I always avoided the polar equations,they seemed so messy but you explained them so easily that now I feel dumb for avoiding them. Thank you very much.
The theta axis is not defined as being counter clockwise from the radial axis. It points in the direction of increasing angle theta of the radial line. It can go either way depending on the problem.
fuck! you such hell damn nice teacher that even I can understand. Thanks man I completely got this problem. You are ma hero for the class of adv dynamics
If we use a polar coordinate system whose origin is either 1) moving with uniform velocity or 2) accelerating or 3) itself moving around another fixed point, can we use Newton's second law in the r hat and theta hat directions. I suspect we can still do so in case 1) but not if it's accelerating in 2) and 3). If not, how would we deal with such a system with an accelerating origin: I'm thinking something like a spinning ride which is itself on a spinning carousel. Hopefully you can comment on this. Thanks.
I'm not seeing how "delta Ur" is equal to ("delta theta" * "U sub theta") from your vector diagram (around the 1:30 mark). It looks more like it'd equal (U'r * sin of delta theta) to me. Perhaps someone can explain it to me?
Mel B as Ur is a unit vector thus the magnitude of it is equal to 1, and U theta is used as unit vector to show the direction so you can rewrite it as the videos shown.
I have an idea but i'm not that sure. As delta theta --> 0, you can consider that delta Ur as a small part of a circumference. Then, delta Ur (the arc) is perimeter*(delta theta)/(2*Pi), where perimeter is (2*Pi*radius), and radius = Ur = 1. Therefore, delta Ur is equal to delta theta
Very helpful, thank you.
This was helpful.. Thank you very much.
Great video, thanks!
I always avoided the polar equations,they seemed so messy but you explained them so easily that now I feel dumb for avoiding them. Thank you very much.
@Kepler 78b hi you still alive?
@@abdelrahmangaber3741 hi you still alive?
@@huissenm8752 no
hi you still alive?@@huissenm8752
Well done! Thanks!
great video thanks
The theta axis is not defined as being counter clockwise from the radial axis. It points in the direction of increasing angle theta of the radial line. It can go either way depending on the problem.
He is speaking in regards to the conventional definition.
fuck! you such hell damn nice teacher that even I can understand. Thanks man I completely got this problem. You are ma hero for the class of adv dynamics
If we use a polar coordinate system whose origin is either 1) moving with uniform velocity or 2) accelerating or 3) itself moving around another fixed point, can we use Newton's second law in the r hat and theta hat directions.
I suspect we can still do so in case 1) but not if it's accelerating in 2) and 3).
If not, how would we deal with such a system with an accelerating origin: I'm thinking something like a spinning ride which is itself on a spinning carousel.
Hopefully you can comment on this.
Thanks.
Gud job
I'm not seeing how "delta Ur" is equal to ("delta theta" * "U sub theta") from your vector diagram (around the 1:30 mark). It looks more like it'd equal (U'r * sin of delta theta) to me. Perhaps someone can explain it to me?
Mel B as Ur is a unit vector thus the magnitude of it is equal to 1, and U theta is used as unit vector to show the direction so you can rewrite it as the videos shown.
I have an idea but i'm not that sure. As delta theta --> 0, you can consider that delta Ur as a small part of a circumference. Then, delta Ur (the arc) is perimeter*(delta theta)/(2*Pi), where perimeter is (2*Pi*radius), and radius = Ur = 1. Therefore, delta Ur is equal to delta theta
This was helpful.. Thank you very much.