That….is about the best teaching I’ve ever seen in math. Everything about this example was beautiful. The pacing, explanation, cohesiveness…if the world had more people to explain concepts like this we’d be a far more developed species.
After viewing several videos, reading it in my textbook and trying over and over again... your simple explanation filled in the gaps in my understanding merely 5 min and 14 sec into the video - what a *¡RELIEF!* I wanted to bang my head into a brick wall. So, *_THANK YOU_* you for recording the explanation, *_THANK YOU_* for uploading the video and *_THANK YOU_* for leaving it up!! Really appreciated! 👍👏🤝👊🤓
I noticed something important when you calculated the projection, you did not divide by the magnitude of the project-on orthonormal vector. There should be two normalization steps in each orthonormalized vector in the Gram-Schmidt method; one for the projection and one to obtain the new orthonormal victor uk. However, your solution is correct, not sure how it was accounted for the first normalization step, but I think it should be highlighted. Thanks for the video.
The inproduct of v1 and v2 is already 0, cant you just leave it out? (2x-2 + 2x1+ 2x1 = -4 + 2 + 2 = 0), so you only have to translate v3? that is what was taught to us in school. I dont know if this is right that is why I am asking
The U1 that your doctor used was not a normalized vector. Therefore, when computing U2 the form would be different from that in the video. The expression of U3 in your lecture would probably be V3-((U1.V3)/(U1. U1))U1 -((U2.V3)/(U2.U2))U2. After normalizing U1,U2 and U3, the answer would be as same as the one in the video.
No color on your chalk, what you write on the board not visible correctly, talk the important word slowly and clearly and emphasize on it, don´t think you covered, think your listener received it correctly or just head it.
Strange video. You don't need to use Gram-Schmidt or do any calculations at all to find an orthonormal basis for Span (v1, v2, v3), which is in fact R3. Just take the standard basis for that vector space, i.e. ((1,0,0), (0,1,0), (0,0,1)).
"the length of v is 2^2+2^2+1. So that's 9. Then the square root of that is 3." This was the one step that every other video like this skips or doesn't explain very well. Still, would have been nice to throw that important bit on the board maybe.
You came here to study not to read comments, go back!!
I needed to see this
@@B.R.L. lmao it's been three years
@@tameyofujoshi lol and your comment still helps people like me too this day 😭. Thank you
That….is about the best teaching I’ve ever seen in math. Everything about this example was beautiful. The pacing, explanation, cohesiveness…if the world had more people to explain concepts like this we’d be a far more developed species.
preach!
so logical
better than all videos i watched about gram schmidt
watching this 3 hours before my linear algebra exam. perfect! right to the point. thanks a lot!
did u pass ? :d
Watching this an hour before mine 7y later. God help us all🫠
After viewing several videos, reading it in my textbook and trying over and over again... your simple explanation filled in the gaps in my understanding merely 5 min and 14 sec into the video - what a *¡RELIEF!* I wanted to bang my head into a brick wall. So, *_THANK YOU_* you for recording the explanation, *_THANK YOU_* for uploading the video and *_THANK YOU_* for leaving it up!! Really appreciated! 👍👏🤝👊🤓
This just saved my life was completely lost in class but now I understand! Thanks so much
I hope the best for this man, such a fantastic teacher
thank you for saving my linear algebra this semester
You guys explain linear algebra better than the big names like Khan Academy imo. Thanks so much for the video!
thank you for helping me pass my math class! amazing
I noticed something important when you calculated the projection, you did not divide by the magnitude of the project-on orthonormal vector.
There should be two normalization steps in each orthonormalized vector in the Gram-Schmidt method; one for the projection and one to obtain the new orthonormal victor uk.
However, your solution is correct, not sure how it was accounted for the first normalization step, but I think it should be highlighted.
Thanks for the video.
You are great, thank you for this description! Helped a lot!
Thanks you just helped me prepare for my final.
best method is to solve a problem b4 anything else... tnx👌
Excellent presentation!
Hi, thank you so muchhhh really helpful tho, in the textbook is so difficult to understand and you explain it clearly
Thank you! May Allah guide you with the best gift ever!
I really needed this. Thank you
I am Pakistani sir very good method of explaination
Thank you so much! best video on the subject
you the best man..thanks alot
THANK YOU SO MUCH FOR THIS.
The inproduct of v1 and v2 is already 0, cant you just leave it out? (2x-2 + 2x1+ 2x1 = -4 + 2 + 2 = 0), so you only have to translate v3? that is what was taught to us in school. I dont know if this is right that is why I am asking
i would like to ask you some questions my doctor give us e that U1=V1 and U2 = V2 - (V2.U1/U1.U1) .U1 is it the same or what ? and thanks in advance
The U1 that your doctor used was not a normalized vector. Therefore, when computing U2 the form would be different from that in the video. The expression of U3 in your lecture would probably be V3-((U1.V3)/(U1. U1))U1 -((U2.V3)/(U2.U2))U2. After normalizing U1,U2 and U3, the answer would be as same as the one in the video.
It helps to write little notes in a notebook to follow along. .
Thank you so much!! It was worth to watch it :)
Why did you use the transpose of v2 when finding u2?
I was wondering the same. Somebody please help out..
Can you sing like George Ezra?
very good question
thanks, i was on a verge of having a breakdown before this
great work thank you
nice job
muy buen video me gusto mucho! gracias
You are Genius
thanks bro... u save me.
Thank you it was useful
thank you, thank you, thank you
really appreciate thank you so much
Thank you so much guy!
great ,thanks
Nice, thanks.
Glad we could help! Check out centerofmath.org for more video tutorials and lectures!
very neat ! thanks
Thank you.
isn't the order of that matrix multiplication wrong??
Ahmad Hasan where?
It is wrong
@@schnekec Which part?
thanks king
amazing!!!!
sick bro thanks
THANKS SOO MUCH
Thanks!!
thank you
exelent men
No color on your chalk, what you write on the board not visible correctly, talk the important word slowly and clearly and emphasize on it, don´t think you covered, think your listener received it correctly or just head it.
Perfect video! Pls replace my teacher!!!!!
thx G
Thank you so much. I'm from Israel! I would like to know if you have example for orthagonal
You are obstructing what you are writing
thx mate ^.^
him having glasses at the end threw me off.. but great video!
Strange video. You don't need to use Gram-Schmidt or do any calculations at all to find an orthonormal basis for Span (v1, v2, v3), which is in fact R3. Just take the standard basis for that vector space, i.e. ((1,0,0), (0,1,0), (0,0,1)).
I have an exam in 20 mins. Wish me luck please
he is so cute :D
Mathematicians create something out of nothing.
just wow
I think, wrong formula because we learn u2=v2-((v2|u1)) /((u1|u1)) u1.
"the length of v is 2^2+2^2+1. So that's 9. Then the square root of that is 3." This was the one step that every other video like this skips or doesn't explain very well. Still, would have been nice to throw that important bit on the board maybe.
Covering the blackboard while he writes, just mumbling through the computations, mentally skipping steps with no vocalization...
thanks. but in your next video , note tht others should be seeing what you are are doing. you are not transparent
Very poor video coverage and explanation. Mind how you position yourself when on the blackboard because you're not teaching yourself
thank you
You are obstructing what you are writing