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good work brother... keep doing this... simple questions yet effective
Thank you, I will
I love your content bro what are you studying??
Nothing 😁Thanks!
Great work sir !
Thank you!
Nice!
Thanks!
👍
Just to confuse the issue logx is also used to represent natural logs in many places in Europe.
Can you prove that not expresding 3/2 as complex number still cover all possiple answe?
4.75 < x < 5
χ=ln7/(ln3-ln2)
Here it is with grouping symbols: x = ln(7)/[ln(3) - ln(2)]
X=ln 7/(ln 3-ln 2)
(3/2) ^x = 1 + 2 + 2^2 x = lg (7) /( lg(3/2)) Herein lg(z) designates log(z) to the base 2Hereby x = lg(7) /( lg(3) - 1)
x= ln7/ln(3/2)
Why did you took the pain of going to the complex calculation when you are not gonna use the complex solution? When do we really use the complex solution as an answer?
For fun, maybe! 😁
In electrical engineering Impedance(Z) is a complex value.
x=ln(1/7) / ln(2/3)
If 1/7 and 2/3 are supposed to be the arguments, then they must be inside grouping symbols.
@@forcelifeforce Fair enough, I've put the parentheses. It is a problem of expressing oneself mathematically in one line
good work brother... keep doing this... simple questions yet effective
Thank you, I will
I love your content bro what are you studying??
Nothing 😁
Thanks!
Great work sir !
Thank you!
Nice!
Thanks!
👍
Just to confuse the issue logx is also used to represent natural logs in many places in Europe.
Can you prove that not expresding 3/2 as complex number still cover all possiple answe?
4.75 < x < 5
χ=ln7/(ln3-ln2)
Here it is with grouping symbols: x = ln(7)/[ln(3) - ln(2)]
X=ln 7/(ln 3-ln 2)
(3/2) ^x = 1 + 2 + 2^2
x = lg (7) /( lg(3/2))
Herein
lg(z) designates log(z) to the base 2
Hereby x = lg(7) /( lg(3) - 1)
x= ln7/ln(3/2)
Why did you took the pain of going to the complex calculation when you are not gonna use the complex solution? When do we really use the complex solution as an answer?
For fun, maybe! 😁
In electrical engineering Impedance(Z) is a complex value.
x=ln(1/7) / ln(2/3)
If 1/7 and 2/3 are supposed to be the arguments, then they must be inside grouping symbols.
@@forcelifeforce Fair enough, I've put the parentheses. It is a problem of expressing oneself mathematically in one line