Deduce Optical Activity of Meso Compound

Let's compare these 2 compounds (A and B) and deduce which is optically inactive.
Each compound contains 2 chiral carbons.
A chiral carbon is a saturated sp3 hybridised carbon bonded to 4 different groups.
The mirror images of a compound with chiral carbon are non-superimposable hence they are isomers of each other.
We call these optical isomers or enantiomers.
To learn more about optical isomerism and other types of stereoisomerism, check out this video lesson:
chemistryguru....
What is interesting about compounds A and B is each chiral carbon is bonded to the same 4 groups:
bromine
hydrogen
ethyl group CH2CH3
the other chiral carbon
This means some of the optical isomers will have mirror symmetry which will cancel its optical activity.
In order to visualise and compare the chiral carbons better, let's apply the following transformations.
1. Convert ethyl group CH2CH3 to Et
The long carbon chain is distracting and since both carbons in ethyl group are non-chiral, we can just replace CH2CH3 with Et without affecting the stereochemistry of the compound.
2. Rotate compound slightly
It will be easier to compare the compounds if the C-C bond for both chiral carbons is horizontal.
So let's rotate the compound slightly.
3. Rotate C-C bond by 180 degrees
We want both ethyl groups to point down to find the mirror plane easily so let's rotate the C-C bond by 180 degrees.
Notice the orientation of Br group will change due to this rotation:
Br pointing towards you before rotation will be pointing away from you after rotation
Br pointing away from you before rotation will be pointing towards you after rotation
4. Find mirror plane
We can now compare the 2 compounds.
Compound A has no mirror plane so it will still be asymmetrical and optically active.
Compound B has a mirror plane between both chiral carbons.
The optical activities of both chiral carbons will cancel out.
Therefore compound B will be optically inactive.
Compound B is an example of a meso compound, where chiral carbons are present but the compound is optically inactive due to a mirror plane within the compound.
Topic: Intro to Organic Chemistry, Organic Chemistry, A Level Chemistry, Singapore
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[@jiayiping2717]

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[@ChemistryGuru]

Hi Jiayi for O level chemistry video lessons please check out I Can Do Chemistry Channel at ua-cam.com/channels/ByA9yDJQzcxtDCFbnglTWw.html

[@jiayiping2717]

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[@ChemistryGuru]

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