Difference Equation || Solution using Z- transform || Part 3 || Dr. Abhishek || RSC

[@christsri]

Dr. Abhishek is very knowledgeable and great in teaching. His teaching skills are well known from his PhD days at IITM

[@rudrastudycircle1572]

Thanks Sriram

[@ruhulaminrobin1840]

Determine the total solution of the following difference equation:
y(n)= 5y(n)-6y(n-2)+x(n)
when the forcing function , x(n)= 3^n and initial condition , y(-1)=2 & y(-2)=4.
Also, draw the difference equation using building blocks. sir answer please

[@akshatbhatia9364]

love u

[@SayantiMaulik]

i think sir z[n^3]=(z^3+4z^2+z)/(z-1)^4. Plz review the solution once more. Thank You

[@sohambangar132]

Sir at 5.02 min how did z^2-z came ? Plz tell ?

[@krishchitlangia1394]

how did we evaluated 1/(x-1)power 4 using partial fraction?

[@yashsagar48]

How did you take z/(z-2)
It should be 2/(2-z) ... Z transform of 2^n u(n) ??? In first question.... Please reply

[@rudrastudycircle1572]

Dear Yash, Z transform ofa^n will be z/(z-a)

[@kosuruarunkushwanthjee9744]

Y n + 2 =2Y n+1 +Y n =2^ n with yo=2,y1=1, how it is solve sir...

[@lzyzhenye]

Hi sir, how do this calculate on 5:11
Y(z)((z+1)(z+3))=z/z-2+z
Y(z)=z^2-z/(z-2)(z+1)(z+3)
how the numerator become z^2-z ?

[@MoneAllen]

take lcm of of LHS and multiple the brackets u will get
z+z^2-2z
that is equal to z^2-z now take z as common from the term and it will goes to RHS as Y(z)/z
i hope it will works for u 😀

[@sandipansarkar3717]

Thank you ❤️🔥

[@surajgolthi8480]

Sir what if y(0) n y(1) are not given

[@rudrastudycircle1572]

This method is applicable for initial value problems. If initial conditions are not given [ y(0) and y(1) ], then we can assume some k1 and k2. And then we get ans in terms of k1 and k2.

[@rudrastudycircle1572]

Thank you suraj for watching.
Keep watching !!!

[@dailymotiv8411]

Very well explained sir thank you

[@syedsaquibmustafa6075]

your way of teaching is good but plz improve your pronunciation of 'zero 'and 'z'

[@yashkumarsahu9182]

question 2 m partial fraction kaise kea hai nahi smjh m aaya

[@neekedhukuraa795]

Sir I clarified from all the doubts but I don't get thee.. last step... Plss in the first prblm...🙃

[@rudrastudycircle1572]

Dear Rakesh, you meant inverse Z Transform in the 1st problem

[@ankitbhargava1184]

At 17:05 in the last line how we get 5z²-4z, we should get 5z²-2z

[@rudrastudycircle1572]

yes
Thanks

[@kapilkakar1722]

y(k+2) + 2 y(k+1) + y(k) = k,
y(0) = y(1) = 0
Sir I have problem in this question please u help me.

[@amudhaganesanvenkatapathy9102]

Great work

[@rudrastudycircle1572]

Thank you so much 😀

[@andhamrandram]

Nice video sir

[@pushpakumari8789]

Great

[@rudrastudycircle1572]

Thanks

[@vaibhavagarwal6320]

👌🏻👌🏻

[@shiaksameer751]

Manmadaraja song played well sir

[@Khushi-cq1df]

Who heard “Suntaragaali” song? 16:06
Anyways nice explanations thanks

[@DheerajKumar-yk3yl]

Thanks a lot sir

[@rudrastudycircle1572]

Most welcome

[@PramodKumar-wb8ir]

Great sir...

[@rudrastudycircle1572]

Thanks Pramod

[@zattiya]

Giro d'italia?

[@rudrastudycircle1572]

YES
OF COURSE

[@DMW.I]

17:32

[@rudrastudycircle1572]

??

[@varunmahadik5072]

Improve handwriting please.... Its hard to get what you want to teaching....

[@Ball-Boy005]

Improve spelling please.... It's hard to get what you when you speak bad English

[@ArunKumar-jg8gx]

Lol 😂

[@ketangaming7987]

Improve your English grammer please.... It's hard to get what you want to say..... 🌚

[@ketangaming7987]

to teach✅..... (to teaching) cross❌

[@ritam2795]

​@@ketangaming7987grammar* improve your spelling homie