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Professor Organic Chemistry Tutor, thank you for a lengthy explanation and analysis of the Horizontal Tangent Lines and Vertical Tangent Lines in Polar form in Calculus Two. This is a tremendous amount of information for all students/nonstudents to remember, therefore I will rewatch this great video. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
For the numerator you can let cosx = x So 2cos^2x + cosx - 1 will be 2x^2 + x - 1 = 0. This is easily factored as (2x - 1)(x + 1) =0. Then just replace the x with cosx.
Hey, amazing video super helpful problem. You are carrying me in calc. I have a question. Dosen't (0, pi) not work for both? According to the graph, there is a cusp there, meaning we cannot differentiate it there
When I put the points I get for the Horizontal and Vertical Tangent lines into a graph they are no were close to where the graph is, am I doing something wrong?
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Final Exams and Video Playlists: www.video-tutor.net/
Full-Length Math & Science Videos: www.patreon.com/mathsciencetutor/collections
Professor Organic Chemistry Tutor, thank you for a lengthy explanation and analysis of the Horizontal Tangent Lines and Vertical Tangent Lines in Polar form in Calculus Two. This is a tremendous amount of information for all students/nonstudents to remember, therefore I will rewatch this great video. This is an error free video/lecture on UA-cam TV with the Organic Chemistry Tutor.
You're a life saver... you explain this stuff way better than my professor.
Half an hour for 1 problem 😖😭 (but he did an AMAZING job of explaining it)
This is hell
he made it so simple but its still hard to remember all that before a test...
NO PAIN NO GAIN
No it is heaven
Doing it WITHOUT this video IS HELL.
I literally love this man, thank god for him.
Dude, your videos help me so much man
Can also use x = rcos & y = rsin, -----> x = 2cos(1+cos) & y = 2sin(1+cos), so u dont need to derivative r & plug it in.
For the numerator you can let cosx = x
So 2cos^2x + cosx - 1 will be
2x^2 + x - 1 = 0.
This is easily factored as
(2x - 1)(x + 1) =0.
Then just replace the x with cosx.
That's what he did lmao he just skipped the substitution. Your just adding in an extra step
You're the best. Thank you very much
Great Explanation!
Hey, amazing video super helpful problem. You are carrying me in calc. I have a question. Dosen't (0, pi) not work for both? According to the graph, there is a cusp there, meaning we cannot differentiate it there
Very great informative video! Thanks!
Thank God. I finally understand.
Currently watching this in class right before the test lets go
Imagine this q come in my exam i’ll spend the all hour to solve it and maybe i’will make a mistake 😂
thank you bro
I thought there wouldn't be a derivative at a cusp and therefore no tangent line? or am I wrong?
thankss 🥰
When I put the points I get for the Horizontal and Vertical Tangent lines into a graph they are no were close to where the graph is, am I doing something wrong?
The horizontal tangent line is touching the graph twice though? How is it a tangent?
god bless you
Good videos
Amazing
The y-axis is another the vertical tangent. (0,pi) seems legit.
could you upload videos related to finding the centroid?
Come to Pakistan bro i need to get you gulab jamans
thankyou :''
Why not just divide by sin(theta) at 10:55?
you would lose answers. Never divide by x! (or theta in this case)
what is this magic
ZAMN!
Come be my teacher please
🍎
i'm so cooked
First