The Fast Fourier Transform Algorithm

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  • Опубліковано 21 лип 2024
  • Computational efficiency of the radix-2 FFT, derivation of the decimation in time FFT.

КОМЕНТАРІ • 131

  • @acatisfinetoo3018
    @acatisfinetoo3018 10 місяців тому +15

    This video is 10 years old and is still the most complete and concise video on the subject 💯

  • @sub-harmonik
    @sub-harmonik 10 років тому +25

    5:30 to skip review of big-O and DFT stuff, good video thanks

  • @TimSweet
    @TimSweet 10 років тому +6

    Awesome video thank you! Explained in ten minutes what I couldn't understand my professor was trying to say in three hours.

  • @psinha6502
    @psinha6502 3 роки тому +6

    Feel bad for Mr. Gauss

  • @nbro5529
    @nbro5529 5 років тому +4

    At minute 6:21, you start explaining the idea behind the FFT algorithm, that is, that you split the original sequence into two subsequences. However, in that expression, you use W_N^{kr} in the addends instead of W_N^{kn}. I think you used r here because in the next slide you use r in order to define the index, but, at this point, you have not yet defined r.

  • @sz7063
    @sz7063 6 років тому +18

    Thank you so much!! So clear!! I read the book, resulting in feeling hopeless, and your explanation just lightens up my world. ^_^ Thanks again!

  • @vinsavi
    @vinsavi 7 років тому +1

    Best clear cut explanation , this video helps to jump from FT to FFT and understand the computational efficiency.
    Come with some prep study of FT and do an actual calculation in excel then come here and you are done!

  • @bbrealey
    @bbrealey 7 років тому +2

    Thank you, this was super helpful in understanding the transition from DFT to DFFT.

  • @rodericksibelius8472
    @rodericksibelius8472 Рік тому

    As an electronics technician of only a 2 year Associate in Science Technology degree in electronics for 37 years, and retired now, who helped engineers design, test breadboard and build / troubleshoot practical low frequency RLC circuits and also at the microwave frequencies for building 'cascaded microwave stripline amplifiers' in the 4 to 30 GHZ range for use in the real world, I had never used Fourier Transforms nor Laplace Transforms, I only used High Tech Oscilloscopes, Spectrum Analyzers, Vector Network Analyzers, SMITH CHARTS, Voltmeters, Ammeters, Frequency counters and computers, and sometimes used ALGEBRA and TRIGONOMETRY to solve electronics circuits problems In the laboratory and in the REAL WORLD,
    I have great RESPECT for the Geniuses of ELECTROMAGNETICS Pioneers, who had derived the mathematical physics of all the basics the we based our technology from: James Clerk Maxwell, Hertz, Gauss, Faraday, Lenz, Oersted, Henry, Steinmetz, Heaviside, Tesla, Weber, and many more, including STEVE WOZNIAC.

  • @allsignalprocessing
    @allsignalprocessing  11 років тому +15

    Yes, good catch. x[8] should not be on slide 4 at 10:04, but it should be x[0] x[2] x[4] x[6] as Colo Ricatti pointed out. Somehow I skipped x[4] when counting.

    • @lad4694
      @lad4694 2 роки тому

      Spent 20 mins trying to figure if there was something I'd missed lol. Will come back to the comments more often in the future

  • @allsignalprocessing
    @allsignalprocessing  11 років тому +2

    no, at 11:10 it is just splitting even and odd index terms (splitting N = 8 DFT into 2 DFTs of N = 4). The full bit reversal (x(0) x(4) x(2) x(6) ) occurs after three stages of splitting - see 15:08

  • @Isti115
    @Isti115 5 років тому

    At 9:33 you say "x sub zero" and I found that a bit confusing later in the video, when I forgot where it's came for, but now I have realized that it's more like "x sub oh". :)
    Thanks for the great video! It really helped me!

