Banach Fixed-Point Theorem

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  • Опубліковано 17 гру 2024

КОМЕНТАРІ • 48

  • @ivansidorov1384
    @ivansidorov1384 6 місяців тому +7

    Thank you. Clear and consequent. I always enjoy your math videos.

  • @nadav7679
    @nadav7679 6 місяців тому +4

    I have a functional analysis exam coming up, so it was great to see the full details of the proof taken with care!

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому

      Thank you very much! Good luck and thanks for the support!

  • @t.b.4923
    @t.b.4923 6 місяців тому +3

    I really enjoyed your concise explanation. Keep up the work and your channel will grow!

  • @DingHang04
    @DingHang04 6 місяців тому +13

    Very interesting to think this happens in real life

  • @StratosFair
    @StratosFair Місяць тому +1

    A beautiful proof for a beautiful theorem

  • @MGoebel-c8e
    @MGoebel-c8e 6 місяців тому

    Nice to listen to someone speaking English in my own accent;) Good video, especially appreciate the constant reminders that this is no rocket science. One question and a couple of observations:
    On 4:27 why does it have to be an inequality? The argument would hold as well if there was an equal sign, no?
    The definition of the map was a little quick for me - had to pause and go back in order to realize that we were hopping from one point to the next. Why this map?
    Would have helped if you had talked more about what this implies, i.e. what insight this delivers that is helpful for all the use cases you mention at the beginning. That would be more insightful than the uniqueness proof at the end (only professional mathematicians would even demand a proof of that, for the rest of us that is obvious enough:))

    • @mulletronuk
      @mulletronuk 6 місяців тому

      4:27 using an inequality here is more general than an equality.
      Insight: Take any real number, and take the cosine of it in your calculator. Now take cos(Answer) repeatedly and watch it converge rapidly to a fixed point :)

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому

      Thanks! Now try to prove this cosine procedure by using the Banach fixed-point theorem :)

  • @DavidLessure
    @DavidLessure 6 місяців тому

    This is a great video, we just learned about it in class, and this explanation makes it make a lot more sense. As always thank you TheBrightSideOfMaths ☀️😎

  • @BreezeTalk
    @BreezeTalk 6 місяців тому +3

    This is high quality mathematics in my eyes

  • @DOROnoDORO
    @DOROnoDORO 6 місяців тому

    Recently had to prove this in an analysis test :) turns out it's quite important for dynamic systems, my university's specialty

  • @awindwaker4130
    @awindwaker4130 6 місяців тому +1

    Beautiful proof

  • @debmallyachanda5384
    @debmallyachanda5384 6 місяців тому

    Absolute gem!

  • @tens0r884
    @tens0r884 6 місяців тому

    does the contraction have to be from X to X ? Does this not apply to X -> a different metric space as well ?

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому +2

      No, it has to be the same space in domain and codomain. Otherwise, the notion "fixed point" would not make much sense.

    • @tens0r884
      @tens0r884 6 місяців тому

      @@brightsideofmaths You're correct but I should have mentioned that the two spaces X and Y have non trivial intersection, for example, a contraction that also shifts the points a bit. I'll give a concrete example, f: [0, 1] -> [0.75, 1.25] given the canonical metric

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому +2

      @@tens0r884 Then the Banach fixed-point theorem is not applicable :D

  • @bestpixels596
    @bestpixels596 4 місяці тому

    Which reference books are used to prove this theorems?

    • @brightsideofmaths
      @brightsideofmaths  4 місяці тому +2

      None. This proof is already mathematical folklore and can also be found in Wikipedia, for example.

  • @eduardoGentile720
    @eduardoGentile720 6 місяців тому +4

    Here in Naples everybody calls this the Banach Caccippoli theorem hahaha

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому +2

      True :) I also know this name!

    • @Risu0chan
      @Risu0chan 6 місяців тому +1

      In France it's called the Picard (or Banach-Picard) fixed-point theorem, after Émile Picard. I didn't know Renato Caccioppoli's name. Interesting character, he was a pianist, an antifascist during Mussolini's era, playing La Marseillaise (French anthem) when il Duce was visiting… There is even a film about him.

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому +1

      @@Risu0chan Thanks! I did not know that :)

    • @eduardoGentile720
      @eduardoGentile720 6 місяців тому +2

      @@Risu0chan He is considered so important here in Naples that the math department of the Federico II (the most important university in the south of Italy) is called "department of Math and applications Renato Caccippoli"

  • @oldcowbb
    @oldcowbb 6 місяців тому

    seems like it will be very useful in nonlinear control

  • @A_doe_wasting_her_life
    @A_doe_wasting_her_life 6 місяців тому

    i was just wondering why is the idea of a cauchy sequence useful lol. NIce vid

  • @satiremuch2643
    @satiremuch2643 6 місяців тому

    What if the distance is 0.9999... + 0.0000...1. How far away are they then? 1:54

    • @brightsideofmaths
      @brightsideofmaths  6 місяців тому +2

      What is your metric space here?

    • @tens0r884
      @tens0r884 6 місяців тому

      0.0000...1 is not a real number (its not well defined)

    • @satiremuch2643
      @satiremuch2643 6 місяців тому

      @@tens0r884 Thank you for the answer. Would you like to expound on that?

    • @tens0r884
      @tens0r884 6 місяців тому

      ​@@satiremuch2643 I mean your decimal representation doesnt make sense. A real number less than zero always has the representation \sum_{i = 1} a_i * 10^(-i)

    • @satiremuch2643
      @satiremuch2643 6 місяців тому

      @@tens0r884 Ah ha.... my intention was to show (0 followed by infinitely many nines) + (0,0 followed by infinitely many zeros and a 1 at the end). 0.(9)n + 1/10n =1
      Not any negative number. Like this en.wikipedia.org/wiki/0.999...#Rigorous_proof

  • @Algebraictivist
    @Algebraictivist 5 місяців тому

    Cool

  • @Ijkbeauty
    @Ijkbeauty 6 місяців тому

    Vsauce