Partial Fractions | Repeated Linear Factors
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- Опубліковано 30 лис 2020
- Partial Fraction Decomposition Form for Repeated Factors:
A factor is repeated if it has multiplicity greater than 1.
If the repeated factor is linear, then each of these rational expressions will have a constant numerator coefficient.
If the factor is to the power of 3. Therefore, 3 rational expressions are needed in the partial fraction decomposition, with each of the denominator is raised to a different positive integer power up to 3, wih 1, 2 and 3 respectively. Since it's linear factor, each of these rational expressions will have a constant numerator coefficient.
smoothest teaching ever, have never seen something smoother than this in any youtube channel
I appreciate it, thank you🙏
Yooo God bless you. I saw a question on repeated linear fractions on a past Q. I factorized the (x+3)² to x²+9. Then got some fractions for A B and C. Thank you ♥️
(x+3)^2 is equal to (x+3) (x+3) which equal to x^2 +6x +9
Professor Tambuwal, thank you for a powerful explanation on the Partial Fraction Decomposition Form for Repeated Factors. This material is helpful in Control Engineering.
Thank You, teacher. I finally found a video that matches my question for this lesson. May Allah bless you
Ameen
Thank you for teaching this. You make it easier to understand. Lots of love.
Thank you
Thank you sir 🙏🏻for your powerful explanation
Professor Tambuwal, thank you really appreciate sir
Sir, thanks alot for teaching
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Genius
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Thank you 🙏
Can we do cover method for this
Well explained 😩🤲thank u sir🥰
Thank you
🙏🙏
Pls resolve this
15x -x+2 (numerator) x-5 (3xsquare+4x-2)
God bless you Amen
Amen
That's amazing but I have a question why the power two for the second fraction
1:17
Good
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Where is t coming from
Can you help me on this one 3-x/(x^2+3)(x+3)?
ua-cam.com/video/WnoOkmqnN2c/v-deo.html
Good morning big bro I'm so grateful for your quick feedback but my problem is just on the numerator. I can't find a right coefficient for x^2 on the left hand side which I should equate to my first right hand side equation.
Yes ooooo