You're welcome! It's always great to have the mathematical background, but sometimes examples are better than just abstract math on the whiteboard/blackboard :)
Nice job with the derivation, as i could follow along. Instead of integrating, could you have substituted acceleration using the kinematic eqn for acceleration V^2=V0^2+2as?
I led to the same answer that u find. this is not constant acceleration problem. at 5:25 u cannot substitute by 0.5m and find the acceleration and use that acceleration to find velocity by using equ. of motion. I will not saying that the acceleration that you find is wrong, but the acceleration during movement is changing because the resistance of spring is increasing by distance traveled.
im so glad i can find this on yt cuz my teacher teach us be like reading a book. btw thank you so much for posting this on yt
You're welcome! It's always great to have the mathematical background, but sometimes examples are better than just abstract math on the whiteboard/blackboard :)
Nice job with the derivation, as i could follow along. Instead of integrating, could you have substituted acceleration using the kinematic eqn for acceleration V^2=V0^2+2as?
what did you do to (v^2)/2? you shoulda multiplied the other side by 2 then taken square root if I'm not wrong. check the final answer again
Yes you're correct on that. I might have skipped that step on the video but did it in my calculator. Thanks for pointing that out though.
why is it my answer in vf= 3.708?
I led to the same answer that u find.
this is not constant acceleration problem.
at 5:25 u cannot substitute by 0.5m and find the acceleration and use that acceleration to find velocity by using equ. of motion.
I will not saying that the acceleration that you find is wrong, but the acceleration during movement is changing because
the resistance of spring is increasing by distance traveled.
how did you get that 50s/2?
the (50s^2)/2 comes from the integration of 50s ds
thanks. great video btw