Runge kutta method second order differential equation simple example(PART-1)
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- Опубліковано 19 жов 2024
- In this video explaining second order differential equation Runge kutta method. This method is very simple and easy steps. The Runge-Kutta method is a numerical method used to approximate the solution of a first-order ordinary differential equation (ODE) given an initial condition. The second-order Runge-Kutta method also known as the midpoint method is a commonly used variation of the Runge-Kutta method that is particularly useful for solving second-order differential equations.
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The video was very informative. One thing, there is a little mistake, while deriving g(x,y,z), both the terms with 1 are positive.
its the first time that i give an indian a like ....thx alot for the clear steps
Bro i have a small dout, in this g(x) dz/dx=1+2xy+x^2z
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Yes that should be “+ve”..
Yes
Ultimate video
Thank you for explaination
Only mistake is, there will be +ve sign in g(x,y,z)
Nicely explained thanks a lot. It just cleared this complex topic into easy one 🙂🙂
Most welcome 😊
Sir, why did you add minus on the second equation (dz/dx=all positive)? And why you multiply h two times on the K equation?
why we consider only k terms to the ultimate solution? why not both the k and l terms? please someone kindly clear this topic.
Thank you so much. But i have one doubt. Why are we not calculating L it similar like k. If we dont need L then why are we doing till end
Thankful sir ,amezing video
Most welcome
thanks to you I get to answer our final project
there is amistake in geq. g but your explanation is perfect. Thanks a lot bro
Dear sir, Is it necessary to calculate l4? what it is use for?
Hello friend, l4 is used in case we would like to calculate over a range of x not just 0.1, it is used to calculate the new "z", just like the k's are used to calculate the new "y"
Can you tell me the book which contains this type of problems? btw nice explanation
Won't the 1 on the RHS of the given problem be considered in the function while computing for consecutive values?
Thanks, significantly helpful,great job
It helped a lot 👍 Thanks
thank u sir first subscriber
Thank you sir, you made this topic easy, subbed
Thanks sir, this helps me very much
Sir hw to solve 2a/r=1+cos thetha and 2a/r=1-cos thetha.....to show tht two lines intersect orthagonally....????
Divide both..
And prove theta equal to 90°
Sir how to do Runge Kutta for 2nd Order non-linear?
Thankyou for this video. 👍🏻
Sir can u do video on taylors series second order
Now better understand thank you so much 👍👍
You are welcome!
Very good thank you💫
can you please solve an example of two 2nd order coupled differential equation?
Thank you very much sir
(i) Solve the differential equation (dy)/(dx) = 2xy, y(0) = 1 by Rungekutta second
order method, where 0≤x≤1.
Sir can you solve this sum
Awesome thank you very much 😍
M3 total all modules upload sir with names and numbers of modules ❤️❤️
All modules uploaded
@@EASYMATHSEASYTRICKS in which play list sir only Laplace and 5th module is there sir
Why do we need to calculate L4?
I was also thinking same.
If you want to find y(0.2) you will need z(0.1). And the equation: z(0.1) = z0 + h/2 *[ L1 + 2*L2 + 2*L3 + L4 ]
L4 is the k4 equivalent for the second equation. He rewrites the second order differential equation into a system of two first order differential equations.
Helo brother after equating the terms each term will be positive there is no negative in the equation plz check it in text book..... page no.80 of author dr.KSC
Thanks so much
Thanks sir
Thanks a lot....the video helped a lot.
thanks a lot brother
good effort can i ask for your help??
Thank you
You're welcome
thank you very effective
Bhai ...gazab...tq bro
Sir solve more problem on module 2 or only 4 problem is sufficient and what about module 5 sir please reply for my comment please I depend on your videos only sir thank you so much for for ur effort sir 😍😍
ok
Sir I have a question regarding with 2nd order differential equation using 4th order Runge kutta method is there any way I can contact u?
What about the second iteration.
If you want to find y(0.2) you will need z(0.1). And the equation: z(0.1) = z0 + h/2 *[ L1 + 2*L2 + 2*L3 + L4 ]
@@ertugrul-bektik Thanks for the explaination.
Very nice
Thank you sir🙏
Thank you so much sir for this videos
By watching ur videos only I cleared my m1 andm4 in 1st attempt only
thank you
Tq u sir
ossum sir,,,very helpfull
y'(0.1) pani sodya bela k garne??
Since we have supposed
y'= dy/dx=z
Calc. Z(0.1)=z0+1÷6( l1+2*l2 + 2*l3+l4)
Thank u somuch sir
Thanks.
Tq sir I'll get esy tips from you
Sir plz do remaining prblms of module 2
ok
How to solve this with Second order equation....
What is the purpose of L4
If you want to find y(0.2) you will need z(0.1). And the equation: z(0.1) = z0 + h/2 *[ L1 + 2*L2 + 2*L3 + L4 ]
Please i request you to add Series of legendry polynomial derivation
i understood, thank you.
❤😊🙏
Correction for dz/dx = 1+x^2z + 2xy…
Thank you
Tq sir