LTSpice Beginner To Expert Part 11: AC Analysis

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  • Опубліковано 6 гру 2022
  • In this simple tutorial we show you how to use the AC Analysis feature in the free electronics circuit simulator LTSpice to measure the frequency response of your circuit.
  • Наука та технологія

КОМЕНТАРІ • 7

  • @yacineayachiamor7336
    @yacineayachiamor7336 Рік тому

    I think this is the best way to explain the AC analysis and LTspice at the same time, Thank you for that, I really enjoyed the series!

  • @r.safakarici4686
    @r.safakarici4686 7 місяців тому

    Thank you very much for all videos. Please keep continue to adding new videos about electronic simulation in LTSpice.

  • @tmiller9099
    @tmiller9099 10 місяців тому

    Very informative. As a new amateur radio operator who is interested in designing and experimenting this is great information. I wish there was more tutorials on using LT Spice for HF circuit design as it is mentioned by amateur radio experimenters often but not really discussed in detail very much. Thank you again.

  • @heinzkreutziger2218
    @heinzkreutziger2218 9 місяців тому +1

    Hi, 6:18 I disagree that the AC analysis is a frequency response analysis. AC analysis rely on a small signal model, which have to be provided e.g. in the Spice models or sub circuits. I have had issues to get an AC analysis for a buck converter but with a FRA it works but it is time consuming due to several simulation runs in time domain. So FRA is not equal to AC analysis.

  • @WayneKnight_Rider
    @WayneKnight_Rider 11 місяців тому

    awesome vid, thx

  • @arunsebastian4035
    @arunsebastian4035 Рік тому

    Nice video

  • @markg1051
    @markg1051 4 місяці тому

    This seems very confusing to me in that you are claiming a gain of 20 dB for a passive RC circuit.
    These can only attenuate the input signal and therefore give a negative dB of gain.
    Is this actually how the LT spice is calculating the results in this example?
    If so it seems to be treating the source V1 as a gain stage of 20dB referred to a 1V,
    i.e. Gain = 20log(10/1) = 20dB.
    Normal way of looking at any voltage divider cct is to take the ratio of Vout/Vin as a cct gain and inverse, Vin/Vout as an attenuation.
    When calculating Gain where Vout = Vin (Unity gain) Gain = 20log*1 = 0dB.
    If however Vout is < Vin then as an example 20log (5/10) = -6.02dB.
    Can you please elaborate and explain why if this is not the case.
    PS I am enjoying your videos, 2 more to go in your play list to go.
    Cheers