Thermodynamic versus Kinetic Control

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  • Опубліковано 23 гру 2024

КОМЕНТАРІ • 40

  • @vasanthakumarg4538
    @vasanthakumarg4538 4 роки тому +5

    Crisp and clear explanation of concepts, well done and thank you

  • @jkpp.
    @jkpp. 10 років тому +3

    Thank you so much. It's rare when I get that, "FUCK, I GET IT NOW" feeling. The clear explanation is much appreciated.

  • @sarahholland5980
    @sarahholland5980 4 роки тому +4

    this made so much more sense than my professor or textbook. thank you!!!!

  • @sciencenerd8879
    @sciencenerd8879 8 років тому +8

    Life makes sense again. Thank you!!!

  • @joenyc
    @joenyc 13 років тому +5

    you rock. thanks for the AMAZING explanation. i was clueless about the difference. now it all makes so much sense!

  • @chiman3778
    @chiman3778 5 років тому

    I just wanted to thank you for putting this together

  • @oguzcangokce6959
    @oguzcangokce6959 2 роки тому +1

    Thanks for the brief and clear explanation!

  • @razasyed575
    @razasyed575 2 роки тому

    my main man micheal evans coming to the rescue thank you!

  • @danielgladish2502
    @danielgladish2502 4 роки тому +2

    Great explanation. What I don't understand is how the factor reaction time works? Like why does the kinetic product eventually convert into the thermodynamic product? No new energy is added to overcome the larger activation energy barrier of the thermodynamic product.
    Thanks!

    • @mevansthechemist
      @mevansthechemist  4 роки тому +1

      Great question! You're absolutely right that no new energy is added, but keep in mind that the distribution of molecules in the reaction changes over time. It's all based on relative activation energies. Early in the reaction we have mostly the starting material (SM), which converts mostly into the kinetic product (KP) due to the lower activation energy leading to it. A little bit of thermodynamic product (TP) forms. Now, if we focus on the activation energies of the REVERSE reactions, we see that the KP reverts back to SM faster than TP. Thus, KP will eventually be funneled to TP due to its greater rate of reversion to the starting material.

  • @adosar7261
    @adosar7261 4 роки тому

    If we change the temperature doesn't delta G of both reactions change? So how do we know that after changing the temperature p1 isn't more thermodynamicaly favorable than p2?

  • @jameelsahadath217
    @jameelsahadath217 9 років тому

    how is kinetic control used to affect the outcome of a chemical reaction where several reaction paths are available

  • @panoskb9405
    @panoskb9405 7 років тому +1

    If you have a reaction that A+B->C, and it is only reversible then the only conclusion that you can make is that is kinetically controlled right?

    • @mevansthechemist
      @mevansthechemist  7 років тому +1

      If the reaction as a whole is reversible, it's thermodynamically controlled, not kinetically controlled. "Reversible" in essence means that the forward and reverse reactions are proceeding at equal rates; i.e., that the reaction system is in equilibrium (caveat: this is the organic chemist's "back of the envelope" definition. The definition in physical chemistry is more rigorous.)

  • @Elevatone
    @Elevatone 11 років тому

    What organic chemistry software is that? Link please?

  • @zaya421
    @zaya421 3 роки тому

    I still can't get it.. 😢

  • @Hands4Surgery
    @Hands4Surgery 12 років тому

    Is your activation energy correct? (0:20 - 0:25)
    I think activation energy is the whole value from the energy level of the starting material, all the way up to the peak of the transition state. Your second (right hand side) activation energy seems correct proceeding from left to right.

    • @mevansthechemist
      @mevansthechemist  7 років тому +3

      Good question-for anyone still confused by this, note that the graph is showing two different reactions proceeding outward from the center. Thus, two separate activation energies are shown.

  • @redarmuhammad1953
    @redarmuhammad1953 10 років тому

    very nice explanation.. Thanks

  • @saritar8819
    @saritar8819 11 років тому

    Thank you for simplifying it!

  • @ruthmasih9047
    @ruthmasih9047 2 роки тому

    amazing! thanks so much.

  • @aoifewest
    @aoifewest 10 років тому

    Great presentation. Thank you very much?

  • @sanadaltarawneh3550
    @sanadaltarawneh3550 Рік тому

    Good stuff

  • @parkjane116
    @parkjane116 6 років тому

    This helped a lot. Thank you so so much.

  • @camichael74
    @camichael74 11 років тому

    Thank you! great video.

  • @skyyward111
    @skyyward111 9 років тому

    Thanks a lot! Very helpful!

  • @FatimaSayes-en5bc
    @FatimaSayes-en5bc 6 місяців тому

    Finally i understood.

  • @RBaleog
    @RBaleog 13 років тому

    Good explanation, thanks!

  • @mmarycalvin6395
    @mmarycalvin6395 11 місяців тому

    Thank you.

  • @TheBitili
    @TheBitili 14 років тому

    Great,,,

  • @davidbohadana8274
    @davidbohadana8274 10 років тому

    Grate job!!!

  • @Aryan_sg
    @Aryan_sg Рік тому

    Thanks bro 😉

  • @jingyiang9786
    @jingyiang9786 5 років тому +2

    CN2116

  • @LunaDanu1
    @LunaDanu1 8 років тому

    thank you

  • @anoopkumarsonar1001
    @anoopkumarsonar1001 8 років тому

    Thanks Bro !

  • @Ace0077
    @Ace0077 11 років тому

    thanks, helped

  • @arqumabdullah2462
    @arqumabdullah2462 3 роки тому

    whose here from AAMC C/P SB #20