Thank you! I'll be making a more complete video when they post the full trajectory data from Earth to L2. As of now they only have posted predicted trajectory until January 22.
This is a great video that helps figure out the size of the halo orbit itself Thanks a lot for making it availalble ! Looks like the diameter of the halo orbit is about the same as the distance from Earth to L2, so that its apparent diameter would be 60°... Why so big? Is there a reason for that? Do you have a more precise figure? Thanks in advance !
I'm actually currently working on a Circular Restricted 3 Body Problem video series! Here is the latest video covering the gradient of the pseudo-potential function in the rotating reference frame: ua-cam.com/video/qWZpJGmpi8g/v-deo.html In the video there is a plot showing the instability of trajectories near the co-linear lagrange points (L1,L2,L3) and the stability of of trajectories near L4 and L5. I haven't gotten far enough into the math to give you a precise answer, but my understanding is that even though L2 itself isn't stable, halo orbits around it are, and I'm guessing they chose that size due to stability and to stay out of the Earth's umbra. For the diameter, it actually looks right about roughly 1.5 million km, as you observed. Here is a plot of it in the Earth-centered Earth-fixed frame IAU_EARTH on a Space StackExchange question I just answered today about it: space.stackexchange.com/questions/57417/how-can-i-find-the-old-reference-orbit-for-jwst-from-2014-and-get-altaz-positi Also here is a video on the linear algebra and geometry of umbra and penumbras, and how to calculate when a spacecraft is in eclipse: ua-cam.com/video/LeJpWfyXJPw/v-deo.html
This is explained by Nasa like this: An orbit is easier to hold, also with such a large orbit it has never a sun eclipse by earth, which could get the instruments too cold and course energy issues. one orbit will take 6 months!
My understanding is that the most important requirement is that JWST's sun shield is always pointed directly at the Sun. Also this animation is really sped up, the velocity w.r.t the rotating frame is actually quite slow. However I think staying pointed at the sun is much easier than the full pointing requirements of JWST since its looking so far into the universe
@@alfonsogonzalez-astrodynam2207 Thanks. I've found it is synchronous with the halo orbit (one orbit = 6 months); otherwise I would not see all around. It does seem somewhat quick since 2 halo orbits happen per year. The back of the scope (deflector shields) are always facing the sun. Thanks
@@louf7178 i just rechecked the script, time is at 450,000x regular time. I didn't wanna make it faster because since it's in the rotating frame it could make people dizzy seeing the universe rotate in the background, which is also why I dimmed the stars
Its moreso the dynamics of the 3 body problem, you can't really have planar orbits unless they lie on the x-y plane of the CR3BP rotating frame (the plane containing the orbit of the Sun and Earth). Here is an example of Orion's planned near-rectilinear halo orbit (NRHO) that has that similar feature: ua-cam.com/video/60Ib6U4v7BE/v-deo.html
It Kinda sucks that the universe is so big, it doesn't even seem that James is going that far away in the grand scheme of things. There's gotta be a way to travel space time faster. Why would it be this big? Makes no sense there's gotta be a way
I'm not a physicist so I can't answer your great questions but as far as JWST, its significance isn't _where_ it is but how far it can see. It's actually going to be able to see to the beginning of the universe, and is sensitive enough to detect 1 photon per second (which is insane) As far as why our universe is so big, the only ones that can answer that are the beings who wrote this simulation 👀👀👩🏻💻
Lagrange point 2 of the Sun Earth system. I'm making a video series on the circular restricted 3 body problem and the Lagrange points derivations is 2 videos away. Here is the introduction video: ua-cam.com/video/fKYm6osKG-k/v-deo.html
Amazing
This is brilliant. Great way to show JWST TRAJECTORY.
Thank you! I'll be making a more complete video when they post the full trajectory data from Earth to L2. As of now they only have posted predicted trajectory until January 22.
