AmateurLogic 187: Buck/Boost, Balun & M5 Ham Radio

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  • Опубліковано 4 жов 2024
  • Tommy builds the M5 Ham Radio project. George makes a high quality 4:1 Balun. Mike assembles a Buck/Boost converter device for use with QRP operations.

КОМЕНТАРІ • 6

  • @ipklondonuk
    @ipklondonuk 10 місяців тому +3

    I had a real busy day before this episode, I checked into the chatroom and even said hello to Emile, saw the start fell asleep then woke up and the very end of the night, looking at this I missed an excellent episode

  • @f4hwn
    @f4hwn 7 місяців тому +1

    Thank you for talking about my M5HamRadio project on M5Stack. That's very kind of you 😌 I'd like to add an information. No, it's not the same project as the one you saw in Dayton. I'm the first one, in 2019, who decide to develop cool stuff on M5Stack, for the Ham radio community. My project M5HamRadio is available for free, as you can see in the video. I'm not selling anything. I'm giving it to the community. The other project is a bad copy, sold at a high price and offering poor performance. Thank you again for this video and 73' de F4HWN Armel 🙏🏻

    • @AmateurlogicTv
      @AmateurlogicTv  7 місяців тому +1

      Thanks for bringing this and your other great project to the Ham community!

    • @f4hwn
      @f4hwn 7 місяців тому

      @@AmateurlogicTv With pleasure, I try to do my best 😌

  • @davetelling
    @davetelling 10 місяців тому

    Re the buck/boost converter: keep in mind that if the battery is discharged to the point that the voltage has dropped noticeably, when you run a load, the INPUT current will be greater than the OUTPUT current if the output voltage is higher than the input voltage, which means that you will discharge the source battery more quickly. As an example, let's assume a converter efficiency of 90%. If you have the output voltage set to 13.5 volts, and you draw 5 amps, that works out to 67.5 watts. with 90% efficiency, the input power will be 75 watts. If your supply voltage is 12.2 volts, you're pulling 6.14 amps from the battery. This may or may not be a problem, but it's definitely worth keeping in mind. The efficiency in boost mode is very dependent upon load current, and peaks at about 95% at a 1 amp load, and falls off either side of this (according to the Linear Tech data sheet).