Using Newton's Method | MIT 18.01SC Single Variable Calculus, Fall 2010

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  • Опубліковано 23 гру 2024

КОМЕНТАРІ • 39

  • @georgesadler7830
    @georgesadler7830 3 роки тому +1

    One of the greatest invention in Calculus for solving equations that involves nonlinear functions is the Newton-Raphson method. Professor Breiner thank you for explaining this method in great detail.

  • @Big_Gourdo
    @Big_Gourdo 4 роки тому +7

    I had this randomly recommended, guess I'm gonna learn now

  • @imegatrone
    @imegatrone 13 років тому +4

    I Really Like The Video From Your Using Newton's Method Instructor: Christine Breiner

  • @archilzhvania6242
    @archilzhvania6242 5 років тому +1

    Why did we not approximate sqrt(3) when approximating x1? How do we know it is approximately 0.564 even after simplification?

  • @guidofeliz8384
    @guidofeliz8384 5 років тому +2

    Nicely done. However, solution steps should be posted on the board to clarify the final answer.

  • @gulnoor7571
    @gulnoor7571 7 років тому +3

    Teacher, Do you have a lecture about integral equations?

  • @samsaraAI2025
    @samsaraAI2025 4 роки тому +1

    Great. I have the same problem but muy line is almost flat and i have 7 intersections. How do i know where to start and how i find all the intersections?

  • @sonukumar-ju3lk
    @sonukumar-ju3lk 7 років тому +4

    REALLY u r a great teacher

  • @semoge3249
    @semoge3249 3 роки тому +1

    Thanks you, MIT,
    Very cool.

  • @aatra1
    @aatra1 7 років тому +2

    Why is the function not y=3x-2cosx? How do you know which side you will subtract?

    • @Xxlmfaox
      @Xxlmfaox 7 років тому +3

      it doesn't matter it would give you the same result by reciprocity

  • @oumaimaabouzaid4948
    @oumaimaabouzaid4948 7 років тому +1

    what if we had a function that we can't draw? in this case ..how we can know the number of the roots and the value used as x0 (for the first iteration)? thansk a lot for answering

    • @AbhishekSachans
      @AbhishekSachans 6 років тому +2

      You can you use the intermediate value theorem to guess a root's location e.g. if f(1)= -2 and f(3)= 3 then root lies somewhere b/w x=1 & x=3. So you can take x0 to be 1,2,3 etc.

  • @amonevelina8261
    @amonevelina8261 10 років тому +2

    Thanx alot. Cud'n get this in a 2 hours lecture but got something in 7 minutes.

  • @rafaellima8146
    @rafaellima8146 10 років тому +3

    thank you!!
    I though it was difficult, but you made things kinda easy actually! =D

  • @ecapanema
    @ecapanema 3 роки тому +1

    Great! Thanks a lot

  • @marcoantoniobarreraolea5573
    @marcoantoniobarreraolea5573 6 років тому

    De Chile great teacher

  • @phyrho1822
    @phyrho1822 4 роки тому

    I love her !

  • @who6284
    @who6284 9 років тому

    wait so how do you calculate it exactly?

  • @aaronasmr8833
    @aaronasmr8833 8 років тому +1

    I have followed this method point to point ... plugged in the the equation by of course I am getting the wrong answers ..x values make no DAMN sense

    • @michaeltwiton2276
      @michaeltwiton2276 8 років тому +11

      Sounds like your calculator is set to degrees. Try changing it to radians.

    • @macmos1
      @macmos1 7 років тому

      lmao

    • @akilakavisinghe7189
      @akilakavisinghe7189 7 років тому

      how would that affect the answer LMAOO

  • @reinowarren7880
    @reinowarren7880 9 років тому

    Personally I do not like the notation cos x. I prefer cos(x), since cos x + 3 can be interpreted cos(x) + 3 or cos(x + 3). Since I deal mainly with beginners, this can be confusing and frustrating to them. Now if you were like our instructor, who is fluent in Mathematics, then cos x is acceptable. For example, I can deal with it, can you?
    ProfRay is my online moniker

  • @juliaj3239
    @juliaj3239 5 років тому

    it's 2 cosx-3x though, and the cos x function would be crossing y=2...so you are throwing me off.
    Better to show us how you get your solutions before plugging it in to the formula, because anyone can do that part

  • @bwamurambala9839
    @bwamurambala9839 7 років тому

    wow thanks alot.

  • @gabrielpereiramendes3463
    @gabrielpereiramendes3463 5 років тому

    #Excelent!

  • @marshalls36
    @marshalls36 2 роки тому

  • @reinowarren7880
    @reinowarren7880 9 років тому +1

    Our instructor uses some inappropriate terminology. She identifies x1 as being at least accurate to two decimal places of the final solution. That is true, but only because of the chosen value of x0. Choose a different x0 then it may not be true.
    This may lead to a student thinking x1 is always accurate to the nearest 100th of the solution, and that is a dirty lie!

  • @anouarelmarnissy599
    @anouarelmarnissy599 5 років тому +1

    x2=x1 c'ause we are looking for only one solution!

  • @vdwest4592
    @vdwest4592 12 років тому

    True and I saw a similiar babe named Jana Marcette but some sly guy married her!

  • @reinowarren7880
    @reinowarren7880 9 років тому

    Final solution is 0.563569204225516... via Microsoft Excel

  • @kittyliter008
    @kittyliter008 13 років тому +1

    total babe

  • @PHILLYMEDIC69
    @PHILLYMEDIC69 6 років тому +1

    how about instead of trying to find x when xo= pi/6, we go and open a business, go on shark tank, and make billions of dollars with kevin o leary and mark cuban

    • @CellWatcher
      @CellWatcher 16 днів тому +1

      Because you've got no money to start a business and keep it going for years till it becomes profitable.