  • @tim_arterbury
    @tim_arterbury 8 років тому +14

    Super helpful! I'm trying to make an audio spectrum analyzer. This has gotten me closer to understanding the concept, thanks!

    • @tharakaratnayake
      @tharakaratnayake 5 років тому +1

      did you build it ? can you share the circuit diagram?

    • @CanaDan
      @CanaDan 2 роки тому +2

      me too. iv been looking around kinda everwhere for good information on how this all works and how to calculate audio into something viewable

    • @tim_arterbury
      @tim_arterbury 2 роки тому +1

      @@CanaDan One tricky bit I’ve learned recently. You will want to skew the visualization horizontally towards the right. For audio, the FFT contains a ton of detailed high frequency information so if you just visualize the FFT as is, it is hard to see the bass/miss areas. You want to skew the visualization to emphasize the bass and mid regions for regular viewing as you might see in a spectrum analyzer in your DAW

  • @efraincaballero7482
    @efraincaballero7482 8 років тому +1

    this is beautiful, thanks man!

  • @Kaiser1234100
    @Kaiser1234100 6 років тому +1

    How would the butterfly diagram (@ 15:06) change if there were numerous iterations of inputs? For example if N=128 but the 8 channels structure is maintained? Thanks

  • @dhimanbhowmick9558
    @dhimanbhowmick9558 8 років тому

    Thank you very very much ,Barry, very nice and deep explanation. Your way of explanation is very good. Thank you so much.

  • @bachkhoa1975
    @bachkhoa1975 Місяць тому

    This is a good overview of FFT. It would be nice to explain how the DFT convolution sum is derived. Also, the de-interlacing of the inputs was glossed over (not explained clearly) but only the reversed binary notation was mentioned (this is just an after-the-fact observation of How, not an explanation of Why). Readers who dive deeper into the splitting of a larger N-point FFT into two smaller N/2-point FFT’s, or understand the relationships between the twiddle factors (and their periodic nature) would understand and retain better the FFT technique (and be able to conquer any arbitrary size of N-point FFT (N being a power of 2, of course).

  • @gynxrm2237
    @gynxrm2237 4 місяці тому

    the best i have watched so far..

  • @MrPsverma
    @MrPsverma 7 років тому +6

    all important things at a place!!!

  • @junbozuo6474
    @junbozuo6474 6 років тому

    Great explanation on Butterfly algorithm!

  • @Tunatunatun
    @Tunatunatun 9 років тому +76

    At 12:00, shouldn't the first left numbers be 0, 2, 4 and 6?

  • @esrayeniaras9292
    @esrayeniaras9292 4 роки тому

    Excellent explanation. Helped a lot. Thanks!

  • @rafafafayo
    @rafafafayo 10 років тому +1

    Very cool, but maybe it lacks some schemas to express more the ideas of the simplification.

  • @atulpol93
    @atulpol93 10 років тому +9

    In butterfly diagram it should be x[4] instead of x[8] ,right?

    • @allsignalprocessing
      @allsignalprocessing  10 років тому +6

      Yes. There is an annotation at 10:07 that points out the problem, but that may not be visible on your device. I have also uploaded a corrected version of this video to my channel, called The Fast Fourier Transform (FFT) Algorithm (c)

  • @freedomchinaify
    @freedomchinaify 5 років тому

    I highly suggest going back to second-year advanced calculus textbooks. There're many well-rounded explanations of FFT rather than what we have in DSP textbooks.

  • @PikaGMS
    @PikaGMS 5 місяців тому

    i just want to say that i love you man

  • @hzlin6655
    @hzlin6655 6 років тому

    there is a lot of interesting points at 13:41. please check that, if it is wrong.

  • @Jsmith32t
    @Jsmith32t 11 років тому

    When you pull the WN^k term out at 7:55, is that term known as the twiddle coefficient?

  • @inverse_functor
    @inverse_functor 4 роки тому

    Thank you for sharing your knowledge.

