Harmonic Balance Analysis of Nonlinear RF Circuits

Поділитися
Вставка
  • Опубліковано 24 гру 2024

КОМЕНТАРІ • 13

  • @tensorbundle
    @tensorbundle 7 років тому

    Hi professor thanks for the webinar. I am currently working on a cmos freq doubler and running cadence's HB. Your lecture helped me a lot to understand the underlying principle. Your book is also excellent, easy to follow and enriched with insightful explanation. Thanks

  • @holydoragon
    @holydoragon 10 років тому +1

    Hi, at 23:20, how did you solve for I_0, I_1, and I_2 for the nonlinear subcircuit? Could you give an example calculation for I_0? I used trigonometric substitution to evaluate the [v(t)]^2 term, and I get a 4th harmonic from that and you drop that term as you say in your next slide, but I think that's the only part that we could agree on.

    • @michaelsteer343
      @michaelsteer343  10 років тому

      I used MATLAB. If you want to follow this along you need to look at the section referred to in the book. Lot's more explanation there.

    • @colin_hart
      @colin_hart 6 років тому +2

      I'm looking at p. 923 in the second edition of the book and I am also struggling to follow along. The only explanation in the book is "The linear subcircuit and the nonlinear subcircuit described by the quadratic model result in the following equations."
      I calculate by substituting v(t) into i(t) = v(t) + [v(t)]^2, expanding the expression and grouping phasors in terms of DC, cos(wt), cos(2wt), etc. as explained:
      I0 = V0 + V0^2 + 1/2*V1^2 + 1/2*V2^2
      I1 = V1 + 2*V0*V1 + V1*V2
      I2 = V2 * 2*V0*V2 + 1/2*V2^2
      I3 = V1*V2 (neglected)
      I4 = 1/2*V2^2 (neglected)
      However the book (19.5) and this video (23:30) give:
      I0 = V0^2 + 1/2*V1^2
      I1 = 2*V0*V1 + V1*V2
      I2 = 1/2*V2^2
      These terms appear in what I calculated but there must be some justification for discarding the remaining portion. The system of differential equations at (32:10) is satisfied by the equations I found so I believe that the remaining portion is necessary.
      Further inspection shows the equations with all terms present in (19.14).
      I'm not sure if there is a subtlety I am missing or if the equations in (19.5) are just incomplete.

    • @FigoMaluco
      @FigoMaluco 6 років тому

      Hello everyone,
      I also solved with trigonometric substitution and there is a lot of variables that are not assigned for some reason that i did not find out.
      Could you please tell me what I'm missing?
      My trigonometric resolution is on the link below:
      drive.google.com/file/d/1w8xdCCbi8cejjh0CrIIg4XYrGI5DpPv6/view?usp=sharing

    • @FigoMaluco
      @FigoMaluco 6 років тому

      Hi Colin Hart,
      Did you find anything ?

    • @colin_hart
      @colin_hart 6 років тому +1

      My work was still on my whiteboard, so here's a photo: imgur.com/csF6ZCs

  • @RahulSharma-qz2vj
    @RahulSharma-qz2vj 4 роки тому

    @Michal Steer , what is wrong if I directly solve for V0, V1 and V2 on slide 2 (Around 25) and got solutions i.e. V0 = -00390V, V1 = -0.125 V and v2 = 0.5 v.

  • @Scuba_Bro
    @Scuba_Bro 3 роки тому

    great webinar! your textbook has really taught me a lot even after using it during grad school.

  • @amalelghailani3258
    @amalelghailani3258 5 років тому

    Great explanation, thank you so much Sir. Can i have the matlab code with which you did the calculations?

  • @Kenobiii
    @Kenobiii Місяць тому

    This is a great video explanation!