Nice explanation. Although, solution to the second problem is incorrect. The correct solution, i think, is as follows: 2^10 = 1024 > 10^3 Taking 5th power on both sides, (2^10)^5 > (10^3)^5 => 2^50 > 10^15 => n = 50. Although, it is still not enough to say that 50 is the LEAST integer to satisfy the ineqality.
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Nice explanation. Although, solution to the second problem is incorrect. The correct solution, i think, is as follows:
2^10 = 1024 > 10^3
Taking 5th power on both sides, (2^10)^5 > (10^3)^5
=> 2^50 > 10^15
=> n = 50.
Although, it is still not enough to say that 50 is the LEAST integer to satisfy the ineqality.
Ya if instead of 15 there is 300 than
By this we end up to 2 ^ 1000 but 997 can satisfy this inequality.
Gold video
Great explanation for the first comparison problem. But for the second problem
2^50 > 10^15
2^(50/15) is also > 10..
So shouldn't n be 50 sir?
He said that n should be an integer, but i think he meant that n/15 has to be an integer
Thank you very much
No sir 9:50
Least integral value will be 50 👍
superb sir..
thank you, merci, gracias