  • @llewgibson
    @llewgibson 6 років тому

    I seen your channel mate, really love the content. Subscribed straight away, We should connect!

  • @cyl3477
    @cyl3477 6 років тому

    Really good video!!! Clearly explained!!! thankyou!

  • @bggbbdg5625
    @bggbbdg5625 4 роки тому

    To calculate the cost in the 13:42. It should be 2(N/2)^2+N/2, the next steps will be similar. So the final cost will be 3/2N+1/2N logN. It is because that the w of the lower half are simply negative of those of the upper half. So the cost should not be counted. Of course under big O notation, the final answer is still O(NlogN). You are really helpful, but there are some minor mistakes.

  • @philphil7551
    @philphil7551 7 років тому

    ist there an advantage of bit reversed positioning ?

  • @marcvandijken7442
    @marcvandijken7442 7 років тому

    I don't know if you ever check comments for this particulair video since it's been a while since you've uploaded it, but I have a question: how do you get O(((N^2)/2)+N)? I know you explained it in the video (at around 12:00), but I don't understand it. Thanks in advance!

  • @ZatoichiRCS
    @ZatoichiRCS 7 місяців тому +1

    This video had so much potential but glossed over so so much.

  • @binchyster
    @binchyster 11 років тому

    Very good thank you! Nice and clear and well explained.

  • @_white.rabbit_
    @_white.rabbit_ 7 років тому

    How do you choose appropriate W values ?

  • @trendytrenessh462
    @trendytrenessh462 2 роки тому

    Somebody please get this guy a raise

  • @intelligenceservices
    @intelligenceservices 7 років тому

    where can i learn more about what "k" and "w"(omega) and all these greek symbols mean? i'm studying too many things and it is just hard to remember what they mean.

  • @amanuelamente6214
    @amanuelamente6214 9 років тому +3

    X[k] = Xe[k] + Wn,k*Xo[k]. Index for X runs from 0 - 7, but that of Xe and Xo runs from 0 - 3. Please reply how to deal with X's when the index runs above 3. (I'm assuming N=8)

  • @ser29009
    @ser29009 9 років тому

    you are my hero .. I think I will use the website too .. thanks

  • @mattanova
    @mattanova Рік тому

    perfect explanation, thank you !

  • @shahdseddik3731
    @shahdseddik3731 5 років тому

    Great video! Thanks

  • @manjumanl5279
    @manjumanl5279 Рік тому

    Wan , you're the best .

  • @varunnegi7202
    @varunnegi7202 10 років тому

    just what i wanted..thanx a lot :)

  • @sivonparansun
    @sivonparansun 7 років тому

    This video saved my ass. Thank you Barry

  • @Net_Flux
    @Net_Flux 5 місяців тому

    Not sure why you left out the recursive relation between the odd and even functions and the DFT. I was so confused where the speed gain was from.

  • @cyl3477
    @cyl3477 6 років тому

    I just understood FFT for the first time!

  • @stevenz995
    @stevenz995 9 років тому +29

    Finally someone explains FFT that people can understand!!!!

    • @nanwu4733
      @nanwu4733 9 років тому +2

      哪来的8啊

    • @stevenz995
      @stevenz995 9 років тому +1

      Nan Wu 诶。。。 你怎么也看这个了

    • @stevenz995
      @stevenz995 9 років тому +1

      Nan Wu 什么8?

    • @nanwu4733
      @nanwu4733 9 років тому +1

      Steven Z 就扫了一眼封面就看到了x[8]

    • @ioptomato
      @ioptomato 6 років тому

      真的是眼力很好啊!

  • @harshavardhanasrinivasan3125
    @harshavardhanasrinivasan3125 8 років тому +1

    While solving decimation in time and frequency algorithm of fft we used only DFT why not IDFT sir.

