Introduction to Z-Transform
Вставка
- Опубліковано 10 лют 2025
- Signal & System: Introduction to Z-Transform
Topics discussed:
1. Introduction to Z-transform.
2. The formula of Z-transform.
3. Use of Z-transform.
4. Z-transform pair.
5. Bidirectional and Unidirectional Z-transforms.
6. Example problem to demonstrate the calculation of Z-transform and Region of Convergence (ROC).
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Music:
Axol x Alex Skrindo - You [NCS Release]
#SignalAndSystemByNeso #Signal&System #ZTransform
Watching calmly at 80% volume as the z transform just flows inside my mind....plus your voice feels so relaxing....You helped me a lot in coping my difficulties in signals.
Thanks team Neso
the first channel on youtube which starts from the basics honestly , You are very genius.
Sir, pls upload all the lectures in signals and systems
10. Discrete Fourier transform and Fast Fourier transform
11. Digital filters
12. Discrete cosine transform
Please accept my sincere appreciation and respect
The
@@EricDzisah The
Don't know y my brain works only the day before exam 😥 and remains dumb during the whole semester and in exams 😑
Same feeling
I feel you bro. 😢
Everything is moh maya... Reality is often disappointing bro
What u do now
Same feeling
your style of speaking is op. I am able to watch these video at 3x a day before exam
signals and systems has been an insane class but with the end near, i have to say that these videos are amazing help. thank you
How did the rest of the class go?
@@PunmasterSTP I also wanna know
@@almostmonk5523 I love replying to old comments like this, and I'm pretty sure a few people got back to me after more than 10 years.
@@PunmasterSTP Lol, same I don't know exactly why, maybe it's because I wanna let them know that they left a comment there few years back and someone actually replied. Its like taking other person back to their past, something like that
@@almostmonk5523 Yes, exactly!
This is one of z best videos I’ve ever seen! Thanks for posting all of them.
Thank you very much sir!!! We are so grateful to Saraswati Mata to have such amazing teachers to teach us. The thing I love about you is you take topics from the basics and make it easy for anybody to understand. Thank you very much sir Jai Siya Ram
Thank you for your efforts! Your clarity has saved me.
Thank you sir very nice gide & very nice best explain introduction Z-transform teaching video.👍
Your videos are awesome sir! This helped me in my exams.
Much anticipated video comes to an end
what is u[n]? you should mention that it is a unit step command. the unit step function is defined as: u[n] = 1, n >= 0 u[n] = 0, n < 0.
You are the best teacher
love you my dude
Thank You Sir 🙏✨ your lectures helped me during my exams 🌞
Amazing explanation in short period of time tq⚡️💫
Came here to study z translation but your voice lead me to meditation . 😙
Very thankful to you sir😍
It couldn't be explained more simply than that.
Nice explanation ❤❤
Any beginner wont know what's CTFT and DTFT
Better skip that portion and jump straight to 3:10
thank you brother
Thank you for the information
"You need friction, for it to skid then hop" does kinda seem intuitive to we when phrased like that
i have exams on 15th this month plz upload DTFT before that ,love ya
Sir pls upload the remaining lectures also . We r waiting for the complete syllabus pls
Thanks. This video helps me get lots of things.
I really thank you for your simple explanation
This was really really helpful.... great job NESO !!
ahhhh... Neso is back
tip: play at 2x
you saved me so much time thanks
😂😂
True 🤣
1.25x is better
Thank you so much
please make video on inverse of z-transform your lecture help us alot Thanks Neso Academy
Good explanation but better to watch in 2x
are there any other extra videos on the Z-Transform ? if yes should I be a member to be able to access it? Your prompt response is really apprecaited
Thank you so much.❤️
Thanks for such clear explanation sir
Sir plz upload videos probability random variable subject ur lectures are nice
This lecture has no comparison, The way teacher explained is unpredictable
very well explained...kudos
Very helpful 👌
Wow , thank you so much ,
sir, u are awesome//
Thank you soo much!!
