I’m so happy I found this video. You should label it open circuits as well. I was so lost trying to qualitatively identify filters using impedences and how devices behave like open or short circuits because I did not understand this core concept. I searched and searched the internet for a clear explanation and no one explained open circuits and their voltage drops this well! Thank you for putting those helpful videos out there!
I understand this only because I have been studying the basics for about. Now I am in class and I have classmates that are struggling with this concept. If your gonna teach you have to know how and be willing to dumb things down. You have to meet the student at his level of knowledge and intellect.
Because it's a series circuit, if current between the open circuit is 0, current across R should also be zero. Another thing we can do is assume resistance across open circuit to be infinity, so resistance effective is infinity, making current from battery to be zero.
Awesome series, I love how clear and to the point your explanations are! As a cs student that watches a lot of Ben Eater this series was at a perfect level for me to get a better understanding of a lot of the breadboard work. I guess you're taking a break from it, are you planning to continue it at some point?
Thanks! As you can see my channel sort of jumps all over the place depending on what I'm interested in at the moment. Eventually, yes, I'd like to continue this series to include other topics I've taught in Mechatronics at Cornell (e.g. RC circuits and op amps), but I probably won't have time in the near future (I have two young kids and UA-cam is mostly a side hobby). I do have a lot of Arduino tutorials up already in case you haven't seen those.
The voltage across R(1) = 30 V and the voltage across R(2) = 45 V. If the wire breaks between the two resistors, the voltage across the break would be __________ V. What about this question?
How do you express the voltage drop across the open switch mathematically? Is there equation for it, or must you say "Ohm's Law doesn't apply; trust me bro."?
Unfortunately I made this whole series 1) during the pandemic while I was largely stuck at home and 2) while I only had one kid. Now I have two kids and zero spare time. I would love to continue the series but at this rate it will be when they're in college.
@BenFinio oh okay no worries we understand. Thank you for making all these episodes, though. Really helped me a lot (I almost made it to the Bangladesh national physics team with your help!!!!!)
The white side of my family came to Jamaica in early 1800s/late 1700s from Ireland to a small village with like 100 people. I couldn't tell you why they did lol.
It’s not. It’s just measuring the potential force. You can think the same thing about the battery. There’s no current moving inside the battery with nothing connected to it but you still measure 12v across it
Unfortunately it's kind of hard to explain in a comment - I just replied to one of your other comments, the potential drop is zero across a CLOSED switch because it has zero resistance. The potential drop is not zero across an open switch, as explained in this video.
Is there going to be a video about capacitors? I was hoping for it, I really liked your 29 videos but I watched them to get to important stuff like capacitors, inductors, diodes, transistors. I kinda wasted time(still nice to remind myself basics). Only thing I can build with this knowledge is a heater... :( This series is only for students who need to pass the exam. False advertising. Any practical use would need additional components which you mentioned that you are gonna cover in almost every single video.
Unfortunately life with two small children has eaten into my time to make UA-cam videos :-). I would love to add more in the future but can't make any promises about when I'll have time. You should be able to find other videos about capacitors on UA-cam though.
![Lp. Сердце Вселенной #60 РОЖДЕНИЕ ЛОЛОЛОШКИ [Финал] • Майнкрафт](http://i.ytimg.com/vi/YoR0pAV9FVQ/mqdefault.jpg)
I’m so happy I found this video. You should label it open circuits as well. I was so lost trying to qualitatively identify filters using impedences and how devices behave like open or short circuits because I did not understand this core concept. I searched and searched the internet for a clear explanation and no one explained open circuits and their voltage drops this well! Thank you for putting those helpful videos out there!
Thanks! If you haven't seen it already, this video is part of a whole series that also includes filters.
Great informative series, thanks so much for putting this out there it’s quite helpful and wholistic , much appreciated
I understand this only because I have been studying the basics for about. Now I am in class and I have classmates that are struggling with this concept.
If your gonna teach you have to know how and be willing to dumb things down. You have to meet the student at his level of knowledge and intellect.