  • @ajayagarwal3200
    @ajayagarwal3200 8 років тому

    beautifully explained (y)

  • @shivamjalotra7919
    @shivamjalotra7919 4 роки тому

    Thankyou for the video, its great

  • @natebennett8189
    @natebennett8189 6 років тому

    14:53 he cancels out the N^2/N (=N) saying "for capital N large enough, this term dominates". Someone, please help me, why do you drop the +N?

    • @sarthakj84
      @sarthakj84 6 років тому

      Awesome explanation. Made it very clear. Thanks

  • @goku5591
    @goku5591 5 років тому

    well done brother

  • @tawrimatsushige8379
    @tawrimatsushige8379 11 років тому

    There shouldn't be an x[8] term, right? Because then N would be 9?

  • @anonyan9832
    @anonyan9832 4 роки тому +1

    You missed one of the main parts: How to compute X[k+N/2]. So you only take k from 0 to N/2. Based on this, you didn't prove that the asymptotics is 2*(N/2)^2.

  • @MehrdadAkhavan224
    @MehrdadAkhavan224 4 роки тому

    where is the input X[4] in the block diagram?

  • @wanglin4785
    @wanglin4785 6 років тому

    Could somebody explains what if the signal is 10 points sampled(which is not 2^N), please?

  • @fadlylado
    @fadlylado 10 років тому +1

    Thanks a lot...

  • @mdorghammm
    @mdorghammm 8 років тому

    Great video

  • @SidsArt
    @SidsArt 8 років тому

    Thanks a lot Sir.. You are awesome! ;-)

  • @SalokinX
    @SalokinX 3 роки тому

    The complexity calculation for the FFT as you explained in the video is incorrect.
    2 summations of half size of the array will be N(N/2 • 2), which is N^2.
    The benefit of FFT is from the fact that
    W_N^rk = -W_N^r(k-N) when k ≥ N.
    This is due to the symmetric property of the exponential function:
    e^j2π = -e^jπ
    Now you only have to compute the FT for half the array and the other half can be constructed by negating those terms, so you end up with complexity
    N(N/2) for the first split.

  • @mudassarshahzad1285
    @mudassarshahzad1285 7 років тому +3

    i am gonna implement FFT in verilog and previously i was a moderate knowledgeabout FFT but after watching this video get through from this Thanks saving my life :v

  • @AaaRrrLllUS
    @AaaRrrLllUS 10 років тому

    Thanks a ton.!!!

  • @krutarthpatel9283
    @krutarthpatel9283 6 років тому +1

    Good one

  • @MPaulHolmesMPH
    @MPaulHolmesMPH 10 років тому

    Great video. Thank you.

  • @allsignalprocessing
    @allsignalprocessing  11 років тому +2

    Yes, those end up being the twiddle factors - see them in the example diagram for N=8 at 15:14

  • @marceloricatti6017
    @marceloricatti6017 11 років тому +1

    10:08 its x[0] x[2] x[4] x[6]

  • @LizaCharalambous
    @LizaCharalambous 10 років тому +2

    Thanks a lot that was really helpful. Great Job :)

  • @zhanjizhu5345
    @zhanjizhu5345 Рік тому

    what will it be if N = 30 ?

  • @clo7473
    @clo7473 2 роки тому

    @1:21 it should be N complex multiplies and N complex adds (not N-1) ... there are as many multiplies as there are adds

  • @csaracho2009
    @csaracho2009 3 роки тому +3

    Very well explained. FFT “For the First Time” somebody explains clearly what the FFT means!

  • @philphil7551
    @philphil7551 7 років тому

    sorry i dont get it... first example N = 8.... second example N = 8 again but more stages... help pls

  • @chispun2
    @chispun2 5 років тому +1

    Like si crees que Sergio y compañía no se han visto el vídeo, pero la recomendación ahí queda.

