Mesh Current Problems in Circuit Analysis - Electrical Circuits Crash Course - Beginners Electronics
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- Опубліковано 22 сер 2024
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Learn how to solve mesh current circuit problems. In this electronic circuits course, you will learn how to write down the mesh current equations and solve for the currents in each branch of the circuit.
This electronics lesson shows how to walk around each mesh loop of the circuit and add up the voltage drops around the path. This is the central point of mesh analysis and is very easy to do once you learn and practice the technique..
Fantastic work, this is helping me far better than my college professor can!
Exactly!!
Great
Did you graduate?
your a very good teacher. I love how you always review everything you do after a few steps. Im struggling a little in class to keep up because we just keep continuing through the problems with little to no review.
This video aged 10yrs, but I'm using it today!! Thank you so much!!
This man has a good teaching tallent. Excellent job!
CogitoErgoCogitoSum what ru talking about
What's with that altitude? This isn't English class, man.
Sir you are great in such a small period of time yo bring much clarity keep it up, its people like you who inspire us to be lectures
Great teacher, easy to understand his accent. great explanation. one my fav teacher
Great Video! The only thing I would suggest is showing more detail on how to solve the matrix without a calculator. Can't leave out Crammers Rule.
FINALLLY, A USEFUL EXAMPLE
So many of the examples online are so simple that they do not hit very important small details about the mesh current method, so that you really only know how to apply it for single-loop circuits
you are amazing teacher.do you know that you saved a life ?? :D
I sincerely hope that students take full advantage of your lessons to enhance their learning in engineering programs throughout the world.
U of WA, EE dept 1975, we had to learn this by reading a book. In all my years of designing power supplies, I never used mesh equations once.
unfortunately in india
in colleges we get taught all sorts of useless things
i regret joining college
Thankyou so much sir.... You way of teaching is much more better then the people staggering for publicity on youtube
I noticed that circuit is actually a bridge, with the 10 ohm resistor as the center. I've been trying to analyze a bridge with no luck, (I think I'm making errors), anyway I applied thevenins theorem to the center resistor and came up with 45.8v th and 13 ohms th and it all worked out! Thanks a bunch!
I think he missed it . No Passive Sign Convention . and he plugged the coefficients into a matrix to solve the system of Eqs( beginners never use a matrix ) , while he wrote all 3 initial equations the "hard way" . all that will definitely confuse any beginner .o'well .
Edit Dec 29 , 2018 read chapter 1 and Chapter 2 of book :
ISBN : 0-07-027410-X McGraw-Hill
Engineering Circuit Analysis Fifth Edition 1993 . Chapter 2 covers the Context of Mesh analysis
verses using basic branch currents . Look on page 65 66 67
Yes , this book does NOT talk about writing equations directly into Pattern Format .
( NOT sure why Pattern formats are NOT included , cause the book does plug into Matrix's too , and the equation format that plugs into the Matrix is the Pattern , which can be
written Directly by Inspection of the circuit diagram ,...too easy .
The Final form Pattern of each equation is there , but the authors never mention it )
You are right.........
Nice explaination thx, but im wondering about 100 voltage why its negative while its rise !!! Should be plus i think. Thank u very much.
Budhabiya maybe the following is the reason why the two opposite conventions are popularly used. Some follow the logic that for every voltage rise is a plus, and a drop for every resistor (because that's what it really is) is a minus. However, if you will follow the passive sign convention of power in a circuit (supplying components are minuses and absorbing components are pluses) then the sign convention changes. We can use whichever sign convention we want as long as we stick to it within a solution. thanks for the video
some people write the KVL sign as they Enter each component . Thus , -neg terminal is Entered
and we write - 100 . Of course some people might write the sign as they Exit each component ,
in that case , we would write + 100 v . This is NOT confusing nor double talk . read chapter 1 and 2
of book : ISBN : 0-07-027410-X Engineering Circuit Analysis Fifth Edition , 1993 .
Note :
ALL 2 Year Tech School books have insufficient info to properly write equations .
( High School teachers don't know how to do it either )
As I was saying in my original Stand-alone-Post , he Never talked about How he Wrote the Equations .
That should have been the Whole Point of this tutorial , but he did NOT do that . Hence your question .
If you are coming from Electron Flow , then give that up . Because all the 4 year books use hole Flow .
If you want to write equations , you will be using hole flow . If you want to use Pspice , you will be
using hole flow .
read chapters 1 and 2 of the book above . That should fill in ALL the gaps in DC circuit equation writing .
You MUST read a Four Year book , such as mentioned above .
He should use positive sign for volti
You don't know sir how much i love you
I really appreciate it!
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Hi, to calculate the matrix inverse is a fairly involved process. The inverse in this problem is correct. I recommend that you study up on how to invert matrices. I have many tutorials on that!
If I was to choose kvl would it be a lot more equations then the mesh current?
thank you so much. I couldn't figure out for ages where the (ia-ib) was coming from but now I actually understand.
Sir your lecture is making me thinking different I really like the way you teach
This is the best video I have found for these topics thank you!!
You, sir, are a gentleman and a scholar. :) Thanks for such a classy and clear explanation!
You have a gift for teaching!! Thank you so much for the help :)
hay man i am from egypt and i wanna tell you that you are better than my prof thank you very much
and i hope ypu make good money of your workl
I've finally found a practical reason to learn algebra. The weird thing is: I'm digging this.
you have no idea how useful this was. beautiful man!!
