Stoichiometry Tutorial 2024. How to solve stoichiometry question on limiting and excess reactants

[@BenChinonso-sj9bl]

Honestly speaking sir am so thankful for this lesson , I am hundred percent sure that I can solve any stoichiometry questions given I appreciate sir❤

[@AsehaefeOkezi-zw4vn]

Thank you so much sir, but pls do video on oxidation and reduction on how to know oxidizing agent and reducing agent,I know it will be 100% helpful....

[@janequeen6403]

Q1
Theoretical yield is 24.765g
% yield= 20.5 ×100/24.8 =82.7%

[@naomikahyana5884]

You're really a great help, you help me alot sir especially in chemistry thank you May God bless ❤❤

[@NurseBright]

Amen
Keep sharing with friends

[@naomikahyana5884]

I will try my best sir

[@Angelalee-bd4lb]

I've been waiting for this video since like forever thanks nurse bright ♥️

[@NurseBright]

You are welcome
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[@Physademy]

A masterpiece indeed❤❤

[@NurseBright]

Thank you ✨

[@egbekobamerit2037]

Thank you
God bless you🙏🏾

[@NurseBright]

Amen
You are welcome
Keeps sharing with friends

[@NkechiyereChristopher]

I have been waiting for this video to drop, and finally, the great OBO has done another wonders,
The great OBO of chemistry just know we ur fans love and look up to u,
God bless you for the help u have rendered to some people and I,
Thanks for the video🙏🙏🙏🤭

[@NurseBright]

I am glad my videos have impacted you greatly Christopher ✨

[@NkechiyereChristopher]

@@NurseBright yes it has Nurse, u re really the best trust me

[@ShafaatuSulebuba]

Thank you so much sir you really don a great help sir please do a video on oxidation and reduction reaction it will be helpful sir. Thank you sir

[@janequeen6403]

Q2
% yield of CCl4=77.4%

[@ChikwadoOkonkwo-xr7rc]

Top notch 🎉

[@NurseBright]

Thanks✨ Keep sharing with friends

[@TemiaginEguolois]

Q1: moles of HI=0.195 moles
8HI= 4I2
8mol = 4moles
0.195 = x
X= 0.0975 moles of I2
Mass of I2= 0.0975×254= 24.8g
% yield= 20.5/24.8= 82.6%
Dont let the excess h2so4 confuse you.
Q2: no of moles for cl2 = 0.31
No of moles for CS2 = 0.237
3Cl2 = CS2
3mol= 1 mol
Xmol = 0.237
Xmol= 0.71
3CL2 = CS2
3MOL = 1MOL
0.31= XMOL
XMOL= 0.103.
Cl2 is the L.A
3CL2 = CCL4
3MOL= 1MOL
0.31= XMOL
XMOL= 0.103MOL
MASS OF CCL4 =
0.103×154= 15.9
12.3/15.9× 100= 77.35.

[@NurseBright]

Very correct ✨

[@femilawal9906]

❤

[@aghahowamaria1095]

Pls do another vid in theoretical yield and percentage yield

[@NurseBright]

Alright

[@nnennadoris327]

God bless you

[@NurseBright]

@@nnennadoris327 Amen
Keep sharing with friends

[@AnimashaunOmoshalewa-wi2vu]

Question 2: theoretical yield is 15.9
Percentage yield is 77.36%

[@DanielChukwuka-nt5et]

Question 1: theoretical yield: 12g while percentage yield: 165%
Question 2: percentage yield:27.9%

[@TemiaginEguolois]

Please explain how you got the answer especially the no of moles for h2so4

[@beautyfinestmarvellous]

Pls solve the second practice question
I think I'm confused

[@GeorgeMatthew-gs7pv]

Theoritical yield for question one is 1122, while percentage yield is 1.827
Question 2
% yield is 2.09898

[@GeorgeMatthew-gs7pv]

So it's correct

[@JumokeBadmus-s2n]

Tysm❤️

[@NurseBright]

You are welcome
Keep sharing with others

[@imaobongjimmy]

Good afternoon everyone, please can someone help me write out the question no.2 is not clear in my phone
Thank you .

[@Alimiyawuiliyasu]

Wow

[@festusrotimi2403]

Hi

[@AsehaefeOkezi-zw4vn]

Explicit

[@Ibrahimensah]

Q1 Theoretical yield =107.115g and Percentage yield = 19.14%
Q2 Percentage yield= 25.8%

[@NormanKekulahLahai-m7e]

This method is too long sir

[@AnimashaunOmoshalewa-wi2vu]

Question 1: theoretical yield is 50.8
Percentage yield is 40.35%

[@AnimashaunOmoshalewa-wi2vu]

Sir is the answer correct