our school didn't taught about this topic so here i am studying, this is so crucial to the course that i'll choose next year. and your video lessons really helped me a lot, thank you sir~
I loved that you mentioned that there is a angle between vector and axis where the vector is above the plane. People confuse either the angle is with vector or projection.
I think instead of calculating cosines with calculator you can add everything up by fraction, since common denominator is 56, after all the fractions have been squared, the sqrt signs cancel. The squares of numerators add up to whatever's inside of the square root. Thus 56/56 =1
I wish I could see where the x, y, and z components really are. I think I understand why cos of those angles = the x or y component over the magnitude of the vector, but I just don't see how the z component is "adjacent" to the angle you drew out (thus fulfilling cos angle = adjacent side/hypotenuse). I wish you can draw the "triangles" the vector makes with its components to clarify it
As you said, the vector A does not lie in the XY plane. What I would like to know is, is the angle that it makes with X or Y axis dependent on it's Z value or we might as well consider it to be in XY plane when calculating A? I am not able to visualize it.
In which video did you explain: Cos of a given component A in the X direction for example is A(x) / A I’ve seen all of the videos in this playlist but I haven’t seen you explain why we divide A(x) / A to get cosA
This video shows you how that works in 2 dimensions (which makes it easier to see). Physics - Advanced E&M: Ch 1 Math Concepts (3 of 55) Direction of a Vector, Direction Cosines ua-cam.com/video/0yIvQ4pz4DA/v-deo.html Let us know if that helps.
It gives square of magnitude of unit vector(as magnitude of unit vector is one, therefore square of one is also one) (as you know cosa =(Ax/A) & cosb=(Ay/A) & cosr=(Az/A)
I just love your teaching, whether its physics or linear algebra, your always find a way to explain it so well.
our school didn't taught about this topic so here i am studying, this is so crucial to the course that i'll choose next year. and your video lessons really helped me a lot, thank you sir~
You are explaining that good that with barely B2 english level and on the speed 2x I understand everything! I am not even studying yet
studying - uni
Thank you. Glad you find our videos helpful. 🙂
Good Job.
Same thing for me!😂👌
I loved that you mentioned that there is a angle between vector and axis where the vector is above the plane. People confuse either the angle is with vector or projection.
A really talented teacher! very straightforward video that saved me a lot of time.
Glad you found our videos! 🙂
Thank you. I couldn't understand it until I found you
You are welcome! Glad you found our videos.
Thanks Professor, you made me fully understand two syllabus, Physics and Linear Algebra
You are most welcome. Glad you found our videos.
Thank you so much..." MICHEL"...I will ONLY say ..you are simply a great flow maker..... Really Great....
Another educational masterpiece.
Thank you. Glad you find them interesting.
Thank you for the help! The first minute of this video saved me on this topic.
I think instead of calculating cosines with calculator you can add everything up by fraction, since common denominator is 56, after all the fractions have been squared, the sqrt signs cancel. The squares of numerators add up to whatever's inside of the square root. Thus 56/56 =1
Yes, that works as well.
I wish I could see where the x, y, and z components really are. I think I understand why cos of those angles = the x or y component over the magnitude of the vector, but I just don't see how the z component is "adjacent" to the angle you drew out (thus fulfilling cos angle = adjacent side/hypotenuse). I wish you can draw the "triangles" the vector makes with its components to clarify it
I thought this would be hard because of trig functions, but it's actually very easy. Thank you sir.
Big up 👍 ma teacher u made me understand this topic accurately
Glad you found our videos.
Beautiful presentation! ❤
Thank you.
You are a wonderful teacher. Thanks a lot!
Thank you. Glad you are finding these videos helpful. 🙂
As you said, the vector A does not lie in the XY plane. What I would like to know is, is the angle that it makes with X or Y axis dependent on it's Z value or we might as well consider it to be in XY plane when calculating A? I am not able to visualize it.
Thank you sir...I really appreciate this
You are most welcome 🙂
Love from India🇮🇳🇮🇳🇮🇳
At 5:56 you are right but you can't round the figures off.
You make math fun
Glad you found our videos and you are now enjoying the math. 🙂
In which video did you explain:
Cos of a given component A in the X direction for example is A(x) / A
I’ve seen all of the videos in this playlist but I haven’t seen you explain why we divide A(x) / A to get cosA
This video shows you how that works in 2 dimensions (which makes it easier to see). Physics - Advanced E&M: Ch 1 Math Concepts (3 of 55) Direction of a Vector, Direction Cosines ua-cam.com/video/0yIvQ4pz4DA/v-deo.html Let us know if that helps.
@@MichelvanBiezen oh ok perfect. I will check it out!
Thank you!
And then if you're asked to find the angle that the vector makes with the x-axis, you can just take the arccos of alpha... Sweet, great video!
You’re amazing…soooo smart!
Thank you! Cheers!
so the direction cos of a vector is it's normal?
Thank u. It helped me
thanks so much for this video
awesome and straight forward
if the vector A= -4i-6j-2k then I should write cosa= -4/(magnitude of vector A) or cosa= +4/(magnitude of vector A)
Why do the sum of the squares equal 1?
By definition, the length of a unit vector is "1".
How to prove this cosθ = (cosα)(cosα') + (cosβ)(cosβ') + (cosγ)(cos γ') ?
Legend! Thank you!
Hakem Yasin Türk 😀 üni bitti mi 😂😂
Why is sum of sq of dcs is 1
Just like in trigonometry, the trig functions are based on the unit circle (in 2-D), in 3-D everything in based on the unit sphere (with radius 1)
Michel van Biezen thank u so much .. it gave me a new perspective
It gives square of magnitude of unit vector(as magnitude of unit vector is one, therefore square of one is also one) (as you know cosa =(Ax/A) & cosb=(Ay/A) & cosr=(Az/A)
You don't have to plug in the numbers into the calculator as you can do some simple algebraic fraction manipulations. They all cancel out in the end😅
But it is useful as a demonstration and to aid in the understanding.
Play lplay list abnormal,
Other chapter has mixed up .
Hi . The expression you suggested (cosa)^2 +(cosb)^2+(cosb)^2=1 true but a^2+b^2+c^2=1 is seem to be false considering a,b,c are angles in radiants
It is correct if alpha is defined as cos(a)
I started solvin incorrectly by using your last equation in your thumbnail. I advise you next time make sure to put clear stuff on your thumbnail.
Exactly
Your thumbnail is wrong buddy
The thumbnail is fine. Thanks for checking.
@@MichelvanBiezen it’s not clear buddy
niceeeeeeeeeeeeeeee
YOUR THUMBNAIL IS WRONG!!!
You look like Vladimir Putin
I HATE PHYSİCS as a cse student WHY I HAVE TO LEARN IT
Why do we learn anything? In the end, increasing one's knowledge offers more opportunities and more capability.
GAMES