Sir u 've the art to make electronic as simple as say hello thanks a lot and 'bravo '
yeah he does. You and finalanswer are the only thing getting me through school
You are my new hero. Your videos have helped more than you know
your teaching is a blessing to this earth
Thanks so much!
very detailed and easy to understand thank you sir
your way better than my teacher, finally understood it
you literally saved my life, i'd have failed if it wasn't for your videos
Truly awesome....
you r really an excellent teacher
Wow, thank you so much, so clear and easy understand.
These videos are sooooo tremendously helpful!!! Thank you so very much. Your videos are much appreciated!
Kindly assist how did he get those inverse values
Thank you! I came down with the flu recently, so I'm trying to catch up on the lectures I missed. This video came in clutch!
Awesome!
@@MathAndScience h
Thank you so much. perfect instructions. I've been trying to learn this for a couple of weeks. Now your video did it.
Thank for given me a good understanding of how to solve mesh circuits problems.
You are best professor
THANKS A LOT. i did this method when i studied electronics but I didn't know this thing called Mesh. (Theoretical Physics student here)
Most university teachers have MSC,PhD...but don't know how to teach...but you are fantastic thanks
This video will never die. Thank you sir!
top notch video. true excellence. you touch on subtleties with convention esp. with the voltage drop from negative terminal to positive as negative, and assuming the polarity of the resistor to conform with the direction of current being analysed at that point. keep it up!
I could not get why everytime there is a voltage drop, the sign of the resistor is still positive instead of negative.
Yes I also saw that mistake throughout his calculations
Good solving technique of solving mesh by matrix...
Thanks for your method sir..
It made solving very easy.
Thanks very much for your explainantion.Now i have confident in my upcoming exam.You really a great teacher
incredible thank you !!!
Thank you very much. You are a genius.
Wow what an incredible explanation . Tq sir helped more than my professor's explanation.
Thank you! This was easier than I though...!!
sir u r gifted with great teaching skill
How are you multiplying the final metric inverse with the constant?
Thanks! It helped me a lot!
Sir Can you replace the voltage source with current source and solve it...?
You are amazing teacher.super...
really talented sir amazing teaching skills
9 years ago, but better than a lot today!
Thank you,that's great teaching. That's so good for me.
you are the best, make it so simple
You are an amazing Teacher!
This is good teaching sir and this video is very very good
a very useful expression. Thank you very much
நன்றி,அருமையான பதிவு ஐயா
Thank you Sir. Right now i feel illuminated.
Very helpful ...now I get it. Thanks a lot .
Bro is doing the work of GOD
Thank you sir your the best teacher very very detailed thank you
Inverse is correct. I would recommend you to use fractions to get a more precise answer.
Very explanatory thanks
this is very helpful thank you!
having a hard time finding your calculated A^-1 values from the given matrix A... please help
just put in your calculator go in matrix then put at matA-1
we can also use Cramer's law...instead of the matrix thing...ryt??btw your teaching style was awesome....and helpful
Thanks .. really good teaching
Hey, what would you do if there was another voltage source as well as the 100v source. (particularly at the matrix step)
You are great sir
you are the best in youtuoe
Awesome video ! Thank you !
you r hero in my life
So happy you liked it!
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very clear explanation. Thank you very much.
I have a doubt. Why are we considering current in a clock_wise direction?
Santhi siva You can take in any direction. We are just assuming it. You can use anti clockwise direction and still arrive at the same answer
@@manojmaharaj1775 again , ( kind of ) , the same answers . CW clock wise arrow might give an answer of -2 amps , while if we had use CCW counter clock wise arrow , we would have gotten an answer of + 2 amps .
Both answers are ( Valid and Correct ) . do you know why Both answers are Valid ? ,...i know why .
Got it so well. Thank you
thank u soo much very helpfull........aizaz from dept of mechanical engineering uet peshawar
Great explanation. Thank you !!!!
My professor is good. But you are great! Thank you :)
omg finally i know how to get the equations no problem but its the calculator inverse of matrix a times b i didnt know omg thanks alot
! You are GOLD
quick question: can I take the I (sub b) mesh to start at the 100V source then into the 20 ohm, then through the 15 ohm, and back to the voltage source? It's a different loop but it still covers all the resistors. Thanks!
no, because there are resistors in the middle of the "super mesh" you propose. the current changes when it goes into other branches (KCL, conservation of charge), which is essentially what you would be ignoring by creating that super mesh.
Luke Porter Thanks a lot for your answer. Very clearly explained. :)
Excellent explanations, thank you!
I am indebted to you, good sir! Thank you!
This is pretty awesome
So happy you liked it!
Jason, MathAndScience.com
Thanks! Great talent for explanation! Let's see if it will be useful on tommorrow's exam :P
this guy is awsome
thank you.thank you
i now understanf it much much better😊😊
Man This helped a lot. Although only if it was that easy to get the inverse, sadly in my course we have to do it by hand and aren't aloud the use of any calculators that have matrix type functions. Although I use Cramer's Rule for the other stuff since I like it more.
thank you....this video was very helpful
You are a legend. Thank you
In the 2nd equation which is ib why we didn’t add -100V to it???
really...you saved me.Thank you!!!!
Is it possible to find current by adding all the resistance and then dividing it by voltage
very good explanation.. thank u sir...
You are very welcome!