Why does I equal zero 4:13
Because it's a series circuit, if current between the open circuit is 0, current across R should also be zero. Another thing we can do is assume resistance across open circuit to be infinity, so resistance effective is infinity, making current from battery to be zero.
Amazing videos man! Im sad that you don't have much subs, very usefull content
Awesome series, I love how clear and to the point your explanations are! As a cs student that watches a lot of Ben Eater this series was at a perfect level for me to get a better understanding of a lot of the breadboard work. I guess you're taking a break from it, are you planning to continue it at some point?
Thanks! As you can see my channel sort of jumps all over the place depending on what I'm interested in at the moment. Eventually, yes, I'd like to continue this series to include other topics I've taught in Mechatronics at Cornell (e.g. RC circuits and op amps), but I probably won't have time in the near future (I have two young kids and UA-cam is mostly a side hobby). I do have a lot of Arduino tutorials up already in case you haven't seen those.
very good explanations
Fantastic explanation, thanks a lot
This is actually a great video. Ohms law gets you in trouble. Thanks! By the way with AC you would get 120 on either side as well.
what will the value be if the circuit was shorted at that point? 0?
The voltage across R(1) = 30 V and the voltage across R(2) = 45 V. If the wire breaks between the two resistors, the voltage across the break would be __________ V.
What about this question?
How do you express the voltage drop across the open switch mathematically? Is there equation for it, or must you say "Ohm's Law doesn't apply; trust me bro."?
tell me you didn't pay attention to the video without telling me you didn't pay attention to the video
@@wilmercuevas6491 Yeah you're right, I did not watch the video. I just typed out that comment for fun because I love the sound my keyboard makes.
What if the 12V battery’s positive terminal is on the right side?
Will the voltage be -12V at the switch?
Assuming you measure the voltage drop in the same direction, yes.
Please continue this series 😭😭😭😭
Unfortunately I made this whole series 1) during the pandemic while I was largely stuck at home and 2) while I only had one kid. Now I have two kids and zero spare time. I would love to continue the series but at this rate it will be when they're in college.
@BenFinio oh okay no worries we understand. Thank you for making all these episodes, though. Really helped me a lot (I almost made it to the Bangladesh national physics team with your help!!!!!)
4:13 why does I = 0?
The white side of my family came to Jamaica in early 1800s/late 1700s from Ireland to a small village with like 100 people. I couldn't tell you why they did lol.
That's cool lol
How does it get through resistor without current.
It’s not. It’s just measuring the potential force. You can think the same thing about the battery. There’s no current moving inside the battery with nothing connected to it but you still measure 12v across it
thank you
Literally been trying to understand this current physics for the past 3 years and can NEVER get my concepts clear. Urgh why is physics so tough?😭
Is potential drop 0 across an open switch? Just need a simple explaination please. My mind will burst.
Unfortunately it's kind of hard to explain in a comment - I just replied to one of your other comments, the potential drop is zero across a CLOSED switch because it has zero resistance. The potential drop is not zero across an open switch, as explained in this video.
Is there going to be a video about capacitors? I was hoping for it, I really liked your 29 videos but I watched them to get to important stuff like capacitors, inductors, diodes, transistors. I kinda wasted time(still nice to remind myself basics). Only thing I can build with this knowledge is a heater... :( This series is only for students who need to pass the exam. False advertising. Any practical use would need additional components which you mentioned that you are gonna cover in almost every single video.
Unfortunately life with two small children has eaten into my time to make UA-cam videos :-). I would love to add more in the future but can't make any promises about when I'll have time. You should be able to find other videos about capacitors on UA-cam though.
But then why on earth the potential drop is 0 around a closed switch??!!!!
A closed switch has zero resistance. Ohm's Law V = IR, if the resistance is zero then the voltage drop is zero.
What is voltage drop accross closed switch?
0
1
2
3
How is it possible
Its 0v
Assuming you model it as an ideal switch with zero resistance, the voltage drop across the closed switch is 0V.
@@BenFinioHow? Closed switch means the current is flowing, right? So if current is flowing how can V BE 0???!!! Y'all messin with my brain 💀