This is a great video that helps figure out the size of the halo orbit itself Thanks a lot for making it availalble ! Looks like the diameter of the halo orbit is about the same as the distance from Earth to L2, so that its apparent diameter would be 60°... Why so big? Is there a reason for that? Do you have a more precise figure? Thanks in advance !
I'm actually currently working on a Circular Restricted 3 Body Problem video series! Here is the latest video covering the gradient of the pseudo-potential function in the rotating reference frame: ua-cam.com/video/qWZpJGmpi8g/v-deo.html
In the video there is a plot showing the instability of trajectories near the co-linear lagrange points (L1,L2,L3) and the stability of of trajectories near L4 and L5. I haven't gotten far enough into the math to give you a precise answer, but my understanding is that even though L2 itself isn't stable, halo orbits around it are, and I'm guessing they chose that size due to stability and to stay out of the Earth's umbra.
For the diameter, it actually looks right about roughly 1.5 million km, as you observed. Here is a plot of it in the Earth-centered Earth-fixed frame IAU_EARTH on a Space StackExchange question I just answered today about it: space.stackexchange.com/questions/57417/how-can-i-find-the-old-reference-orbit-for-jwst-from-2014-and-get-altaz-positi
Also here is a video on the linear algebra and geometry of umbra and penumbras, and how to calculate when a spacecraft is in eclipse: ua-cam.com/video/LeJpWfyXJPw/v-deo.html
This is explained by Nasa like this: An orbit is easier to hold, also with such a large orbit it has never a sun eclipse by earth, which could get the instruments too cold and course energy issues. one orbit will take 6 months!
Hey, what do you use to display these orbits? Is this a software or a website?
Will JWST rotate about its own axis as it rotates about the halo-orbit's axis? Or is JWST always "upright"?
My understanding is that the most important requirement is that JWST's sun shield is always pointed directly at the Sun. Also this animation is really sped up, the velocity w.r.t the rotating frame is actually quite slow. However I think staying pointed at the sun is much easier than the full pointing requirements of JWST since its looking so far into the universe
@@alfonsogonzalez-astrodynam2207 Thanks.
I've found it is synchronous with the halo orbit (one orbit = 6 months); otherwise I would not see all around. It does seem somewhat quick since 2 halo orbits happen per year. The back of the scope (deflector shields) are always facing the sun.
Thanks
@@louf7178 i just rechecked the script, time is at 450,000x regular time. I didn't wanna make it faster because since it's in the rotating frame it could make people dizzy seeing the universe rotate in the background, which is also why I dimmed the stars
Why is the orbit so slanted compared to the solar plane? Isn't a 90-degree halo orbit plane a more straightforward approach?
Its moreso the dynamics of the 3 body problem, you can't really have planar orbits unless they lie on the x-y plane of the CR3BP rotating frame (the plane containing the orbit of the Sun and Earth). Here is an example of Orion's planned near-rectilinear halo orbit (NRHO) that has that similar feature: ua-cam.com/video/60Ib6U4v7BE/v-deo.html
It Kinda sucks that the universe is so big, it doesn't even seem that James is going that far away in the grand scheme of things. There's gotta be a way to travel space time faster. Why would it be this big? Makes no sense there's gotta be a way
I'm not a physicist so I can't answer your great questions but as far as JWST, its significance isn't _where_ it is but how far it can see. It's actually going to be able to see to the beginning of the universe, and is sensitive enough to detect 1 photon per second (which is insane)
As far as why our universe is so big, the only ones that can answer that are the beings who wrote this simulation 👀👀👩🏻💻
@@alfonsogonzalez-astrodynam2207 🤣🤣🤣
There is a way. We will find it in the next few centuries. Scientists are working on it.
what is sun earth L2?
Lagrange point 2 of the Sun Earth system. I'm making a video series on the circular restricted 3 body problem and the Lagrange points derivations is 2 videos away. Here is the introduction video: ua-cam.com/video/fKYm6osKG-k/v-deo.html