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Class - 10 Ex - 8.1 Q7 Maths (Trigonometry) NCERT CBSE
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- Опубліковано 12 жов 2020
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Plz sir application to trigonometry ka bhi video banaye
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Easy method to solve this question
=1-sin²Q / 1-cos²Q
=cos²Q / sin²Q
=cot²Q
And as we know that cotQ=7/8
So, cot²Q=(7/8)²
=49/64
(Q= THETA)
8:12
Yes sir please complete these chapter fast🙏🙏🙏🙏
Good
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Inshallah
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Sir make a video of reduced syllabus class 10th.
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Sir why can't we cut 113 up and down insted of talking LCM?
yes i was also thinking same
We need 49/64
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Sir agar hmm 1st part me 1-sin square thita ko cos square thita likhte or niche 1-cos square thita ko sin square thita likhte to ye cos square thita/sin square thita ho jata jisse hmm cot square thita likh sakte hai cot ki value hme de rakhi hai 7/8 iska square Kate to 49/64 ata or ye ek sath dono hi part nikal jate (🤔ek teer se do nessane )
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