√x+ i√x=2 √x(1 + i)=2 (now times (1 - i) => 2√x = 2(1-i) x=(1-i)^2 = -2i symmetry shows -x and x are same as x and -x => second solution +2i (corrected)
Nonsense. Square root of x for complex x has no unique meaning. For example, sqrt{-1} is a set containing two elements: i and -i. Hence the problem is not well defined.
Nice solution. Thanks for showing that.
Loved the sound of the chickens in the background :-)
அருமை
√x+ i√x=2
√x(1 + i)=2 (now times (1 - i) =>
2√x = 2(1-i)
x=(1-i)^2 = -2i
symmetry shows -x and x are same as x and -x => second solution +2i
(corrected)
Why move the 2nd term to the other side? Just square both RHS and LHS at the start. Much easier.
Bravissimo❤
Solved it in my head in +- 2i seconds.
I did it in my head really fast but only got --2i. I guess I better watch the whole video, huh?
What’s wrong in my method please?
Sqrt(x) + sqrt(-x)=2
Sqrt(x) as a common
Sqrt(x)*(1+i)=2
Sqrt(x)=2/(1+i)
Square both..
So,
X=4/(1+i)^2
X=2/i only 😢
🙏
1
Une racine négative n'existe pas
Nonsense. Square root of x for complex x has no unique meaning. For example, sqrt{-1} is a set containing two elements: i and -i.
Hence the problem is not well defined.
But you cannot square root a negative number
Use your imagination.