Complex Numbers - Mod-Arg Form (3 of 5: Calculating the Modulus)

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  • Опубліковано 10 лис 2015
  • More resources available at www.misterwootube.com

КОМЕНТАРІ • 11

  • @roxanneedl5484
    @roxanneedl5484 Рік тому +7

    Okay I know that this is an old video, and I know this comment is not specific to this particular video, but I have been watching a lot of your lessons about complex numbers and I'm amazed by how digestible it is. I find myself excited to wanna try to tackle some homework even tho I'm not a student and don't have any complex numbers to crunch! So thank you for making these great public resources!

  • @user-sq1zv4lp8t
    @user-sq1zv4lp8t 6 місяців тому

    Understanding maths makes solving questions more comprehensible

  • @adityatangirala3609
    @adityatangirala3609 7 років тому +2

    Excellent job.... helped me through my exam

  • @mms9038
    @mms9038 7 років тому +5

    Did anyone mention that you are a life saver!!! XD

    • @peacecop
      @peacecop 3 роки тому +1

      Is your life full of complex numbers beating you?

  • @thomasolson7447
    @thomasolson7447 8 років тому +3

    Is it known that the n-sphere has radius functions that also make an n-sphere? The rose curve is an example. That also continues in the sphere and the hypersphere. It seems to have a complex number affect to it. In the sense that you raise everything by a power and still get a circle.

  • @ewg6200
    @ewg6200 Рік тому

    I propose a new system of numbers to complement the limited complex numbers which are based on i alone. My system is based on the entity "n", which is defined as
    |n| := -1 where |x| is the absolute value of x and is always positive. If "i" stands for "iota", then "n" stands for "nonsense". The entity "n" is represented on the third mutually-orthogonal axis. Thus, we have the real axis, the imaginary axis, and the nonsense axis to represent numbers in 3-D space. Numbers are universally represented as z = a + bi + cn

  • @MrDhanesh2nair
    @MrDhanesh2nair 7 років тому +2

    Sir why dont we consider i before rsin theta in |Z|.

    • @matemaatika-math
      @matemaatika-math 3 роки тому +2

      Because "I" only shows which number runs on imaginary axis.

  • @rajbalasharma8713
    @rajbalasharma8713 5 років тому

    Hey why are boundries between -pi by 2 to plus pi divided by 2

  • @vcrashthegreat
    @vcrashthegreat 8 років тому

    FIRST