  • @CAIJianping
    @CAIJianping 10 років тому

    there might be sign errors: -1 should be used for X(k+N/2)

    • @allsignalprocessing
      @allsignalprocessing  10 років тому

      I'm having a hard time finding the equation you are referring to. Could you give me a time stamp in the video and be a bit more specific? Thanks.

    • @CAIJianping
      @CAIJianping 10 років тому

      Hi, sorry for the unclear description.There might be a sign error in the example graphs.

    • @lukmackul
      @lukmackul 10 років тому +10

      CAI Jianping why dont you just give the time in the video when the example graph appears

  • @bridgeasparagus5437
    @bridgeasparagus5437 3 роки тому

    where's all the cosines and sines in the equations?

  • @taylorklitschko8546
    @taylorklitschko8546 11 років тому

    Can anyone make a subtitle :目?

  • @likhithareddy5384
    @likhithareddy5384 6 років тому

    Linear filtering methods based on dft problems

  • @chemistrywaalla
    @chemistrywaalla 7 років тому

    Its awesome :)) !..

  • @rajatmalhotra4633
    @rajatmalhotra4633 8 років тому

    awesome

  • @seeva92
    @seeva92 8 років тому

    How it is n = 2r for even and n = 2r+1 for odd.. Can you explain please?.. Lets say if n = 8, for even -> n=2r -> 2*4 = 8. whereas,
    for odd -> n=2*r+1 => 9

    • @ShuvamNandi
      @ShuvamNandi 7 років тому

      Let us take the case that N is 8, the samples are numbered X[0], X[1], X[2], ... till X[7]. By dividing them into even and odd samples, X[0], X[2], X[4], and X[6] are grouped together, and X[1], X[3], X[5], and X[7] are grouped together. The value of r ranges from 0 to N/2 - 1. Thus, We can say that r is in the range of 0 to 3 (N/2 - 1 = 8/2 - 1 = 4 -1 = 3), making 2r and 2r+1 fall in the same range as well. Hope this makes things clear :)

  • @dr.m.senthilkumar6279
    @dr.m.senthilkumar6279 10 років тому

    really good n useful

  • @lwwm192
    @lwwm192 10 років тому

    very nice

  • @cassandriel
    @cassandriel 7 років тому

    Is that the power of j or i?

    • @kurianbinu3383
      @kurianbinu3383 4 роки тому

      If you are electrical engineer like me, we use j

  • @raymondzhao9557
    @raymondzhao9557 2 роки тому

    interesting!

  • @augustodutra3839
    @augustodutra3839 3 роки тому

    I just read the fast and fourious transform.

  • @Cyranek
    @Cyranek 5 років тому +2

    fuck me this is hard

  • @user-xk5rx9xe6w
    @user-xk5rx9xe6w 3 місяці тому

    15:33 ♡♡

  • @NisargJain
    @NisargJain 5 років тому +2

    15:07 muck fe

  • @jannastevens4086
    @jannastevens4086 6 років тому

    well mama what about how well we are doing in skewl... the Kids

  • @user-bc1nc2hi9l
    @user-bc1nc2hi9l 9 років тому

    what is "j" ????

  • @TheCaitlinlopez
    @TheCaitlinlopez 10 років тому

    Sorry but gauss was not, Fourier was

  • @user-fd2vs8vj4k
    @user-fd2vs8vj4k 3 роки тому

    هاذه صورت بابا اني هبه احبك هواي انته وعالتك اني حبكم هواي باي

  • @user-kw9nu7nv8w
    @user-kw9nu7nv8w 9 років тому

    Ffg

  • @sifsif2725
    @sifsif2725 3 роки тому +1

    LMAO imagine waiting 31 years for your image to be processed xD

  • @ahmedalmoola8191
    @ahmedalmoola8191 2 роки тому

    Good video but the ads are very distracting. if your intention to help, minimize or remove the ads. thumb down.

  • @xavieraxiak6866
    @xavieraxiak6866 11 місяців тому

    Crap audio.