Cart Collision with a Spring

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  • Опубліковано 10 вер 2024

КОМЕНТАРІ • 32

  • @ashikurrahman9672
    @ashikurrahman9672 3 роки тому +4

    I feel really glad to have such a teacher like you sir... thank you for sharing your ideas to us.

  • @mohfa1806
    @mohfa1806 2 роки тому +1

    wow what a teacher ........ i salute you from lebanon

  • @Renegen1
    @Renegen1 2 роки тому +1

    really great example to show how elastic collisions work, those are rare.
    I want to get some additional answers, and maybe you can help: What would the above example look like if the spring had plastic deformation? What would happen to the energy? Would some of it get lost in this deformation? And how do we generally integrate the stress analysis into this collision.

  • @mziaulkarammziaulkaram2787
    @mziaulkarammziaulkaram2787 Рік тому

    I still have not get solution of my problem but I like your way of working. Very like it. Thanks

  • @preetiseth3615
    @preetiseth3615 3 роки тому +3

    Sir can we solve it In the Center Of Mass frame ??

  • @emrecakirbas4511
    @emrecakirbas4511 2 роки тому +3

    THX SO MUCH SIR FOR CRYSTAL CLEAR EXPLANATION :D

  • @hoda202
    @hoda202 2 роки тому +1

    this same problem actually came in my test lol just different numbers, thanks a lot

  • @samanthaolga1
    @samanthaolga1 2 роки тому +1

    what if i have 2 springs, one on mass1 and one on mass 2 , same k constant

  • @marypoppins6290
    @marypoppins6290 3 роки тому +3

    this video really helped!! Thanks a lot!!

  • @user-uq5qm3zu3u
    @user-uq5qm3zu3u 11 місяців тому

    I have doubt well it may rather seem foolish but while doing these type of numericals why do we not consider momentum of spring I mean surely it should also have momentum right please can you answer this

  • @roman6422
    @roman6422 3 роки тому +3

    Thank you, this really helped me. Keep it up!

  • @aboplus1010
    @aboplus1010 3 роки тому +2

    You deserve more views n subs bro❤️📖

    • @PhysicsNinja
      @PhysicsNinja  3 роки тому

      Thanks! I’ll continue working hard to help students.

  • @PAL0S0LJA
    @PAL0S0LJA 3 роки тому +4

    Nice video and very well explained!

  • @chandbeautifulpoetryands-cx4rk

    Good

  • @stephanyrodriguez4247
    @stephanyrodriguez4247 10 місяців тому +1

    what’s the previous video? i’m having trouble finding it

    • @PhysicsNinja
      @PhysicsNinja  10 місяців тому

      One Dimensional Elastic Collisions
      ua-cam.com/video/MJQ9eKGanUs/v-deo.html

  • @sheraah.-1948
    @sheraah.-1948 Рік тому +1

    Excellent ❤

  • @ahmedayman6402
    @ahmedayman6402 3 роки тому +3

    You are awesome

  • @bobnouh4538
    @bobnouh4538 5 місяців тому

    I don’t think that part D fir max compression will happen by just assuming that both blocks move with same speed. This should be solved by differentiating the X equation and find out V1 and V2

  • @BenAllan-og1gw
    @BenAllan-og1gw 5 місяців тому

    Good ❣️

  • @RuchiReddy-ob7ju
    @RuchiReddy-ob7ju Місяць тому

    Solve jee ad 2016 problem on rotaional that is really good

  • @user-shalu84.
    @user-shalu84. Рік тому

    Really helpful

  • @sanchit6728
    @sanchit6728 3 роки тому +1

    Sir how can I contact you ?

  • @RuchiReddy-ob7ju
    @RuchiReddy-ob7ju Місяць тому

    Is this 11 grade problem

  • @cjcrawford1958
    @cjcrawford1958 2 роки тому

    Derivation or proof that maximum spring compression occurs at equal and opposite block velocities?

    • @PhysicsNinja
      @PhysicsNinja  2 роки тому +3

      At max compression the blocks ha the same final velocity. There’s not really a prof but consider some of the cases. If the block and still moving toward each other than clearly the compression can’t be a max value. If the are moving away from each other the max compression had to happen some time before.

    • @cjcrawford1958
      @cjcrawford1958 2 роки тому

      @@PhysicsNinja still not convinced: at max compression the two velocities are 0, and yes 0=0 at that point, but that is at the limit and given different f=ma's they could be approaching each other a different speeds and accelerations.