablife55 12 років тому

    How do you get E = V/d ?!

  • @AA-iu3lb
    @AA-iu3lb 10 років тому

    hello
    can you make a video on as level electric current and DC circuits

    • @DrPhysicsA
      @DrPhysicsA  10 років тому +3

      That material should be in the A-level physics revision playlist.

  • @fenerbahce262
    @fenerbahce262 11 років тому

    Is this for OCR A Physics please respond asap!!!

  • @ahmedismail6916
    @ahmedismail6916 5 років тому

    Man, you're godsend!

  • @yabi1384
    @yabi1384 11 років тому

    thanks Drphysics you are really awesome !

  • @AeonFlexMusic
    @AeonFlexMusic 11 років тому

    ahh ok thank you, i was equating e/b field strength with the kind of force you would experience due to gravity, but i didn't take into account the necessary charges. Let's say that I put a shirt on with 10^10000000000 negative charges and stood in front of a large positively charged metal plate, In my mind I thought the force of the interaction could A. Pull the metal plate towards me, or B.See a rather large electric charge jump off of the plate into my chest haha

  • @fablife55
    @fablife55 12 років тому

    When is net electric flux zero?

  • @samuelsmith921
    @samuelsmith921 11 років тому +1

    Am i right in saying that actually the minus charges move toward to positive?
    Because i am getting really confused now, i was okay with simple electricity being reversed but now it makes no sense... :(

  • @adn17
    @adn17 11 років тому

    You are the best sir! :)
    Thank you

  • @checkywilson
    @checkywilson 8 років тому

    Sir, is there any convention to using Q or q as charge?

  • @tJiNpolitics
    @tJiNpolitics 12 років тому

    thanks bro. R u by any chance related to the show Dr. Who ? lol

  • @fablife55
    @fablife55 12 років тому

    Okay i get it.. thank you :)
    your videos help me out soo much

  • @hamzadanial5892
    @hamzadanial5892 5 років тому +1

    Is this relevant to AS

  • @andreasdc1
    @andreasdc1 12 років тому

    thank god i found you , you are my life saver ;p

  • @liamhughes70
    @liamhughes70 9 років тому

    Isnt K 8.99x10^9??

    • @DrPhysicsA
      @DrPhysicsA  9 років тому

      +Liam Hughes What value did I give? And at what time on the video?

  • @hiraahmed4263
    @hiraahmed4263 12 років тому

    You're Awesome! Thank You! Would greatly appreciate if you make videos on Maxwell's Equations as well! :-)

  • @xyz39r1abc
    @xyz39r1abc 11 років тому

    Geshbeddin , the man is a very good instructor , if you don't like his vedios then don't watch it ,

  • @teezo3afana
    @teezo3afana 11 років тому +1

    IM gonna fucking fail tomorrow

  • @axvxiii
    @axvxiii 4 роки тому

    Thank u💙💙💙💙

  • @MrArda96
    @MrArda96 11 років тому

    where can ı found electric field questions?

    • @DrPhysicsA
      @DrPhysicsA  11 років тому

      You may find some in my video at AS Physics Exam Question: Electricity

    • @MrArda96
      @MrArda96 11 років тому

      thankk youuuu !!

  • @andylee3450
    @andylee3450 10 років тому

    Thank you so much, appreciate your great effort!

  • @laureldavis8939
    @laureldavis8939 4 роки тому

    best video tysmmmmmm

  • @kiradownoumbeanderson3335
    @kiradownoumbeanderson3335 2 роки тому

    THANKS

  • @takmaps
    @takmaps 11 років тому

    thank you

  • @zaza92926
    @zaza92926 11 років тому

    you should have used Q and q to explained !

  • @paulinembopda5083
    @paulinembopda5083 2 роки тому

    Thanks

  • @benallia8262
    @benallia8262 8 років тому

    thank you sir, i finally understood fields

  • @durntok2293
    @durntok2293 8 років тому

    found this helpful ,thanks sir

  • @xeryan2747
    @xeryan2747 9 років тому

    thank you so much!

  • @rajtash
    @rajtash 11 років тому

    Even after watch this video ??

  • @llang01248
    @llang01248 11 років тому

    At an infinite distance from a field causing charge Q I have some ambiguity with regards to the Kinetic Energy of an unit positive charge - my understanding is that Etotal=Ek and it is hence maximum as the potential energy is converted to kinetic energy. However, I also understand that E is inversely proportional to r^2 so wouldn't that suggest that the charge decelerates and becomes stationary at infinity? Thank you in advance!

    • @DrPhysicsA
      @DrPhysicsA  11 років тому +2

      It depends on the signing convention. We usually say that when an object is at an infinite distance away then its potential energy is zero and its kinetic energy is zero. Since energy can be neither created nor destroyed the total energy at all points along the trajectory to infinity must also equal zero. Since it will have positive kinetic energy we therefore say that it has negative potential energy. But as I say, that is all just a matter of the signing convention.

  • @alpha.m5483
    @alpha.m5483 7 років тому +2

    Man can never be hot

  • @hamzabadyi4649
    @hamzabadyi4649 7 років тому

    thank you you are excellent

  • @thesuperproify
    @thesuperproify 8 років тому

    is this AS or A2 ?