Awesome video. Great to see 3 different ways to go about this problem. Technique 1 is very helpful as it gives practice to 4 "topics" in 12.5. Thanks for the video!
actually, with the 2nd method, you don't need to calculate t at all. you just need the minimum module of that vector, that is, minimize a quadratic equation. you know that the minimum is found at (-b/2a, -delta/4a), so the answer will be sqrt(-delta/4a). anyway, very good explanation :D
By far the most extensive, helpful and intuitive method on finding the distance of a point to a line in 3D. Thanks!
Helped me for the unit test a few months ago, and now for the exam. Thank you very much!
That last method we use explains it so well!
Awesome video. Great to see 3 different ways to go about this problem. Technique 1 is very helpful as it gives practice to 4 "topics" in 12.5. Thanks for the video!
This was an excellent video! You have superb teaching skills!
actually, with the 2nd method, you don't need to calculate t at all. you just need the minimum module of that vector, that is, minimize a quadratic equation. you know that the minimum is found at (-b/2a, -delta/4a), so the answer will be sqrt(-delta/4a). anyway, very good explanation :D
Great man, thanks!!
what a legend, thanks a lot
Awesome video...really helpful!!! :)
Fucking awesome
Really nice video.
thank u vry much...:)