Lecture 19: Review of Fluid Mechanics - I

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  • Опубліковано 8 лис 2024

КОМЕНТАРІ • 9

  • @rafaelaguilar3107
    @rafaelaguilar3107 8 років тому +8

    The classroom is very different compared to the ones where other lectures of these two teachers are given. First i though they were at MIT or kind of. Excelent techers by the way, i learn of them from Mexico.

    • @conductionandconvectionhea6729
      @conductionandconvectionhea6729  8 років тому +5

      +Rafael Aguilar These lectures are recorder as part of the 3rd year BTech course Heat Transfer at IIT Kharagpur, India.

  • @amardongare9909
    @amardongare9909 3 роки тому +1

    Wonderful , wonderful , wonderful.

  • @btechbalusu3444
    @btechbalusu3444 4 роки тому

    Awesome lecture

  • @sayandeepsom3610
    @sayandeepsom3610 8 років тому +1

    Dear Sir...I have a question regarding the relation Nu=Nu(Re,Pr)........It is easily see that as Re increases Nu increases but what about the Pr=Kinematic Viscosity/Thermal Diffusion .As Kinematic viscosity increases heat transfer decreases so is the case with thermal diffusivity as that leads to an increase in thermal boundary layer and hence low heat transfer..so how are these to combined together to be a function of Nu.......

    • @bashamsk1288
      @bashamsk1288 7 років тому

      Sayandeep Som prandtle number is given to fluid it never changes for a fluid, its a property

    • @mohanishrocks
      @mohanishrocks 5 років тому +2

      For a particular value of fluid velocity and characteristic length L, as the kinematic viscosity increases, Reynolds number decreases and hydrodynamic boundary layer increases. But this data just gives us the information about the nature of the flow.
      Also for a particular fluid, the Prandtl number is constant and equal to ratio of hydrodynamic and thermal boundary layer.
      So if hydrodynamic boundary layer increases, the thermal boundary layer has to increase.
      Thus we see that to obtain the correlation between velocity and temperature profile, we need to have both Re and Pr values, and hence Nu = Nu (Re,Pr).

  • @sahilrajeshgajbhiye4968
    @sahilrajeshgajbhiye4968 3 роки тому +1

    ty very much sir

  • @rushikesh7408
    @rushikesh7408 4 роки тому +1

    Last kuch samaj hi nahi aya