Is it possible that if the numbers are too close to each other (for example: biggest value is -1.8 and lowest is -2.39 so 2.39-1.8=0.5) that this method is not working? Thank you for your time!
You say that certain numbers would not be easy to plot based on the number of big squares divided by range, but this is exactly the problem I have. When I get the range of my data and divide it is not an easy number. For example, one of my ranges is 9.15. I have 10 big squares vertically and horizontally. Dividing it would result in .0915. This is the area I am stuck on to make my scale. Please respond, it would be greatly appreciated.
If I am bounded to have 8 big squares on x axis and 12 big squares on y axis than i have a problem from this method i can't plot my last value of x axis please guide me...
@@Tinghca here is my data On x axis 1.0,0.50,0.33,0.25,0.20,0.17 these are the values of inverse of width of a paper strip in cm which is to be torsionaly oscilated and here are the values of time period T along y axis 6.58,3.11,1.84,1.30,1.07,0.913
Range for x axis is 1-0.17 = 0.83, rounding it to 0.9, however you only have 8 big squares, 0.9 divide by 8, 7, 6, or 5 wouldn’t give you a easy value to plot. So just round the range to 1.0 and use 5 big squares so as to include all values. The y axis values can fit quite easily because the range can be rounded off to 6 and you have 12 big squares.
always had a problem with graphs but this seems plausible. Gonna see if this works thanks dude
You have no idea how much this has helped me! Thankyou so much !!!!!!
Is there any undergraduate learning this???
I'm the one!!!
Thanks a lot for this video.
OMG OMG THANK U SOOOOOOO Much my exam is tomorrow if I get a good grade I will dedicate it to u much appreciated, God bless u
@Daniel Cousins bruv I got an a* lol, I was so happy that I forgot about the vid. Thanks again! Keep it up.
Is it possible that if the numbers are too close to each other (for example: biggest value is -1.8 and lowest is -2.39 so 2.39-1.8=0.5) that this method is not working? Thank you for your time!
You say that certain numbers would not be easy to plot based on the number of big squares divided by range, but this is exactly the problem I have. When I get the range of my data and divide it is not an easy number. For example, one of my ranges is 9.15. I have 10 big squares vertically and horizontally. Dividing it would result in .0915. This is the area I am stuck on to make my scale. Please respond, it would be greatly appreciated.
Hi DA
Since one big square is about 0.09, keep it to one big square to 0.1 would solve your problem. Regards.
+Hc Ting Thanks
Hello how to calculate scale on y axis and x axis (division and unit)
How to plot this V/V against I/A : V/V = 0.2,0.3,0.4,0.6,0.9,3.7 & I/A=0.06,0.08,0.09,0.10,0.18,0.74!
PLEASE HELP ME!
I can help u please visit
If I am bounded to have 8 big squares on x axis and 12 big squares on y axis than i have a problem from this method i can't plot my last value of x axis please guide me...
work out the range as described in the video and always round up, if not u can show me your values, I will guide u along.
@@Tinghca here is my data
On x axis 1.0,0.50,0.33,0.25,0.20,0.17 these are the values of inverse of width of a paper strip in cm which is to be torsionaly oscilated and here are the values of time period T along y axis
6.58,3.11,1.84,1.30,1.07,0.913
Range for x axis is 1-0.17 = 0.83, rounding it to 0.9, however you only have 8 big squares, 0.9 divide by 8, 7, 6, or 5 wouldn’t give you a easy value to plot. So just round the range to 1.0 and use 5 big squares so as to include all values. The y axis values can fit quite easily because the range can be rounded off to 6 and you have 12 big squares.
How do you follow this
Please How do I know how many boxes I should use?
marking assessment criteria dictate it. size area of plotted points, end to end should occupy 3/4 the size of the allotted graph area.
what about small boxes?
PLS SOMEONE SHOULD ANS
how would I plot a graph having 1.8 as minimum values and maximum value 3.17
Sova Sarkar ur range would be equal to 1.37 rounding it off would come to 1.4. So u can use 7 big squares which would give u 1big square =0.2
I think the starting point will 0.5
Using 8 big squares
This doesn't seem to work for bigger values like 1300, 1400 etc
please show me your table of values
Well done sir.
Thanks a lot! Very well explained.
Very good
Jah jah why they don't just teach us this first sigh
Thank you! Very helpful!
Hey thanks alot this is really helpfull
OMG THANKK YOUU SO MUCHH 😭🙏
Thank you so much.
Your voice is a problem some time you are speaking loudly and some time we can't hear you
Thank you
thanks.......very much it was very helpful
Hie
Hw r u
The scale is incorrect, it should be 4 not 5...
I need to understand this but i didn't understand this🤦🤦😫💔💔help me.please
Thank you!
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