Sir, please hurry up, my final exam is in 3days! BTW your lecture is awesome!
He's not your private teacher, and the guy can take as much time he wants to complete (he's not even obliged to do so) his series.
We have better thanking him for the efforts he has already put in these videos! Thank you Neso!!
Well said. The guy's put in soo much effort into this, yet here we are, ungrateful as ever.
Thank you so very much Neso.
maybe you should come replace my DSP lecturer... this is some good stuff, thanks.
very good teaching sir
sir thank you very much but when u will complete signal and systems
play at 1.5x or 2x
2x it is
Tq Sir🙏❣️
8:30 "lettuce write a power n..."
Love u hro
I'm very late! 😢
Sir will you start dft fft or not or the singanl is completed????
Nice
Sir please complete the course
sir please make video on inverse z_transform quickly
Thanku
why u[n] will start from 0 not -infinity ?
u[n] is unit step signal and is zero for -ve values and 1 for positive values
@@theroast9376 thank you sir!!
Why did he just remove u[n]? Also: What does this mean? What does the z-transform tell us about x[n]?
He removes u(n) when he changes the summation from -inf to 0 Because u(n) is a unit step function, meaning x(n) = 1 for n>=0 and 0 for n less than zero. So, we don’t care about the values before n=0, because they will be 0.
But why ?? |az^-1| = 2 or 3 (>1) is also possible right?? why are we putting |az^-1| < 1 only??
can i ask what app are u using for drawing ?
Complete signals and systems ASAP
Digital signal processing yahi h kya
sir when will u teach dtft and dtfs
Find Z transform and sketch ROC
x(n) = 4 e^j( π/4 n) .u(n)
ANy solution to this?
sir how do you know that common ratio is less than 1 ?
Neso, why dont you at first finish Analog Electronics Lectures, why you are messing the lectures so much by starting new lecture material and not finish the previous started, like Analog El?
DTFT was taught in which video in the playlist?
Why not use the power sum formula?
8:50 e⁰=1
what does (a) indicates in z transform
sir a small query....why we are calculating ROC only for laplace transform and z-transform why nt for other transforms?????....plz let me know sir?????
What i presume is, CTFT is a limited case of Laplace transform, and DTFT is a limited case of Z transform. And by defining ROC for Laplace transform and Z transform, we are defining for a general case than a limited case.
And if you observe the mathematical expressions of LT, you have "s" as independent variable by which we can relate its existence with s- plane and similarly in ZT, "z" as independent variable by which we can relate its existence to z plane, which is not the case with CTFT and DTFT.
@@vavilapallisatyavenkatasan6563 bro.. may i kno what exam u r preparing for? U frm a.p,?
ASMR 🌝
pls complete z transform
Thank you for the clear and well articulated tutorial. At ua-cam.com/video/mJgVOV9jRZU/v-deo.html isn't this supposed to be a broken circle since the inequality is a strict one ? Thanks again.
actually, mod Z > mod A should be written. that way we also consider negative axis values of A of the circle.
❤
Why must az^(-1) < 1?
A property of summation formula when you have r = bla bla for every term.
Time shifted towards negative axis that is -1. So roc is lesser.
9n(3/2)^(n-1) u[n-1]
Please give me the Z transformation solve of this
oi upload DTFT man i am all lost
slowly slowly🤣🤣
Despacito😅
Can't here properly
Bss is to difficult subject
Confusion
Very difficult to listen to.
লাইক করবেন
we will get all the values less than 0 to be 0 because of u(n)
u do know someone will watch this video to understand not to be told things without any explanation into why just a waste of time this was
Okay, so a basic signal like u(n) should be explained completely in the 305th video of this course? It is “told” like this because u(n) is explained and used many times earlier in the course. A student following from the beginning will find no issue.
Why u[n] is 0 at - infinity to 0?
It is a unit step function and unit step function brings this property with itself. It has a step at zero and rises till one at y axis and then stays the same till infinity.