calculate the magnitude of the electric field at the center of a square
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- Опубліковано 9 лип 2016
- Calculate the magnitude of the electric field at the center of a square 2.0 cm on a side, if one corner is occupied by a 14 µC charge and the other three are occupied by 8.0 µC charges.
Great explanation!!! I have physics test tomorrow and you saved my life. Thank you
Excellent explanation and the idea of briefing about the required concept is superb.. Please continue doing that.
Bless u, I was so confused for my lectures. Thank you!!
Thank you! Your explanations helped a lot
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You must convert to meters before you begin your calculations to gain the correct answer. Since 2cm is .02meters when you square and take the square root of .02meters it is not the same as just taking 2cm root 2cm dividing it by 2 and then squaring that which is 2cm and then converting and saying it's .02meters when it reality it's .0002 meters
Thanks I thought I was doing it wrong.
That’s what I’m thinking too
Then the answer should be: 1.91 *10^8 N/C…
Thanks so much for this wonderful explanation. What if they give you positive and negative charges .for example ,top left of the square +q,bottom left -q and top right of the square -2q,bottom right +2q .then we are told to find the direction and electric field at the center of the square?
Good Explanation!!
Can I know from where did you get this exercise?
(the name of the book)
Very helpful, went into more detail than I needed but would apply to a wide variety of students
Thank you for the feedback!
Very detailed = Very helpful = Great video = Thank you
+mustafa rashad = You're welcome!
what if one of the charges are negative would the electric field arrows instead of being in the opposite direction would it be towards the charge?
Hello there,
I have a question regarding the lengths of this problem. Why wouldn't you convert to the meter before doing the hypotenuse? I tried converting first (which to me makes sense) and I got a different answer,
Would you elaborate, please?
The net charge is (14-8) μC or 6 μC pointing away from the larger charge at π/4 or 45 degrees (+- depending on how you draw your diagram.) The distance between the vertex and center is 0.01*sqrt(2) m. The net charge or the electric field E at the center is (k*6*10^-6)/(0.01*sqrt(2))^2 = 269632 N/C
hey what about if the charge is negative for both ? How the result is going to change?
Very well explained thanks
great explanation!!
very helpful, thank you so much.
Thank you!
What if the charges are 5 , -5 , -5 , -5 microcoulom???
If all four charges were negative, then the direction of the electric field would change.
I'll modify this problem and use it as an example.
So q1= -14μC and q3= -8μC
q2 and q4 would still cancel, so you can still ignore them.
Now the electric field line of q1 is pointing toward q1 (tail is at center, head is at q1) and the electric field line of q3 is similarily facing itself (tail at center, head at q3).
Since the fields are pointing away from the center, the net electric field will be equal to "larger electric field - smaller electric field".
Since q1 has a larger magnitude of charge, it will have a stronger electric field.
so we need to do E1- E3 = (k/r^2)*(q1-q3). r is half the diagonal length, not half the side (mistake i kept making).
You do not need to break the electric field vectors into their components. To understand why, imagine tilting the square so it is a diamond. q1 and q3 are now on a linear line, hence no y-component.
If all of them are negative then also the ques will be solved the same way, because -ve and -ve also repel each other
If the two other charges cancel out, Why can't you take the Total Field Charges of the two remaining as if they were on the same super positioned line. why do we have to take the cos and the sin
You're right, symmetry is valuable with these kinds of problems. Here, all you need to know is distance to the center, and the charge left after superposition.
You have Q=6E-6C due to superposition. Distance to center is a^2+a^2=c^2...
So, c/2 = sqrt(2)*a/2 = a/sqrt(2) distance to center, where a=.02m.
So r= .02/sqrt(2)
Plug these two values into the electric field equation to get your answer (2.7E6).
THANK YOU!!!!
Why can't we just subtract E3 from E1 . As they are in 180 degree direction to each other.
Thank you WNY tutor. It was helpful.
ya its very helpful.. thanksss
Thank u so much
Good explanation 👍👍👍
Well explained thank you
a charge of 5 μc is placed at each corner of a square 0.2 m on a side. calculate the magnitude and direction of the net force on each charge.
bless u young man
Thanks sir
what should we do if we want to calculate electric field at any point outside of the square?
find the distance between the point outside the square and each of the charges and then use the superposition principal the procedure should be similar to the example in the video but the distances and directions will be different, also the electric force weaker i guess
@@maryia6542 thanks but i've already graduated :)
Thanks....
so what is if the charge was negative.
Abdul-Aziz Muhammad the vector line will be in the opposite direction, maybe.
Good
should be m^2
wow
who's watching this on 2019
Alexandrei Quilala 2020
I’m on 2024 😭😹
Please edit out your mouth lip/tongue smacking sounds cause it’s really distracting for a good informative video
+Leen Please be grateful when others show you how to do your homework.
WNY Tutor I said it’s a good informative video. However for us people with severe mesophonia (google it please) it’s a hard struggle to find a good video that doesn’t trigger us, and this is a good video, just extremely triggering and hard for a mentally ill kid who just wants to do their homework xx I apologize for the rude comment I was I guess just very upset then and I feel bad for commenting that I just want to raise more awareness at the issue, it’s nothing personal, any sound can tick us off no matter who or what. 😌
@@leen4093 That isn't his problem. That's your problem. If you are able to be bothered by something that most others are not bothered by, then you must use some common sense and realize that it would not even occur to him or anyone else to edit out noises that will trigger you. For that matter, if the rest of us don't even notice it then how can he edit out sounds that aren't even noticed by him or everyone else? It must suck that you have such a disorder, but it is not his responsibility to walk on egg shells for you. If his video triggers you, then find another one. Your comment was very much a rude one and if you can't see that then you have greater problems then a mental disorder. Be grateful for the help he provides and don't expect others to walk on egg shells because you have issues with noises that the rest of us won't even notice. Your issues are for you to deal with, not him or anyone else. So deal with them. With that said, if you need help with physics then the organic chemistry tutor is a good one. If you have issues with him making noises though then keep your mouth shut about it. I've seen hundreds of his videos at least and have had no issues so if you do, then perhaps you should just get off of youtube and stick to the book, or mute the video entirely because those issues are beyond anyone's ability to do anything about.
Thank you!
You're welcome!