At around 6 minutes you said dividing by .01 is the same as multiplying by 100, and gave the answer as 8.99e^7. If we multiply 8.99e^9 by 100, isn't it 8.99e^11? I appreciate you time and efforts thank you for all your videos, you are a great teacher!
in second example , by 11:40, how did u get that ans when i pressed it in my calculator i got 17980 and if we are to change it to standard form is 1.798 x 10^4
Hi Chad, I’m a student at ASU in Phy121, how relevant are these lessons to the curriculum. Your chem lessons were very helpful and I was hoping to use these as well for my class. Thank you.
They will help you 80-90% of the way. But being algebra-based, there will be a few areas where they will fall short lacking the calculus. But overall, you should still find them very helfpul!
Unfortunately, it won't work out. The angle provided in the problem was the angle with respect to the vertical (the y-axis). To use the convention that we use cosine to determine the x-component and sine the y-component, you have to have the angle with respect to the horizontal, the x-axis. Now you could have still used the 30 degree angle, but the x-component would have been the opposite side causing you to use the sine function and the opposite for the cosine function which would have yielded; Tsin30-mg=0 for x-component Tcos30-kq*2/r*2=0 for y-component Compare this to how I solved it in the video and you might realize it is an equivalent set of equations as sin30=cos60 and cos30=sin60 (the sine and cosine of complimentary angles are always equal). Hope this helps!
If i've a midterm exam,i will study till capacitance .. Will i rely on these videos for studying the lessons as a said , solve questions by myself and the proffesor's previous exams ?
Hey chad, my school is on trimesters so Im about 5 lessons ahead right now. Is it possile to see the videos that arent released yet somehow. You got me through orgo 1 & 2. Thank you
At around 6 minutes you said dividing by .01 is the same as multiplying by 100, and gave the answer as 8.99e^7. If we multiply 8.99e^9 by 100, isn't it 8.99e^11? I appreciate you time and efforts thank you for all your videos, you are a great teacher!
in second example , by 11:40, how did u get that ans when i pressed it in my calculator i got 17980 and if we are to change it to standard form is 1.798 x 10^4
He said to use absolute value for the negative charge, be sure to also square the radius. It will become 1E-12m^2 instead of 1E-6m. This is crucial.
Hi Chad,
I’m a student at ASU in Phy121, how relevant are these lessons to the curriculum. Your chem lessons were very helpful and I was hoping to use these as well for my class. Thank you.
They will help you 80-90% of the way. But being algebra-based, there will be a few areas where they will fall short lacking the calculus. But overall, you should still find them very helfpul!
Can it be done if I do it like this:
Tcos30-mg=0 for x-component
Tsin30-kq*2/r*2=0 for y-component?
Unfortunately, it won't work out. The angle provided in the problem was the angle with respect to the vertical (the y-axis). To use the convention that we use cosine to determine the x-component and sine the y-component, you have to have the angle with respect to the horizontal, the x-axis.
Now you could have still used the 30 degree angle, but the x-component would have been the opposite side causing you to use the sine function and the opposite for the cosine function which would have yielded;
Tsin30-mg=0 for x-component
Tcos30-kq*2/r*2=0 for y-component
Compare this to how I solved it in the video and you might realize it is an equivalent set of equations as sin30=cos60 and cos30=sin60 (the sine and cosine of complimentary angles are always equal).
Hope this helps!
I didn't know about this relationship between complementary angles, thank you.@@ChadsPrep
If i've a midterm exam,i will study till capacitance .. Will i rely on these videos for studying the lessons as a said , solve questions by myself and the proffesor's previous exams ?
Also isnt the first example 8.99x10^11
(8.99x10^9)(2x10^-6)(1x10^-6)/(1x10^-6)^2 = 1.798x10^10.... this one?
@@ChadsPrep Yea, i was trippin my b
This is what I got too
I'm so confused how you got 8.99x10^7 instead of 8.99x10^11 for the first problem?
Fr, please Chad let us know how you got this! I am praying I did it right, without calculator for MCAT LOL please tell me I did it right!!
same!
Hey chad, my school is on trimesters so Im about 5 lessons ahead right now. Is it possile to see the videos that arent released yet somehow. You got me through orgo 1 & 2. Thank you
Shoot me an email: chad@chadsprep.com
gigachad
Happy Studying!
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